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Viscosity, Newtonian fluids and the Navier-Stokes equations

The constitutive law for viscous stress and the derivation, term by term, of the incompressible Navier-Stokes equations.

Viscosity is internal friction: layers of fluid sliding past each other exchange momentum. The viscous stress \(\tau\) must vanish when the fluid moves rigidly, so it cannot depend on the velocity itself (a uniform translation) or on the antisymmetric part \(W\) of the velocity gradient (a rigid rotation). It can depend on the rate of strain \(S = \tfrac12(\nabla\mathbf{u} + \nabla\mathbf{u}^T)\). A Newtonian fluid is one in which the dependence is linear and the same in every direction. The most general such law is \[ \tau = 2\mu S + \lambda(\nabla\cdot\mathbf{u})\,I, \] and in incompressible flow the second term vanishes, leaving \(\tau = 2\mu S\), \(\tau_{ij} = \mu(\partial_j u_i + \partial_i u_j)\). The constant \(\mu\) is the dynamic viscosity. Water, air and oil are Newtonian to high accuracy; blood, paint and toothpaste are not.

Insert \(\sigma = -pI + 2\mu S\) into Cauchy's equation. The divergence of the viscous stress is \[ \partial_j\bigl(\mu(\partial_j u_i + \partial_i u_j)\bigr) = \mu\,\Delta u_i + \mu\,\partial_i(\nabla\cdot\mathbf{u}) = \mu\,\Delta u_i, \] using equality of mixed partial derivatives and incompressibility. Dividing by the constant density and writing \(\nu = \mu/\rho\), the kinematic viscosity, gives the incompressible Navier-Stokes equations: \[ \frac{\partial\mathbf{u}}{\partial t} + (\mathbf{u}\cdot\nabla)\mathbf{u} = -\nabla p + \nu\Delta\mathbf{u} + \mathbf{f}, \qquad \nabla\cdot\mathbf{u} = 0, \] where \(p\) now denotes pressure divided by density. For water at 20 °C, \(\nu \approx 1.0\times10^{-6}\) m²/s; for air, \(\nu \approx 1.5\times10^{-5}\) m²/s.

Read each term as a statement about a fluid particle. \(\partial_t\mathbf{u} + (\mathbf{u}\cdot\nabla)\mathbf{u}\) is its acceleration: local change plus the nonlinear advection. \(-\nabla p\) pushes it from high pressure to low. \(\nu\Delta\mathbf{u}\) is diffusion of momentum: a particle moving faster than the average of its neighbours is slowed down, exactly as the heat equation smooths temperature. \(\mathbf{f}\) is any external force per unit mass. The constraint \(\nabla\cdot\mathbf{u} = 0\) has no time derivative in it; the pressure is whatever it must be to keep it true, and taking the divergence gives \(-\Delta p = \partial_i u_j\,\partial_j u_i - \nabla\cdot\mathbf{f}\).

Viscosity also changes the boundary condition. At a solid wall a viscous fluid does not slip: \(\mathbf{u}\) equals the wall's velocity. This is an experimental fact, and it raises the order of the equations enough to impose it. The equations carry several names because they were found several times: Navier (1822) from a molecular model, Cauchy and Poisson in the 1820s and 1831, Saint-Venant (1843), and Stokes (1845), whose continuum derivation is the one given here.

The mathematical questions this course builds towards are posed for the equations on all of \(\mathbb{R}^3\), with velocity decaying at infinity, or on the periodic box \(\mathbb{T}^3 = \mathbb{R}^3/(2\pi\mathbb{Z})^3\): given a smooth divergence-free initial velocity \(\mathbf{u}_0\), find \(\mathbf{u}\) and \(p\) for \(t \gt 0\). The periodic case removes boundaries and infinity and keeps only the equations.

Picture it: a deck of cards pushed along the top card; each card drags the one below by friction, and the drag is proportional to how fast neighbouring cards slide past each other. That is \(\tau = \mu\,du/dy\) in one line. Think it: Navier-Stokes is the Euler equations plus a Laplacian: a nonlinear transport equation coupled to a heat equation and a divergence constraint. The Laplacian smooths; the nonlinearity can steepen; which wins is the central question.

Przykład pracownika · laplacian of sin(x)*sin(y)

Laplacian of sin(x)*sin(y)

\nabla^2\left(\sin{\left(x \right)} \sin{\left(y \right)}\right)

Krok po kroku

  1. f(x, y) = \sin{\left(x \right)} \sin{\left(y \right)},\quad \nabla^2 f = \frac{\partial^2 f}{\partial x^2} + \frac{\partial^2 f}{\partial y^2}

    The Laplacian adds the second partial derivative in each direction.

  2. \frac{\partial f}{\partial x} = \sin{\left(y \right)} \cos{\left(x \right)},\quad \frac{\partial^2 f}{\partial x^2} = - \sin{\left(x \right)} \sin{\left(y \right)}

    Differentiate twice with respect to x, holding the other variables constant.

  3. \frac{\partial f}{\partial y} = \sin{\left(x \right)} \cos{\left(y \right)},\quad \frac{\partial^2 f}{\partial y^2} = - \sin{\left(x \right)} \sin{\left(y \right)}

    Differentiate twice with respect to y, holding the other variables constant.

  4. \nabla^2 f = \left(- \sin{\left(x \right)} \sin{\left(y \right)}\right) + \left(- \sin{\left(x \right)} \sin{\left(y \right)}\right) = - 2 \sin{\left(x \right)} \sin{\left(y \right)}

    Add the second partials.

Odkryj odpowiedź
\nabla^2 f = - 2 \sin{\left(x \right)} \sin{\left(y \right)}

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Jak to zrobić?: Viscosity, Newtonian fluids and the Navier-Stokes equations

  1. Start from Cauchy's equation rho Du/Dt = div(sigma) + rho f.
  2. Insert sigma = -p I + 2 mu S with S the symmetric part of grad u.
  3. Take the divergence of 2 mu S, use div u = 0 to reduce it to mu times the Laplacian of u.
  4. Divide by rho, name nu = mu/rho, and add the constraint div u = 0 and the no-slip boundary condition.

Pytania, które ludzie zadają

Why does rotation produce no viscous stress?

In a rigid rotation neighbouring particles do not slide past each other, so there is no friction between them. Mathematically, rotation lives in the antisymmetric part W of the velocity gradient, which the stress does not see.

What is the difference between mu and nu?

mu (dynamic viscosity) measures stress per unit strain rate. nu = mu/rho (kinematic viscosity) is a diffusivity, in square metres per second, and says how fast momentum spreads. Air has a smaller mu than water but a larger nu.

What do I need before starting fluid dynamics?

Multivariable calculus (divergence, curl, the divergence and Stokes theorems), linear algebra (symmetric matrices and eigenvalues) and partial differential equations (the heat and Laplace equations). The last lessons also use Sobolev spaces, which are introduced where they are needed.

What are the Navier-Stokes equations in one sentence?

Newton's second law for each particle of a viscous incompressible fluid: acceleration equals the pressure force plus viscous diffusion of momentum, with the constraint that the velocity field is divergence-free.

Why is two-dimensional flow easier than three-dimensional flow?

In 2D the vorticity is a scalar that is only carried and diffused, so its maximum never grows; in 3D vortex lines can be stretched, which amplifies vorticity, and no known bound rules out unlimited growth.

Is this course physics or mathematics?

Both, in order. The first half derives the equations from physical principles and solves classical flows; the second half treats the equations as mathematical objects and studies which of their properties can be proved.

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