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The complex plane and Euler's formula
z = x + iy as a point, modulus and argument, e^{iθ} = cos θ + i sin θ.
Complex numbers are points in the plane; multiplication rotates and scales. Euler's formula makes rotation an exponential, so e^{iπ} = −1. Picture it: polar form of 1 + i, the point at distance √2 and angle 45°. Think it: the exponential map wraps the imaginary axis around the unit circle; that periodicity is why the complex logarithm has branches.
Ишлатилган мисол · e^(i*pi)
Қадамма-қадам
- e^{i \pi} = -1
Power: E^(I·π) = -1.
Жавобни кўрсатиш
Энди сизлар Мавзуни танланг, ёзинг ёки ўзингиз чизинг. Ҳар бир қадам, расм, жавоб сиз сўрагунча яширин.
Бепул ҳисоб ҳар бир дарсга ёзув қўшиб беради, сиз тугатган нарсалар ва ҳал қилинган масалалар бир жойда қайд этилади ва сиз бу саҳифа ҳақида устоздан сўрашингиз мумкин. Математика ўзида очиқ бўлиб, унга кириш ёки киришни истамаган ҳар кимга очиқ.
Ройхатдан ўтиш КиришБу ерда қўлланилган белгилар
Барча белгилар учун тўлиқ таъриф, сурат ва ҳар бир ҳарфнинг маъносини кўриш учун белгини босинг.
Қандай: The complex plane and Euler's formula
- Power: E^(I·π) = -1.
Одамлар сўрайдиган саволлар
Why is complex differentiability so much stronger than real?
The limit must be the same from every direction in the plane, not just two. That forces the Cauchy-Riemann equations, which in turn force infinitely many derivatives and a convergent Taylor series.
What is a residue?
The coefficient of 1/(z − a) in the Laurent series at a singularity a. The residue theorem says a contour integral equals 2πi times the sum of the residues inside, which evaluates many real integrals in one line.
Кўпроқ Complex Analysis
Holomorphic functions and the Cauchy-Riemann equationsContour integrals and the residue theoremPower series and analytic continuation