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Planes in Space
This section expects students to have familiarity with the notation and operations of vectors from .
Planes in Space
This section expects students to have familiarity with the notation and operations of vectors from . We also would like to point to our earlier description of flat objects in space to motivate the difference between lines and planes as our flat objects. The examples and activities in this section are selected to highlight the broad range of ways that information about a plane can be given, including talking about parallel planes, the interaction between equations of planes and lines, and the angle between planes.
This section can be covered in a longer class period alongside Planes. Many exercises in this section include taking information from planes to get information about a related line and vice versa, so you may want to select work from the sections on lines and planes together.
Introduction
In , we saw how to describe a line in \(\R^n\) by setting an initial point and allowing unrestricted movement in a direction given by a direction vector. In this section's Preview Activity, we will be looking at what happens when we allow only movement that is perpendicular to a given direction. Since we will specify the given direction by a vector, we will find the perpendicular directions using orthogonal vectors.
Exploration
We will consider what happens when we allow movement in \(\R^3\) with the restriction that the movement must be orthogonal to \(\vv=\langle 1,2,3 \rangle\).
Find values for \(a_0\) and \(b_0\) such that \(\langle 0,a_0,b_0 \rangle\) is orthogonal to \(\langle 1,2,3\rangle\).
Find values for \(c_0\) and \(d_0\) such that \(\langle c_0,d_0,0 \rangle\) is orthogonal to \(\langle 1,2,3\rangle\).
Find values for \(c_1\) and \(d_1\) such that \(\langle c_1,d_1,1 \rangle\) is orthogonal to \(\langle 1,2,3\rangle\).
Find two other values for each of \(c\) and \(d\) such that \(\langle c,d,1 \rangle\) is orthogonal to \(\langle 1,2,3\rangle\).
Verify that each of the following vectors is also orthogonal to \(\langle 1,2,3 \rangle\).
- \(\langle -2,-2,2 \rangle\)
- \(\langle c_0,a_0+d_0,b_0 \rangle\)
- \(\langle -2c_1,a_0-2d_1,b_0-2 \rangle\)
Put all of the vectors you have computed into the interactive below to visually verify that each of them is orthogonal to \(\langle 1,2,3 \rangle\). You should put the component values of each vector into this array with each vector corresponding to a row. If you do not have eight distinct vectors from the previous parts, multiply one of your repeated vectors by \(-1\) and enter that instead of entering a vector multiple times.
Describe what you think the plot of the set of vectors that are orthogonal to \(\langle 1,2,3 \rangle\) will look like.
Planes in Space
Now that we have a way of describing lines, we would like to develop a means of describing planes in three dimensions. In Section, we studied the coordinate planes and planes parallel to them. In particular, \(x=1\), \(y=-2\), and \(z=\sqrt{3}\) are examples of fundamental planes. In general, the equations of fundamental planes have the form \(coordinate = constant\).
As shown in , any vector in a plane with \(x= \text{constant}\) will be orthogonal to the vector \(\langle 1,0,0 \rangle\), any vector in a plane with \(y= \text{constant}\) will be orthogonal to the vector \(\langle 0,1,0 \rangle\), and any vector in a plane with \(z= \text{constant}\) will be orthogonal to the vector \(\langle 0,0,1 \rangle\). We will use this idea to define a plane in general.
Like the definition of a line, the definition of a plane given above uses a starting point and a vector as the critical pieces of information. For a line, you begin at the starting point and move as much as you want parallel to the given vector (the direction vector). For a plane, you begin at the starting point and move as much as you want orthogonal to the given vector (the normal vector). For a line, you move only in the direction of the given vector whereas on a plane you cannot move at all in the direction of the given vector.
