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Turbulence and Kolmogorov 1941 (a heuristic theory)

The energy cascade, Kolmogorov's dimensional predictions, the one exact law, and what is and is not proved.

This lesson is different from the others: most of what it states is heuristic, supported by experiments and computation rather than proved from the equations. At high Reynolds number flows become turbulent: irregular, unpredictable in detail, and full of eddies of every size. Richardson (1922) described the picture in verse: big whirls have little whirls that feed on their velocity. Energy is injected at a large scale \(L\), passed by the nonlinearity to smaller and smaller eddies, and dissipated by viscosity only at the smallest scales. The rate \(\varepsilon\) at which energy per unit mass flows down this cascade equals the rate at which it is dissipated.

Kolmogorov (1941, now called K41) made this quantitative with two hypotheses about statistically homogeneous, isotropic turbulence: at scales much smaller than \(L\) the statistics are universal and depend only on \(\varepsilon\) and \(\nu\); and at scales between \(L\) and the dissipation scale they depend on \(\varepsilon\) alone. Everything else is dimensional analysis. From \(\nu\) (m²/s) and \(\varepsilon\) (m²/s³) there is exactly one length, velocity and time: \[ \eta = \left(\frac{\nu^3}{\varepsilon}\right)^{1/4}, \qquad u_\eta = (\nu\varepsilon)^{1/4}, \qquad \tau_\eta = \left(\frac{\nu}{\varepsilon}\right)^{1/2}. \] The Kolmogorov length \(\eta\) is where eddies are small enough for viscosity to destroy them; its Reynolds number \(u_\eta\eta/\nu\) is exactly 1. With \(\nu = 10^{-6}\) m²/s and \(\varepsilon = 10^{-3}\) W/kg, \(\eta \approx 0.18\) mm.

In the inertial range, the energy spectrum \(E(k)\) (energy per unit wavenumber, units m³/s²) can only be built from \(\varepsilon\) and \(k\), which forces \[ E(k) = C\,\varepsilon^{2/3}k^{-5/3}, \] the famous five-thirds law, confirmed in tidal channels, wind tunnels and the atmosphere with \(C \approx 1.5\). Equivalently velocity differences over a distance \(r\) scale like \((\varepsilon r)^{1/3}\). Using \(\varepsilon \sim U^3/L\), the ratio of largest to smallest scale is \(L/\eta \sim \mathrm{Re}^{3/4}\), so a direct simulation resolving every eddy needs about \(\mathrm{Re}^{9/4}\) grid points: a reason turbulence remains computationally hard.

Two results stand out as more than dimensional analysis. Kolmogorov's four-fifths law, \(\langle(\delta u_\parallel)^3\rangle = -\tfrac45\varepsilon r\), is derived from the Navier-Stokes equations under assumptions of homogeneity, isotropy and a non-vanishing dissipation limit. And Onsager's conjecture (1949) that energy is conserved by Euler solutions with Hölder regularity above \(1/3\), but can be dissipated below it, is now a theorem: the conservation half by Constantin, E and Titi (1994) and the dissipation half by Isett (2018) and Buckmaster, De Lellis, Székelyhidi and Vicol (2019). The exponent \(1/3\) is exactly the K41 scaling of velocity increments. The K41 predictions themselves are not theorems, and measured higher-order statistics deviate from them (intermittency, addressed by Kolmogorov in 1962).

Picture it: a waterfall of energy tumbling from big eddies to small ones at a steady rate, with viscosity waiting at the bottom. Think it: dimensional analysis with a single conserved flux fixes every exponent; the mathematical content of turbulence theory is to find out which of these predictions actually follow from the equations.

ਕੰਮ ਉਦਾਹਰਨ · (0.000001^3/0.001)^(1/4)

Evaluate (0.000001^3/0.001)^(1/4)

0.00017783

ਕਦਮ ਦਰ ਕਦਮ

  1. 0.000177827941 = \sqrt[4]{\frac{1}{1000000000000000000} \cdot 1000}

    Power: 1/0.001 = 1000.

