maths.free › Real Analysis › Convergence of series

Convergence of series

Divergence, ratio, comparison and integral tests, and the harmonic series.

An infinite series converges when its partial sums approach a limit. The terms going to zero is necessary but not enough. The harmonic series 1 + ½ + ⅓ + … diverges even though its terms vanish. The ratio test settles most series with factorials or powers; comparison and the integral test handle the p-series family.

Toimiva esimerkki · does 1/n^2 for n = 1 to oo converge

Calculus · Series-And-Sums

Convergence of n^(-2)

\frac{1}{n^{2}}

Askel kerrallaan

  1. \sum_{n=1}^{\infty} \frac{1}{n^{2}}

    Does this series converge?

  2. \lim_{n\to\infty} \frac{1}{n^{2}} = 0

    Divergence test: if the terms do not go to 0 the series cannot converge.

  3. \lim \left|\frac{a_{k+1}}{a_k}\right| = \lim \left|{\frac{n^{2}}{\left(n + 1\right)^{2}}}\right| = 1

    Ratio test: < 1 converges, > 1 diverges, = 1 says nothing.

  4. = \frac{\pi^{2}}{6}

    It converges, and the CAS knows the sum.

Paljasta vastaus
\text{converges to } \frac{\pi^{2}}{6}

Nyt sinä Valitse ongelma tai kirjoita tai piirrä omasi. Jokainen vaihe, kuva ja vastaus piilotettuna, kunnes kysyt.

Pidä oma työsi

Vapaa tili lisää muistiinpanoja jokaiseen oppituntiin, muistiinpanoja siitä, mitä olet saanut päätökseen, ratkaistuja ongelmiasi yhdessä paikassa ja ohjaajaa, jolta voit kysyä tästä sivusta. Matematiikka on kaikille avoin, kirjautunut tai ei.

Rekisteröidy Kirjautuminen

Symbolit, joita käytetään täällä

Napauta symbolia koko määrittelyn, kuvan ja sen jokaisen kirjaimen osalta.

Miten: Convergence of series

  1. Does this series converge?
  2. Divergence test: if the terms do not go to 0 the series cannot converge.
  3. Ratio test: < 1 converges, > 1 diverges, = 1 says nothing.
  4. It converges, and the CAS knows the sum.

Kysymyksiä

What is the ε, δ definition actually saying?

That you can make the output as close to the limit as anyone demands (within ε) by keeping the input close enough (within δ). It replaces "approaches" with a challenge-and-response that can be checked.

Why does the harmonic series diverge when its terms go to zero?

Because the terms shrink too slowly: group them as 1/3 + 1/4 > 1/2, 1/5 + … + 1/8 > 1/2, and so on: infinitely many halves.

Lisää Real Analysis

Sequences and their limitsImproper integralsTaylor approximation and errorFunctions of a complex variableContinuity and differentiability, rigorouslySequences of functions and uniform convergence