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Polar form of 1 + I

1 + i

Step by step

  1. z = 1 + i = 1 + (1)i

    Read off the real and imaginary parts.

  2. |z| = \sqrt{1^2 + 1^2} = \sqrt{2} \approx 1.4142

    The modulus is the distance from the origin (Pythagoras).

  3. \theta = \arg z = \frac{\pi}{4} \approx 0.78540

    The argument is the angle from the positive real axis (watch the quadrant).

  4. z = \sqrt{2}\left(\cos \frac{\pi}{4} + i\sin \frac{\pi}{4}\right) = \sqrt{2} e^{i \frac{\pi}{4}}

    Polar and exponential forms (Euler).

Reveal the answer
\sqrt{2} e^{i \frac{\pi}{4}}