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Integrals
Antiderivatives by substitution, parts and partial fractions.
Integration undoes differentiation. The solver shows which technique it uses (the power rule, a u-substitution, integration by parts, partial fractions) and the graph plots the antiderivative F against the integrand f, so you can see that F's slope is f.
Ишлатилган мисол · integral of x*e^x dx
Қадамма-қадам
- \int x e^{x}\, dx
Find an antiderivative.
- u = x,\quad dv = e^{x}\, dx
Integration by parts: ∫u dv = uv − ∫v du.
- du = 1\, dx,\quad v = e^{x}
Differentiate u, integrate dv.
- \int x e^{x}\, dx = x e^{x} - \int e^{x}\, dx
Apply the formula.
- \int e^{x}\, dx = e^{x}
∫ aᵘ du = aᵘ / ln a (for eˣ that is just eˣ).
- = x e^{x} - e^{x}
Combine.
- F(x) = \left(x - 1\right) e^{x} + C
Add the constant of integration.
Жавобни кўрсатиш
Энди сизлар Мавзуни танланг, ёзинг ёки ўзингиз чизинг. Ҳар бир қадам, расм, жавоб сиз сўрагунча яширин.
Бепул ҳисоб ҳар бир дарсга ёзув қўшиб беради, сиз тугатган нарсалар ва ҳал қилинган масалалар бир жойда қайд этилади ва сиз бу саҳифа ҳақида устоздан сўрашингиз мумкин. Математика ўзида очиқ бўлиб, унга кириш ёки киришни истамаган ҳар кимга очиқ.
Ройхатдан ўтиш КиришБу ерда қўлланилган белгилар
Барча белгилар учун тўлиқ таъриф, сурат ва ҳар бир ҳарфнинг маъносини кўриш учун белгини босинг.
Қандай: Integrals
- Find an antiderivative.
- Integration by parts: ∫u dv = uv − ∫v du.
- Differentiate u, integrate dv.
- Apply the formula.
- ∫ aᵘ du = aᵘ / ln a (for eˣ that is just eˣ).
- Combine.
- Add the constant of integration.
Одамлар сўрайдиган саволлар
What is a derivative in one sentence?
The slope of the graph at a point, the rate at which the output is changing there. Speed is the derivative of position.
What is an integral in one sentence?
The accumulated total of a rate: the area under the curve. Distance travelled is the integral of speed.
Why are derivatives and integrals opposites?
That is the fundamental theorem of calculus: accumulating a rate and then measuring how fast the accumulation grows gets you back the rate. Integration undoes differentiation up to a constant.
When do I use substitution and when integration by parts?
Substitution when part of the integrand is the derivative of another part (u and du both present). Parts when the integrand is a product of two unrelated kinds of function, a polynomial times an exponential, log or trig function.
Кўпроқ Calculus
LimitsDerivativesDefinite integralsTaylor seriesSeries and sumsMaxima and minimaThe chain ruleImplicit differentiationRelated rates and optimisationIntegration techniques: substitution, parts, partial fractionsApplications of integration: area, volume, arc lengthInfinite series and convergence tests