This description of a plane allows us to find the equation of a plane. Assume that \(\vn=\langle a,b,c\rangle\), \(P_0 = (x_0, y_0, z_0)\), and that \(Q=(x,y,z)\) is an arbitrary point on the plane. Since the vector \(\overrightarrow{P_0 Q}\) lies in the plane, it must be perpendicular to \(\vn\). This means that \[\begin{aligned}0 =\mathstrut \amp \vn\cdot\overrightarrow{P_0 Q} \\ =\mathstrut \amp \vn\cdot \big(\langle x,y,z \rangle - \langle x_0, y_0, z_0\rangle\big) \\ =\mathstrut \amp \vn \cdot \langle x-x_0, y-y_0, z-z_0 \rangle \\ =\mathstrut \amp a(x-x_0) + b(y-y_0) + c(z-z_0).\end{aligned}\]
We may now summarize our new equation for a plane.
The scalar equation of the plane with normal vector \(\vn =\langle a,b,c \rangle\) containing the point \(P_0 = (x_0, y_0, z_0)\) is \[\begin{aligned}\end{aligned}\].
The vector equation of the plane with normal vector \(\vn =\langle a,b,c \rangle\) containing the points \(P_0 = (x_0, y_0, z_0)\) and \(Q = (x,y,z)\) is \[\begin{aligned}\end{aligned}\].
Condensed: the full section is in Boelkins et al., Active Calculus Multivariable.
Ҳоло шумо Ҳеҷ ҳисобкунак инро ҳал намекунад, лекин қисмҳои он ҳисобшавандаанд. Яке аз инҳоро дар поён санҷед ё худи худро ворид кунед.
Машқ (1)
Ҳар як саволро аввал дар коғаз санҷед. Ҷавобро барои санҷиш нишон диҳед; ҷавобҳои санҷидашударо дар ҳалкунанда барои ҳар қадам кушода метавонед.
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Find an equation for the plane that contains both of the lines described in .
Ҷавоби ҷавобро нишон диҳед
Find the normal vector to the two direction vectors. \(\vu \times \vv = ((1)(5) - (3)(1))\vi - ((-2)(5) - (3)(-2))\vj + ((-2)(1) - (-2)(1))\vk = \langle 2, 4, 0 \rangle\). Use either \((4, -2, 1)\) or \((-4, 2, 17)\) and \(\langle 2, 4, 0 \rangle\) to write the scalar equation of the plane \(2(x + 4) + 4(y - 2) + 0(z - 17) = 2(x + 4) + 4(y - 2) = 0\) or \(2(x - 4) + 4(y + 2) + 0(z - 1) = 2(x - 4) + 4(y + 2) = 0\)
Дар ҳисоби ройгон ба ҳар як дарс қайдҳо илова карда мешаванд, қайди он, ки шумо чӣ кор кардаед, масъалаҳои ҳалшуда дар як ҷо ва муаллиме, ки шумо метавонед дар бораи ин саҳифа пурсед. Математика барои ҳама кушода аст, хоҳ ворид шуда бошад ё на.
Бақайдгирӣ Ворид шуданСимволы, используемые здесь
Барои муайянкунии пурраи маъно, тасвир ва маънои ҳар як ҳарф дар он, ба ҳар як аломат пахш кунед.
Чӣ тавр: Planes in Space
- How is a plane defined in terms of measurements of points and vectors?
- What different ways are there to determine a plane through geometric information?
Саволҳои маъмул
What is a partial derivative?
The ordinary derivative with respect to one variable while every other variable is frozen: the slope of the surface in one coordinate direction.
What does the gradient point at?
Uphill: the direction of steepest increase, with length equal to that steepest slope. It is perpendicular to the level curves.
Қисми ин саҳифа аз Boelkins et al., Active Calculus Multivariable (CC BY-SA 4.0). Дар ин ҷо барои мо чизе нест, ки мо ба он бирасем.
& Иловаи забон Multivariable Calculus
Functions of several variablesPartial derivatives and the gradientOptimisation in several variablesDouble and triple integralsVector fields, line integrals and the big theorems