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Power series and analytic continuation

Radius of convergence, the identity theorem, and extending ζ(s) beyond its series.

A holomorphic function equals its Taylor series on the largest disc avoiding singularities. Two holomorphic functions agreeing on a small set agree everywhere they are both defined, so a function can be extended uniquely, which is how ζ(s) exists at s = −1 (and equals −1/12). Picture it: the geometric series 1/(1 − x) converging inside |x| < 1, though the function lives everywhere except x = 1. Think it: this rigidity is the engine of the Riemann Hypothesis page.

ឧទាហរណ៍​ដែល​បាន​ធ្វើ · taylor series of 1/(1-x)

Calculus · Taylor-Series

Taylor series of 1/(1 - x)

\frac{1}{1 - x}

ជំហាន​ដោយ​ជំហាន

  1. f(x) = \frac{1}{1 - x}

    Taylor series about x = 0: f(x) = Σ fᵏ(x₀)/k! · (x − x₀)ᵏ.

  2. f^{(0)}(0) = \frac{1}{1 - x}\big|_{x=0} = 1

    Derivative 0 at the centre.

  3. f^{(1)}(0) = \frac{1}{\left(1 - x\right)^{2}}\big|_{x=0} = 1

    Derivative 1 at the centre.

  4. f^{(2)}(0) = - \frac{2}{\left(x - 1\right)^{3}}\big|_{x=0} = 2

    Derivative 2 at the centre.

  5. f^{(3)}(0) = \frac{6}{\left(x - 1\right)^{4}}\big|_{x=0} = 6

    Derivative 3 at the centre.

  6. f^{(4)}(0) = - \frac{24}{\left(x - 1\right)^{5}}\big|_{x=0} = 24

    Derivative 4 at the centre.

  7. f^{(5)}(0) = \frac{120}{\left(x - 1\right)^{6}}\big|_{x=0} = 120

    Derivative 5 at the centre.

  8. x^{5} + x^{4} + x^{3} + x^{2} + x + 1

    Assemble the terms up to degree 5.

បង្ហាញ​ចម្លើយ
x^{5} + x^{4} + x^{3} + x^{2} + x + 1 + O((x-0)^{6})

ឥឡូវ​អ្នក ជ្រើស​បញ្ហា ឬ​វាយ​បញ្ចូល ឬ​គូរ​របស់​អ្នក​ផ្ទាល់ ។ ជំហាន​នីមួយៗ រូបភាព ចម្លើយ​ត្រូវ​បាន​លាក់​រហូត​ដល់​អ្នក​សួរ ។

រក្សា​ការ​ធ្វើការ​របស់​អ្នក​ផ្ទាល់

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ចុះឈ្មោះ ចូល

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ចុច​និមិត្ត​សញ្ញា​ណាមួយ​សម្រាប់​ការ​កំណត់​ពេញលេញ រូបភាព និង​តួអក្សរ​នីមួយៗ​មាន​ន័យ​អ្វី ។

របៀប​: Power series and analytic continuation

  1. Taylor series about x = 0: f(x) = Σ fᵏ(x₀)/k! · (x − x₀)ᵏ.
  2. Derivative 0 at the centre.
  3. Derivative 1 at the centre.
  4. Derivative 2 at the centre.
  5. Derivative 3 at the centre.
  6. Derivative 4 at the centre.
  7. Derivative 5 at the centre.
  8. Assemble the terms up to degree 5.

សំណួរ​ដែល​មនុស្ស​សួរ

Why is complex differentiability so much stronger than real?

The limit must be the same from every direction in the plane, not just two. That forces the Cauchy-Riemann equations, which in turn force infinitely many derivatives and a convergent Taylor series.

What is a residue?

The coefficient of 1/(z − a) in the Laurent series at a singularity a. The residue theorem says a contour integral equals 2πi times the sum of the residues inside, which evaluates many real integrals in one line.

បន្ថែម​ទៀត​ក្នុង Complex Analysis

The complex plane and Euler's formulaHolomorphic functions and the Cauchy-Riemann equationsContour integrals and the residue theorem