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The complex plane and Euler's formula

z = x + iy as a point, modulus and argument, e^{iθ} = cos θ + i sin θ.

Complex numbers are points in the plane; multiplication rotates and scales. Euler's formula makes rotation an exponential, so e^{iπ} = −1. Picture it: polar form of 1 + i, the point at distance √2 and angle 45°. Think it: the exponential map wraps the imaginary axis around the unit circle; that periodicity is why the complex logarithm has branches.

Nhazi ahụ ejirila · e^(i*pi)

Arithmetic · Arithmetic

Evaluate e^(i*pi)

e^{i \pi}

Nzọụkwụ site n'ụdị

e^{i \pi} = -1
Power: E^(I·π) = -1.

Gosi nzaghachi

-1

Ugbu a ị Họrọ nsogbu, mọọbụ tinye mọọbụ depụta gị. Nzọụkwụ ọbụla, inyogo, azịza ahụ echekwara ruo mgbe ịjụla.

Kwụsị ọrụ gị

Akwụkwọ ndebanye n'efu na-egbakwunye ntọala n'ụdị ọmụmụ ihe ọbụla, ndepụta nke ihe ị ga-eme, nsogbu ị ga-ewepụ n'otu ebe, na onye nkụzi ị ga-ajụ banyere ihuakwụkwọ a. Akwụkwọ ndepụta ihe bụ nke ọbụla mepere maka onye ọbụla, ọbụla ma ọ bụ na ọ bụghị.

Akaụntụ Nbanye

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Tinye ọbụla simbụl maka nkọwa zuru ezu, inyogo, na ihe ọbụla ọbụla na-egosi.

Olee otú: The complex plane and Euler's formula

Power: E^(I·π) = -1.

Ajụjụ ndị mmadụ jụrụ

Why is complex differentiability so much stronger than real?

The limit must be the same from every direction in the plane, not just two. That forces the Cauchy-Riemann equations, which in turn force infinitely many derivatives and a convergent Taylor series.

What is a residue?

The coefficient of 1/(z − a) in the Laurent series at a singularity a. The residue theorem says a contour integral equals 2πi times the sum of the residues inside, which evaluates many real integrals in one line.

Oge Complex Analysis

Holomorphic functions and the Cauchy-Riemann equations Contour integrals and the residue theorem Power series and analytic continuation