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Binomial Coefficients Revisited

The binomial coefficient \binom{n}{k} was originally defined in terms of the factorial notation, and with our recursive definitions of the factorial notation, we also have a complete and legally-correct definition of…

Binomial Coefficients Revisited

The binomial coefficient \(\binom{n}{k}\) was originally defined in terms of the factorial notation, and with our recursive definitions of the factorial notation, we also have a complete and legally-correct definition of binomial coefficients. The following recursive formula provides an efficient computational scheme.

Let \(n\) and \(k\) be integers with \(0\le k\le n\). If \(k=0\) or \(k=n\), set \(\binom{n}{k}=1\). If \(0\lt k\lt n\), set \[\begin{aligned}\end{aligned}\] This recursion has a natural combinatorial interpretation. Both sides count the number of \(k\)-element subsets of \(\{1,2,\dots,n\}\), with the right-hand side first grouping them into those which contain the element\(n\) and then those which don't. The traditional form of displaying this recursion is This pattern is called Pascal's triangle. Other than the \(1\)s at the ends of each row, an entry of the triangle is determined by adding the entry to the left and the entry to the right in the row above.

Xing was intrigued by the fact that he now had two fundamentally different ways to calculate binomial coefficients. One way is to write \(\binom{n}{m}=P(n,m)/m!\) and just carry out the specified arithmetic. The second way is to use the recursion of Pascal's triangle, so that you are just performing additions. So he experimented by writing a computer program to calculate binomial coefficients, using a library that treats big integers as strings. Which of the two ways do you think proved to be faster when \(n\) say was between \(1800\) and \(2000\) and \(m\) was around \(800\)?

Dabar tu Joks skaičiuotuvas nenusistato, bet jo dalys yra skaičiuojamos. Pabandykite vieną žemiau arba įveskite savo.

Praktika (1)

Išbandykite kiekvieną ant popieriaus pirmą. Atskleisti atsakymą patikrinti; patikrintas tie gali būti atidarytas sprendėjas už kiekvieną žingsnį.

  1. Write a couple of sentences to explain why \(C(n-1,k-1)\) counts the number of \(k\)-element subsets of \(\{1,2,\dots,n\}\) that contain the element \(n\).

Išlaikyti savo darbą

Nemokama paskyra prideda pastabas apie kiekvieną pamoką, įrašą apie tai, ką baigėte, savo išspręstas problemas vienoje vietoje ir mokytoją, kurį galite paklausti apie šį puslapį. Pati matematika yra atvira visiems, kurie yra ar nėra užsiregistravę.

Prisijungti Prisijungti

Čia naudojami simboliai

Bakstelėkite visus simbolius, kad būtų galima apibrėžti visą apibrėžimą, paveikslėlį ir ką reiškia kiekviena raidė.

Klausimai, kuriuos klausia žmonės

Permutation or combination?

Ask whether order matters. A lock code is a permutation (order matters); a hand of cards is a combination (it does not).

What is a graph in this sense?

Dots (vertices) joined by lines (edges), not a plot. Road maps, social networks and molecules are graphs; questions like "is there a route" and "how few colours" are graph theory.

Šio puslapio dalys pritaikytos nuo Keller & Trotter, Applied Combinatorics (CC BY-SA 4.0). Čia yra įtikinamų ir iš naujo paaiškintų klaidų.

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