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Weak solutions (Leray-Hopf) and Sobolev spaces for fluids
Solutions that exist for all time and all finite-energy data, the function spaces they live in, and what is known about them.
Without a bound that prevents blow-up, one can still ask for solutions in a weaker sense, defined by what the energy equality controls. The natural spaces are these. \(L^2_\sigma\) is the closure in \(L^2\) of smooth, compactly supported, divergence-free fields. The homogeneous Sobolev space \(\dot H^1\) measures \(\|\nabla\mathbf{u}\|_{L^2}\); in Fourier terms \(\|\mathbf{u}\|^2_{\dot H^s} = \int|\mathbf{k}|^{2s}|\hat{\mathbf{u}}(\mathbf{k})|^2\,d\mathbf{k}\), which defines \(\dot H^s\) for every real \(s\). Sobolev embedding in 3D says \(\dot H^1 \subset L^6\) and \(\dot H^{1/2} \subset L^3\); scaling explains the exponents, since both sides must change by the same power of \(\lambda\).
A Leray-Hopf weak solution with data \(\mathbf{u}_0 \in L^2_\sigma\) is a field \[ \mathbf{u} \in L^\infty(0,T;L^2_\sigma) \cap L^2(0,T;\dot H^1) \] that satisfies the equations in the sense of distributions against divergence-free test fields \(\boldsymbol{\varphi}\) (so the pressure never appears): \[ \int_0^T\!\!\int \left(-\mathbf{u}\cdot\partial_t\boldsymbol{\varphi} - (\mathbf{u}\otimes\mathbf{u}):\nabla\boldsymbol{\varphi} + \nu\nabla\mathbf{u}:\nabla\boldsymbol{\varphi}\right)dx\,dt = \int\mathbf{u}_0\cdot\boldsymbol{\varphi}(\cdot,0)\,dx, \] together with the energy inequality \(\tfrac12\|\mathbf{u}(t)\|^2_{L^2} + \nu\int_0^t\|\nabla\mathbf{u}\|^2_{L^2}\,ds \le \tfrac12\|\mathbf{u}_0\|^2_{L^2}\) for all \(t\). A smooth solution with enough decay is a weak solution: multiply by \(\boldsymbol{\varphi}\) and integrate by parts.
Leray (1934, on \(\mathbb{R}^3\)) and Hopf (1951, in bounded domains) proved that global weak solutions exist for every finite-energy initial datum. The method: solve an approximate problem (Hopf used the Galerkin method, truncating to finitely many Fourier modes), obtain the energy bound uniformly in the approximation, extract a weakly convergent subsequence, and use compactness in time (later formalised as the Aubin-Lions lemma) to get strong \(L^2\) convergence, which is what the quadratic term needs. Norms can drop under weak limits, which is why only an inequality for the energy survives.
What is known about these solutions. They are smooth and unique as long as a smooth solution exists (weak-strong uniqueness, Prodi 1959 and Serrin 1963). In two dimensions they are always unique and smooth (Lions and Prodi, 1959; Ladyzhenskaya). In three dimensions Leray showed they are smooth except on a closed set of times of measure zero, and smooth after some large time; Scheffer (1976) sharpened this to zero half-dimensional Hausdorff measure. Their uniqueness in 3D is open; Albritton, Brué and Colombo (2022) proved non-uniqueness of Leray-Hopf solutions with a specially constructed force, and Buckmaster and Vicol (2019) proved non-uniqueness for a weaker class of finite-energy weak solutions that need not satisfy the energy inequality.
The energy class controls \(\mathbf{u}\) in \(L^p_tL^q_x\) whenever \(\frac2p + \frac3q = \frac32\), \(2 \le q \le 6\), by interpolating between \(L^\infty L^2\) and \(L^2L^6\). Compare that with the scale-invariant relation \(\frac2p + \frac3q = 1\) in the next lesson: the energy falls short by exactly one half, the quantitative form of saying it is supercritical.
Picture it: a weak solution is a flow we can only see through frosted glass (averaged against smooth test fields), bright enough to know it exists and has bounded energy, too blurred to tell whether it has a singular point. Think it: existence comes from compactness plus the energy bound, and regularity needs more than the energy gives; that gap is the whole difficulty.
Contoh yang dikerjakan · integrate 1/(1+x^2)^2 dx from -oo to oo
Integrate (x^2 + 1)^(-2) from -oo to oo
Langkah demi langkah
- \int_{-\infty}^{\infty} \frac{1}{\left(x^{2} + 1\right)^{2}}\, dx
First find an antiderivative F, then evaluate F(b) − F(a).
