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σ-algebras and measures
Which sets can be measured, and the countable additivity that makes limits work.
A σ-algebra is a family of sets closed under complements and countable unions; a measure assigns sizes additively over countable disjoint unions. Lebesgue measure gives intervals their length and extends to far stranger sets. Picture it: covering a set by intervals and taking the cheapest total length. Think it: not every set is measurable (Vitali), which is why the σ-algebra is part of the definition.
Töötatud näide · integrate 1/10 dx from 2 to 5
Samm-sammult
- \int_{2}^{5} \frac{1}{10}\, dx
First find an antiderivative F, then evaluate F(b) − F(a).
- \int \frac{1}{10}\, dx = \frac{x}{10}
The integral of a constant c is c·x.
- F(5) - F(2) = \left(\frac{1}{2}\right) - \left(\frac{1}{5}\right)
Fundamental theorem of calculus: plug in the limits.
- = \frac{3}{10}
Simplify.
Vastuse avalikustamine
Nüüd sina. Vali probleem, või kirjuta või joonista oma. Iga samm, pilt, vastus peidetud, kuni küsid.
Tasuta konto lisab märkmeid igale õppetunnile, ülestähenduse, oma lahendatud probleemide kohta ühes kohas ja juhendaja kohta, kellelt võid küsida selle lehekülje kohta. Matemaatika ise on avatud kõigile, allkirjastatud või mitte.
Registreeru SisselogimineSiin kasutatavad sümbolid
Koputage kõiki sümboleid, mis on mõeldud täieliku definitsiooni, pildi ja iga tähe all.
Kuidas: σ-algebras and measures
- First find an antiderivative F, then evaluate F(b) − F(a).
- The integral of a constant c is c·x.
- Fundamental theorem of calculus: plug in the limits.
- Simplify.
Küsimusi, mida inimesed küsivad
What is wrong with the Riemann integral?
It fails on functions that oscillate too much, and it does not interact well with limits: the limit of integrable functions need not be integrable. Lebesgue's integral fixes both.