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Holomorphic functions and the Cauchy-Riemann equations

What complex differentiability demands, and why it is so restrictive.

f = u + iv is holomorphic when u_x = v_y and u_y = −v_x. Then u and v are harmonic and f is infinitely differentiable. Picture it: z² = (x² − y²) + i(2xy): the level curves of the real and imaginary parts cross at right angles. Think it: the derivative at a point is a rotation-and-scaling, so holomorphic maps preserve angles (conformal).

Намунаи коркардашуда · derivative of x^2 - y^2 wrt x

Calculus · Derivatives

Differentiate x^2 - y^2

\frac{d}{dx}\left[x^{2} - y^{2}\right]

Қадами ба қадам

  1. \frac{d}{dx}\left[x^{2} - y^{2}\right]

    Start from the derivative to compute.

  2. \frac{d}{d x} x^{2} + \frac{d}{d x} \left(- y^{2}\right)

    Sum rule: differentiate term by term.

  3. 2 x + \frac{d}{d x} \left(- y^{2}\right)

    Power rule: (xⁿ)′ = n·xⁿ⁻¹ with n = 2.

  4. 2 x

    The derivative of a constant is 0.

Ҷавоби ҷавобро нишон диҳед
f'(x) = 2 x

Ҳоло шумо Масъаларо интихоб кунед, ё ки онро навишта ё кашед. Ҳар қадам, тасвир, ҷавоб то он даме, ки шумо пурсед, пинҳон мешавад.

Кор кардан

Дар ҳисоби ройгон ба ҳар як дарс қайдҳо илова карда мешаванд, қайди он, ки шумо чӣ кор кардаед, масъалаҳои ҳалшуда дар як ҷо ва муаллиме, ки шумо метавонед дар бораи ин саҳифа пурсед. Математика барои ҳама кушода аст, хоҳ ворид шуда бошад ё на.

Бақайдгирӣ Ворид шудан

Символы, используемые здесь

Барои муайянкунии пурраи маъно, тасвир ва маънои ҳар як ҳарф дар он, ба ҳар як аломат пахш кунед.

Чӣ тавр: Holomorphic functions and the Cauchy-Riemann equations

  1. Start from the derivative to compute.
  2. Sum rule: differentiate term by term.
  3. Power rule: (xⁿ)′ = n·xⁿ⁻¹ with n = 2.
  4. The derivative of a constant is 0.

Саволҳои маъмул

Why is complex differentiability so much stronger than real?

The limit must be the same from every direction in the plane, not just two. That forces the Cauchy-Riemann equations, which in turn force infinitely many derivatives and a convergent Taylor series.

What is a residue?

The coefficient of 1/(z − a) in the Laurent series at a singularity a. The residue theorem says a contour integral equals 2πi times the sum of the residues inside, which evaluates many real integrals in one line.

& Иловаи забон Complex Analysis

The complex plane and Euler's formulaContour integrals and the residue theoremPower series and analytic continuation