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σ-algebras and measures

Which sets can be measured, and the countable additivity that makes limits work.

A σ-algebra is a family of sets closed under complements and countable unions; a measure assigns sizes additively over countable disjoint unions. Lebesgue measure gives intervals their length and extends to far stranger sets. Picture it: covering a set by intervals and taking the cheapest total length. Think it: not every set is measurable (Vitali), which is why the σ-algebra is part of the definition.

Ишлатилган мисол · integrate 1/10 dx from 2 to 5

Integrate 1/10 from 2 to 5

\int_{2}^{5} \frac{1}{10}\, dx

Қадамма-қадам

  1. \int_{2}^{5} \frac{1}{10}\, dx

    First find an antiderivative F, then evaluate F(b) − F(a).

  2. \int \frac{1}{10}\, dx = \frac{x}{10}

    The integral of a constant c is c·x.

  3. F(5) - F(2) = \left(\frac{1}{2}\right) - \left(\frac{1}{5}\right)

    Fundamental theorem of calculus: plug in the limits.

  4. = \frac{3}{10}

    Simplify.

Жавобни кўрсатиш
\frac{3}{10}

Энди сизлар Мавзуни танланг, ёзинг ёки ўзингиз чизинг. Ҳар бир қадам, расм, жавоб сиз сўрагунча яширин.

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Ройхатдан ўтиш Кириш

Бу ерда қўлланилган белгилар

Барча белгилар учун тўлиқ таъриф, сурат ва ҳар бир ҳарфнинг маъносини кўриш учун белгини босинг.

Қандай: σ-algebras and measures

  1. First find an antiderivative F, then evaluate F(b) − F(a).
  2. The integral of a constant c is c·x.
  3. Fundamental theorem of calculus: plug in the limits.
  4. Simplify.

Одамлар сўрайдиган саволлар

What is wrong with the Riemann integral?

It fails on functions that oscillate too much, and it does not interact well with limits: the limit of integrable functions need not be integrable. Lebesgue's integral fixes both.

Кўпроқ Measure Theory