- x = \tan{\left(\theta \right)}
Trigonometric substitution.
- \cos^{2}{\left(\theta \right)} = \frac{\cos{\left(2 \theta \right)}}{2} + \frac{1}{2}
Rewrite the integrand into a friendlier form.
- \int \frac{\cos{\left(2 \theta \right)}}{2} + \frac{1}{2}\, d_theta = \int \frac{\cos{\left(2 \theta \right)}}{2}\, d_theta + \int \frac{1}{2}\, d_theta
The integral of a sum is the sum of the integrals.
- \int \frac{\cos{\left(2 \theta \right)}}{2}\, d_theta = \frac{1}{2} \int \cos{\left(2 \theta \right)}\, d_theta
Pull the constant \frac{1}{2} out of the integral.
- u = 2 \theta,\quad du = 2\, d_theta
Substitute u = 2 \theta.
- \int \cos{\left(2 \theta \right)}\, d_theta = \int \frac{\cos{\left(u \right)}}{2}\, d_u
Rewrite the integral in terms of u.
- \int \frac{\cos{\left(u \right)}}{2}\, d_u = \frac{1}{2} \int \cos{\left(u \right)}\, d_u
Pull the constant \frac{1}{2} out of the integral.
- \int \cos{\left(u \right)}\, d_u = \sin{\left(u \right)}
Standard trigonometric antiderivative.
- = \frac{\sin{\left(2 \theta \right)}}{2}
Substitute back u = 2 \theta.
- \int \frac{1}{2}\, d_theta = \frac{\theta}{2}
The integral of a constant c is c·x.
- = \frac{x}{2 \left(x^{2} + 1\right)} + \frac{\operatorname{atan}{\left(x \right)}}{2}
Substitute back.
- F(\infty) - F(-\infty) = \left(\text{NaN}\right) - \left(\text{NaN}\right)
Fundamental theorem of calculus: plug in the limits.
- = \frac{\pi}{2} \approx 1.5708
Simplify.
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Bagaimana untuk: Weak solutions (Leray-Hopf) and Sobolev spaces for fluids
- Fix the space: L^infinity in time with values in L^2 (divergence-free), and L^2 in time with values in H^1.
- Write the weak formulation by testing against smooth divergence-free fields, so the pressure drops out.
- Build approximate solutions (Galerkin), bound them uniformly with the energy equality, and pass to the limit using compactness.
- Keep track of what is lost: the limit satisfies only the energy inequality.
Soalan yang orang tanya
Why not just prove the equations have smooth solutions directly?
Because for large data in 3D no known estimate controls enough derivatives for all time. Weak solutions are what the energy bound alone can deliver.
Are weak solutions physically meaningful?
Leray called them turbulent solutions and hoped they would describe turbulence. If they are unique and smooth they coincide with the classical solution; if not, deciding which one nature picks would be a new physical question.
What do I need before starting fluid dynamics?
Multivariable calculus (divergence, curl, the divergence and Stokes theorems), linear algebra (symmetric matrices and eigenvalues) and partial differential equations (the heat and Laplace equations). The last lessons also use Sobolev spaces, which are introduced where they are needed.
What are the Navier-Stokes equations in one sentence?
Newton's second law for each particle of a viscous incompressible fluid: acceleration equals the pressure force plus viscous diffusion of momentum, with the constraint that the velocity field is divergence-free.
Why is two-dimensional flow easier than three-dimensional flow?
In 2D the vorticity is a scalar that is only carried and diffused, so its maximum never grows; in 3D vortex lines can be stretched, which amplifies vorticity, and no known bound rules out unlimited growth.
Is this course physics or mathematics?
Both, in order. The first half derives the equations from physical principles and solves classical flows; the second half treats the equations as mathematical objects and studies which of their properties can be proved.
Lebih dalam Fluid Dynamics
The continuum hypothesis and fieldsEulerian and Lagrangian descriptions, the material derivativeKinematics: streamlines, pathlines and streaklinesConservation of mass, the continuity equation and incompressibilityThe stream function and two-dimensional incompressible flowVorticity, circulation and Kelvin's circulation theoremThe stress tensor and Cauchy's momentum equationHydrostatics and pressureThe Euler equations and Bernoulli's theoremPotential flow and the Laplace equationViscosity, Newtonian fluids and the Navier-Stokes equationsExact solutions: Couette, Poiseuille and Stokes' first problemDimensional analysis, the Reynolds number and the scaling symmetryStokes flow at low Reynolds number