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Interpolation and Taylor approximation

Fitting polynomials through points, and approximating functions near a centre.

Through n + 1 points passes exactly one polynomial of degree n (Lagrange). Near a point, the Taylor polynomial matches the derivatives. Picture it: the dashed polynomial hugging the curve near the centre and peeling away. Think it: approximation theory asks for the best polynomial over a whole interval, Chebyshev, not Taylor.

କାର୍ଯ୍ୟକାରୀ ଉଦାହରଣ · taylor series of e^x

Calculus · Taylor-Series

Taylor series of e^(x)

e^{x}

ପଦକ୍ଷେପ କ୍ରମେ

  1. f(x) = e^{x}

    Taylor series about x = 0: f(x) = Σ fᵏ(x₀)/k! · (x − x₀)ᵏ.

  2. f^{(0)}(0) = e^{x}\big|_{x=0} = 1

    Derivative 0 at the centre.

  3. f^{(1)}(0) = e^{x}\big|_{x=0} = 1

    Derivative 1 at the centre.

  4. f^{(2)}(0) = e^{x}\big|_{x=0} = 1

    Derivative 2 at the centre.

  5. f^{(3)}(0) = e^{x}\big|_{x=0} = 1

    Derivative 3 at the centre.

  6. f^{(4)}(0) = e^{x}\big|_{x=0} = 1

    Derivative 4 at the centre.

  7. f^{(5)}(0) = e^{x}\big|_{x=0} = 1

    Derivative 5 at the centre.

  8. \frac{x^{5}}{120} + \frac{x^{4}}{24} + \frac{x^{3}}{6} + \frac{x^{2}}{2} + x + 1

    Assemble the terms up to degree 5.

ଉତ୍ତରକୁ ଖୋଲନ୍ତୁ
\frac{x^{5}}{120} + \frac{x^{4}}{24} + \frac{x^{3}}{6} + \frac{x^{2}}{2} + x + 1 + O((x-0)^{6})

ଏବେ ଆପଣ ଗୋଟିଏ ସମସ୍ୟା ବାଛନ୍ତୁ, କିମ୍ବା ଆପଣଙ୍କର ନିଜ ସମସ୍ୟାକୁ ଟାଇପ କରନ୍ତୁ କିମ୍ବା ଆଙ୍କନ୍ତୁ। ପ୍ରତ୍ୟେକ ପର୍ଯ୍ୟାୟରେ, ଗୋଟିଏ ଚିତ୍ର, ଉତ୍ତର ଲୁକ୍କାୟିତ ହୋଇଥାଏ ଯେ ପର୍ଯ୍ୟନ୍ତ ଆପଣ ପଚାରନ୍ତି ନାହିଁ।

ଆପଣଙ୍କର ନିଜ କାର୍ଯ୍ୟକୁ ବଜାୟ ରଖନ୍ତୁ

ଗୋଟିଏ ମୁକ୍ତ ଖାତା ପ୍ରତ୍ୟେକ ପାଠରେ ଟିପ୍ପଣୀ ଯୋଗ କରିଥାଏ, ଆପଣ ଯାହା ସମାପ୍ତ କରିଛନ୍ତି ତାହାର ଗୋଟିଏ ରେକର୍ଡ, ଆପଣଙ୍କର ସମାଧାନ ହୋଇଥିବା ସମସ୍ୟାଗୁଡ଼ିକ ଗୋଟିଏ ସ୍ଥାନରେ, ଏବଂ ଜଣେ ଶିକ୍ଷକ ଆପଣ ଏହି ପୃଷ୍ଠା ବିଷୟରେ ପଚାରିପାରିବେ। ଗଣିତ ନିଜେ ସମସ୍ତଙ୍କୁ ଖୋଲା ଅଛି, ଲଗଇନ ହୋଇଥିବା କିମ୍ବା ନଥିବା।

ସଦସ୍ୟତା ନିଅନ୍ତୁ ଲଗଇନ

ଏଠାରେ ବ୍ୟବହୃତ ପ୍ରତୀକଗୁଡିକ

ସମ୍ପୂର୍ଣ୍ଣ ବର୍ଣ୍ଣନା ପାଇଁ ଯେକୌଣସି ପ୍ରତୀକକୁ ଟ୍ୟାପ କରନ୍ତୁ, ଗୋଟିଏ ଚିତ୍ର, ଏବଂ ଏଥିରେ ଥିବା ପ୍ରତ୍ୟେକ ଅକ୍ଷରର ଅର୍ଥ କଣ।

କିପରି: Interpolation and Taylor approximation

  1. Taylor series about x = 0: f(x) = Σ fᵏ(x₀)/k! · (x − x₀)ᵏ.
  2. Derivative 0 at the centre.
  3. Derivative 1 at the centre.
  4. Derivative 2 at the centre.
  5. Derivative 3 at the centre.
  6. Derivative 4 at the centre.
  7. Derivative 5 at the centre.
  8. Assemble the terms up to degree 5.

ଲୋକମାନେ ପଚାରୁଥିବା ପ୍ରଶ୍ନ

Why not just solve exactly?

Most equations have no closed-form solution at all, and many that do are unusable in practice. A numerical method delivers as many correct digits as you need, and a good one tells you how many that is.

Why can Newton's method fail?

If it starts where the tangent is nearly flat it shoots far away; near a repeated root it slows to a crawl; and with several roots it may land on the wrong one. A bracketing method like bisection is slower but cannot fail.

ଅଧିକ Numerical Methods

Root finding: bisection and Newton's methodNumerical integration: trapezoid and SimpsonFloating point and error