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Complex numbers

i² = −1, arithmetic in the complex plane, modulus and conjugates.

Allowing one new number, i with i² = −1, makes every polynomial equation solvable. Complex numbers add like vectors and multiply by multiplying lengths and adding angles; the modulus |a + bi| = √(a² + b²) is the distance from 0. The solver evaluates the arithmetic exactly and the quadratic pages show where complex roots come from.

ឧទាហរណ៍​ដែល​បាន​ធ្វើ: (1 + 2i)*(3 - i)

Evaluate (1 + 2I)·(3 - I)

\left(1 + 2 i\right) \left(3 - i\right)

ជំហាន​ដោយ​ជំហាន

  1. \left(1 + 2 i\right) \left(3 - i\right) = 5 + 5 i

    Evaluate.

បង្ហាញ​ចម្លើយ
5 + 5 i

ព្យាយាម​របស់​អ្នក​ផ្ទាល់

បន្ថែម​ទៀត​ក្នុង Precalculus