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Step by step
- \sum_{n=1}^{\infty} 2^{- n} n
Does this series converge?
- \lim_{n\to\infty} 2^{- n} n = 0
Divergence test: if the terms do not go to 0 the series cannot converge.
- \lim \left|\frac{a_{k+1}}{a_k}\right| = \lim \frac{\left|{\frac{n + 1}{n}}\right|}{2} = \frac{1}{2}
Ratio test: < 1 converges, > 1 diverges, = 1 says nothing.
- = 2
It converges, and the CAS knows the sum.
Reveal the answer
\text{converges to } 2