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Step by step
- \int x \log{\left(x \right)}\, dx
Find an antiderivative.
- u = \log{\left(x \right)},\quad du = \frac{1}{x}\, dx
Substitute u = \log{\left(x \right)}.
- \int x \log{\left(x \right)}\, dx = \int u e^{2 u}\, d_u
Rewrite the integral in terms of u.
- u = u,\quad dv = e^{2 u}\, d_u
Integration by parts: ∫u dv = uv − ∫v du.
- du = 1\, d_u,\quad v = \frac{e^{2 u}}{2}
Differentiate u, integrate dv.
- \int u e^{2 u}\, d_u = \frac{u e^{2 u}}{2} - \int \frac{e^{2 u}}{2}\, d_u
Apply the formula.
- \int \frac{e^{2 u}}{2}\, d_u = \frac{1}{2} \int e^{2 u}\, d_u
Pull the constant \frac{1}{2} out of the integral.
- u = 2 u,\quad du = 2\, d_u
Substitute u = 2 u.
- \int e^{2 u}\, d_u = \int \frac{e^{u}}{2}\, d_u
Rewrite the integral in terms of u.
- \int \frac{e^{u}}{2}\, d_u = \frac{1}{2} \int e^{u}\, d_u
Pull the constant \frac{1}{2} out of the integral.
- \int e^{u}\, d_u = e^{u}
∫ aᵘ du = aᵘ / ln a (for eˣ that is just eˣ).
- = \frac{e^{2 u}}{2}
Substitute back u = 2 u.
- = \frac{u e^{2 u}}{2} - \frac{e^{2 u}}{4}
Combine.
- = \frac{x^{2} \log{\left(x \right)}}{2} - \frac{x^{2}}{4}
Substitute back u = \log{\left(x \right)}.
- F(x) = \frac{x^{2} \left(2 \log{\left(x \right)} - 1\right)}{4} + C
Add the constant of integration.
Reveal the answer
\frac{x^{2} \left(2 \log{\left(x \right)} - 1\right)}{4} + C