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Dimensional analysis, the Reynolds number and the scaling symmetry

Non-dimensionalising Navier-Stokes, dynamic similarity, and the scaling that leaves the equations unchanged.

Physical laws cannot depend on the choice of units. Measure lengths in units of a typical size \(L\), velocities in units of a typical speed \(U\), times in units of \(L/U\) and pressure in units of \(\rho U^2\). Writing \(\mathbf{x} = L\mathbf{x}'\), \(\mathbf{u} = U\mathbf{u}'\), \(t = (L/U)t'\), \(p = \rho U^2 p'\) in the Navier-Stokes equations and dropping the primes gives \[ \frac{\partial\mathbf{u}}{\partial t} + (\mathbf{u}\cdot\nabla)\mathbf{u} = -\nabla p + \frac{1}{\mathrm{Re}}\Delta\mathbf{u}, \qquad \mathrm{Re} = \frac{UL}{\nu}. \] Everything about the fluid, the speed and the size has collapsed into one number, the Reynolds number, named after Osborne Reynolds, whose 1883 dye experiments in glass pipes showed that the transition from smooth to turbulent flow is governed by this combination.

The Reynolds number compares inertia with viscosity: \(|(\mathbf{u}\cdot\nabla)\mathbf{u}| \sim U^2/L\) against \(|\nu\Delta\mathbf{u}| \sim \nu U/L^2\), whose ratio is \(UL/\nu\). A bacterium swimming (\(\mathrm{Re} \sim 10^{-4}\)) lives in a world ruled by viscosity; a whale (\(\mathrm{Re} \sim 10^{8}\)) in one ruled by inertia. Water at 2 m/s in a 10 cm pipe has \(\mathrm{Re} = 2\times0.1/10^{-6} = 2\times10^5\). Two geometrically similar flows with the same Reynolds number are the same dimensionless flow: this dynamic similarity is why a scale model in a water tunnel can predict a full-size aircraft. More generally the Buckingham Pi theorem (1914) says a relation among \(n\) dimensional quantities built from \(k\) independent units is a relation among \(n-k\) dimensionless groups; the drag on a sphere must take the form \(F = \rho U^2 L^2\,g(\mathrm{Re})\).

On all of space, with no boundaries to fix a length, the equations have an exact scaling symmetry. If \((\mathbf{u},p)\) solves the unforced Navier-Stokes equations on \(\mathbb{R}^3\), then so does \[ \mathbf{u}_\lambda(\mathbf{x},t) = \lambda\,\mathbf{u}(\lambda\mathbf{x},\lambda^2 t), \qquad p_\lambda(\mathbf{x},t) = \lambda^2 p(\lambda\mathbf{x},\lambda^2 t), \] for every \(\lambda \gt 0\). To check it, count powers of \(\lambda\): \(\partial_t\mathbf{u}_\lambda\), \((\mathbf{u}_\lambda\cdot\nabla)\mathbf{u}_\lambda\), \(\nabla p_\lambda\) and \(\nu\Delta\mathbf{u}_\lambda\) each carry exactly \(\lambda^3\). Time scales like length squared, as in the heat equation, and velocity like inverse length.

The scaling tells you how any norm behaves at small scales. For the \(L^q\) norm in space, the change of variables \(\mathbf{y} = \lambda\mathbf{x}\) gives \[ \|\mathbf{u}_\lambda(\cdot,t)\|_{L^q(\mathbb{R}^3)} = \lambda^{1 - 3/q}\,\|\mathbf{u}(\cdot,\lambda^2 t)\|_{L^q}. \] The kinetic energy \(\int|\mathbf{u}_\lambda|^2\,dx\) scales like \(\lambda^{-1}\): zooming in on small scales (\(\lambda\) large) makes the energy look small even when the velocity gradients are huge. The \(L^3\) norm is unchanged. Norms that scale like \(\lambda^0\) are called critical, and this bookkeeping is the organising principle of the modern theory in the last lessons.

Picture it: a flow zoomed in by a factor \(\lambda\) and played \(\lambda^2\) times faster, with velocities multiplied by \(\lambda\), is still a Navier-Stokes flow. Think it: the local Reynolds number of the rescaled flow, speed times length over viscosity, is unchanged by the scaling; a critical norm is one that measures a flow the same way at every scale.

Օրինակ · 1000*2*0.1/0.001

Evaluate 1000*2*0.1/0.001

200000.0

Քայլ առ քայլ

  1. 200000.0 = 200000

    Multiply: 1000·2·0.1·1000 = 200000.

Առաջարկել պատասխանը
200000.0

Now you Ընտրեք խնդիր, կամ տեքստ գրեք կամ նկարեք ձեր սեփականը։ Յուրաքանչյուր քայլ, նկար, պատասխանը թաքնված է մինչև դուք հարցնեք։

Ձեր սեփական աշխատանքը շարունակեք

Ազատ հաշիվը յուրաքանչյուր դասավանդման համար գրառումներ է ավելացնում, Ձեր ավարտելիք դասերի և լուծված խնդիրների ցուցակ է պահում մեկ տեղում, և ուսուցիչ, ում կարող եք հարցնել այս էջի մասին։ Մաթեմատիկան բաց է բոլորի համար, անկախ նրանից մուտքագրվել եք արդյոք կամ ոչ։

Գրանցվել Գրանցում

Օգտագործված սիմվոլներ

Տեղադրեք ցանկացած նշան՝ ամբողջական սահմանման, նկարի և դրա մեջ ամեն մի տառի իմաստը տեսնելու համար։

Ինչպես: Dimensional analysis, the Reynolds number and the scaling symmetry

  1. Pick a velocity scale U, a length scale L, and look up the kinematic viscosity nu.
  2. Compute Re = U L / nu and compare it with known thresholds for the geometry.
  3. For a model test, choose model speed or fluid so that the Reynolds numbers match.
  4. For a scaling question, assign powers of lambda to x, t, u and p and count them term by term.

Հարցեր, որոնք մարդիկ տալիս են :

Is there a single critical Reynolds number for turbulence?

No. It depends on geometry and on how quiet the incoming flow is. Pipe flow typically turns turbulent around 2000 to 4000, but disturbance-free experiments have kept it laminar at 100,000.

Why does the scaling need all of space?

A boundary or a periodic box fixes a length, and rescaling would change the domain. On the torus the symmetry still holds between tori of different sizes, which is enough to use it heuristically.

What do I need before starting fluid dynamics?

Multivariable calculus (divergence, curl, the divergence and Stokes theorems), linear algebra (symmetric matrices and eigenvalues) and partial differential equations (the heat and Laplace equations). The last lessons also use Sobolev spaces, which are introduced where they are needed.

What are the Navier-Stokes equations in one sentence?

Newton's second law for each particle of a viscous incompressible fluid: acceleration equals the pressure force plus viscous diffusion of momentum, with the constraint that the velocity field is divergence-free.

Why is two-dimensional flow easier than three-dimensional flow?

In 2D the vorticity is a scalar that is only carried and diffused, so its maximum never grows; in 3D vortex lines can be stretched, which amplifies vorticity, and no known bound rules out unlimited growth.

Is this course physics or mathematics?

Both, in order. The first half derives the equations from physical principles and solves classical flows; the second half treats the equations as mathematical objects and studies which of their properties can be proved.

Ցուցադրել Fluid Dynamics