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Kinematics: streamlines, pathlines and streaklines

Three different curves drawn by a flow, why they coincide for steady flow, and how to compute each.

A velocity field can be drawn in three ways, and they answer three different questions. A streamline is a curve tangent to \(\mathbf{u}\) at one frozen instant: along it \(d\mathbf{x}\) is parallel to \(\mathbf{u}\), so in two dimensions \[ \frac{dy}{dx} = \frac{v(x,y,t)}{u(x,y,t)}, \qquad t \text{ fixed}. \] A pathline is the actual trajectory of one particle, the solution of \(d\mathbf{X}/dt = \mathbf{u}(\mathbf{X},t)\). A streakline is what you see when dye is released continuously from a fixed point \(\mathbf{x}_0\): at time \(t\) it is the set of positions of all particles that passed through \(\mathbf{x}_0\) at earlier times \(s \le t\).

For a steady flow the three coincide: the field never changes, so a particle simply runs along a streamline and every later particle from the same point follows it. For an unsteady flow they differ, and the difference is easy to compute. Take \(\mathbf{u} = (1, t)\). At time \(t\) the streamlines are straight lines of slope \(t\). The particle that starts at the origin has \(X = t\), \(Y = t^2/2\), so its pathline is the parabola \(y = x^2/2\). A particle released from the origin at time \(s\) is at \(X = t-s\), \(Y = (t^2-s^2)/2\) at time \(t\); eliminating \(s\) gives the streakline \(y = tx - x^2/2\) for \(0 \le x \le t\). Three different curves from one field.

Streamlines of the steady rotation \(\mathbf{u} = (y,-x)\) satisfy \(dy/dx = -x/y\), a separable equation whose solutions are the circles \(x^2+y^2 = C\). Streamlines of the strain \(\mathbf{u} = (x,-y)\) satisfy \(dy/dx = -y/x\), giving the hyperbolas \(xy = C\). A bundle of streamlines through a small closed curve forms a stream tube; no fluid crosses its wall, because the velocity is tangent to it.

Points where \(\mathbf{u} = 0\) are stagnation points, and near one the flow looks like its linearisation \(\mathbf{u} \approx (\nabla\mathbf{u})\,\mathbf{x}\). The eigenvalues of the velocity gradient classify the picture: real of opposite signs gives a saddle (the strain \((x,-y)\) has eigenvalues \(1\) and \(-1\)), purely imaginary gives a centre (the rotation).

Picture it: iron filings on a sheet show streamlines; a long-exposure photograph of one lit particle shows a pathline; smoke from a chimney on a gusty day shows a streakline. Think it: streamlines are integral curves of a time-dependent vector field at a frozen time, pathlines are integral curves in space-time, and streaklines are images of a curve of release times under the flow map. Only the pathline is a solution of an ODE in time.

Rechenbeispiel · y' = -x/y

Y' = -x/y

\frac{d}{d x} y{\left(x \right)} = - \frac{x}{y{\left(x \right)}}

Schritt für Schritt

  1. \frac{d}{d x} y{\left(x \right)} = - \frac{x}{y{\left(x \right)}}

    The differential equation.

  2. \text{order } 1

    Order 1: the highest derivative present.

  3. \text{Separable}

    Move everything in y to one side with dy and everything in x to the other, then integrate both sides.

  4. y{\left(x \right)} = - \sqrt{C_{1} - x^{2}}

    General solution (C₁, C₂ … are arbitrary constants).

  5. \checkmark

    Verified: substituting the solution back into the equation gives 0.

Antwort aufdecken
y{\left(x \right)} = - \sqrt{C_{1} - x^{2}}

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Wie man: Kinematics: streamlines, pathlines and streaklines

  1. Decide which curve is asked for: frozen-time tangent (streamline), a particle trajectory (pathline) or a dye trace (streakline).
  2. Streamline: solve dy/dx = v/u with t held as a constant.
  3. Pathline: solve dX/dt = u(X, t), dY/dt = v(X, t) with the starting point as initial condition.
  4. Streakline: solve the pathline starting from x0 at a general release time s, then eliminate s at the observation time t.

Fragen, die die Leute stellen

Can two streamlines cross?

Only where the velocity is zero or undefined. Elsewhere the velocity has one direction, so there is one tangent line through each point.

Which one does a wind tunnel smoke visualisation show?

A streakline, because smoke is released continuously from a fixed nozzle. In a steady tunnel flow that is also the streamline.

What do I need before starting fluid dynamics?

Multivariable calculus (divergence, curl, the divergence and Stokes theorems), linear algebra (symmetric matrices and eigenvalues) and partial differential equations (the heat and Laplace equations). The last lessons also use Sobolev spaces, which are introduced where they are needed.

What are the Navier-Stokes equations in one sentence?

Newton's second law for each particle of a viscous incompressible fluid: acceleration equals the pressure force plus viscous diffusion of momentum, with the constraint that the velocity field is divergence-free.

Why is two-dimensional flow easier than three-dimensional flow?

In 2D the vorticity is a scalar that is only carried and diffused, so its maximum never grows; in 3D vortex lines can be stretched, which amplifies vorticity, and no known bound rules out unlimited growth.

Is this course physics or mathematics?

Both, in order. The first half derives the equations from physical principles and solves classical flows; the second half treats the equations as mathematical objects and studies which of their properties can be proved.

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