  2. \sqrt[4]{\frac{1}{1000000000000000000} \cdot 1000} = \sqrt[4]{\frac{1}{1000000000000000}}

    Multiply: (1/1000000000000000000)·1000 = 1/1000000000000000.

  3. \sqrt[4]{\frac{1}{1000000000000000}} = 0.00017783

    Simplify.

ਜਵਾਬ ਦਿਓ
0.00017783

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ਮੁਫਤ ਅਕਾਊਂਟ ਹਰੇਕ ਲੈਕਚਰ ਉੱਤੇ ਨੋਟਿਸ ਸ਼ਾਮਲ ਕਰਦਾ ਹੈ, ਜੋ ਤੁਸੀਂ ਪੂਰਾ ਕੀਤਾ ਹੈ, ਉਸ ਦਾ ਰਿਕਾਰਡ, ਤੁਹਾਡੇ ਹੱਲ ਕੀਤੇ ਸਮੱਸਿਆਵਾਂ ਇੱਕ ਥਾਂ ਤੇ, ਅਤੇ ਇੱਕ ਟੂਟੋਰਿਅਲ, ਜਿਸ ਬਾਰੇ ਤੁਸੀਂ ਇਸ ਸਫ਼ੇ ਬਾਰੇ ਪੁੱਛ ਸਕਦੇ ਹੋ । ਗਣਿਤ ਆਪ ਹੀ ਹਰੇਕ ਲਈ ਖੁੱਲ੍ਹਾ ਹੈ, ਲਾਗਇਨ ਕੀਤਾ ਹੋਵੇ ਜਾਂ ਨਾ ਹੋਵੇ ।

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ਇੱਥੇ ਵਰਤੇ ਨਿਸ਼ਾਨ

ਕਿਸੇ ਵੀ ਨਿਸ਼ਾਨ ਨੂੰ ਦਬਾਉ, ਜਿਸ ਵਿੱਚ ਪੂਰੀ ਪਰਿਭਾਸ਼ਾ, ਇੱਕ ਤਸਵੀਰ ਅਤੇ ਹਰ ਅੱਖਰ ਦਾ ਅਰਥ ਹੈ ।

ਕਿਵੇਂ: Turbulence and Kolmogorov 1941 (a heuristic theory)

  1. List the quantities allowed (epsilon, nu, k or r) and their units in metres and seconds.
  2. Write the unknown as a product of powers and match the exponents of metres and seconds.
  3. Solve the small linear system for the exponents.
  4. Remember the status: these are predictions of a heuristic theory, checked against data, not theorems.

ਲੋਕ ਪੁੱਛਦੇ ਹਨ

Is turbulence described by the Navier-Stokes equations?

Physicists and engineers are confident it is: simulations of the equations reproduce measured turbulence statistics. What is not known is how to derive those statistics mathematically.

Why five thirds?

Because E(k) has units of m^3/s^2, and the only way to make those units from epsilon (m^2/s^3) and k (1/m) is epsilon^(2/3) k^(-5/3). No other combination fits.

What do I need before starting fluid dynamics?

Multivariable calculus (divergence, curl, the divergence and Stokes theorems), linear algebra (symmetric matrices and eigenvalues) and partial differential equations (the heat and Laplace equations). The last lessons also use Sobolev spaces, which are introduced where they are needed.

What are the Navier-Stokes equations in one sentence?

Newton's second law for each particle of a viscous incompressible fluid: acceleration equals the pressure force plus viscous diffusion of momentum, with the constraint that the velocity field is divergence-free.

Why is two-dimensional flow easier than three-dimensional flow?

In 2D the vorticity is a scalar that is only carried and diffused, so its maximum never grows; in 3D vortex lines can be stretched, which amplifies vorticity, and no known bound rules out unlimited growth.

Is this course physics or mathematics?

Both, in order. The first half derives the equations from physical principles and solves classical flows; the second half treats the equations as mathematical objects and studies which of their properties can be proved.

ਹੋਰ ਵਿੱਚ Fluid Dynamics