maths.free › Combinatorics & Graph Theory › 6. Partially Ordered Sets › The Subset Lattice

The Subset Lattice

When X is a finite set, the family of all subsets of X, partially ordered by inclusion, forms a subset latticeA lattice is a special type of poset.

The Subset Lattice

When \(X\) is a finite set, the family of all subsets of \(X\), partially ordered by inclusion, forms a subset latticeA lattice is a special type of poset. You do not have to concern yourself with the definition and can safely replace lattice with poset as you read this chapter.. We illustrate this in where we show the lattice of all subsets of \(\{1,2,3,4\}\). In this figure, note that we are representing sets by bit strings, and we have further abbreviated the notation by writing strings without commas and parentheses.

For a positive integer \(t\), we let \(\bftwo^t\) denote the subset lattice consisting of all subsets of \(\{1,2,\dots,t\}\) ordered by inclusion. Some elementary properties of this poset are:

The height is \(t+1\) and all maximal chains have exactly \(t+1\) points.
The size of the poset \(\bftwo^t\) is \(2^t\) and the elements are partitioned into ranks (antichains) \(A_0, A_1,\dots, A_t\) with \(|A_i|=\binom{t}{i}\) for each \(i=0,1,\dots,t\).
The maximum size of a rank in the subset lattice occurs in the middle, if \(s=\lfloor t/2\rfloor\), then the largest binomial coefficient in the sequence \(\binom{t}{0}, \binom{t}{1},\binom{t}{2},\dots,\binom{t}{t}\) is \(\binom{t}{s}\). Note that when \(t\) is odd, there are two ranks of maximum size, but when \(t\) is even, there is only one.

Sperner's Theorem

For the width of the subset lattice, we have the following classic result of Sperner.

Theorem: Sperner's Theorem

For each \(t\ge1\), the width of the subset lattice \(\bftwo^t\) is the maximum size of a rank, , \[\begin{aligned}\end{aligned}\].

Proof

The width of the poset \(\bftwo^t\) is at least \(C(t,\lfloor\frac{t}{2}\rfloor)\) since the set of all \(\lfloor\frac{t}{2}\rfloor\)-element subsets of \(\{1,2,\dots,t\}\) is an antichain. We now show that the width of \(\bftwo^t\) is at most \(C(t,\lfloor\frac{t}{2}\rfloor)\).

Let \(w\) be the width of \(\bftwo^t\) and let \(\{S_1,S_2,\dots, S_w\}\) be an antichain of size \(w\) in this poset, , each \(S_i\) is a subset of \(\{1,2,\dots,t\}\) and if \(1\le i\lt j\le w\), then \(S_i\nsubseteq S_j\) and \(S_j\nsubseteq S_i\).

For each \(i\), consider the set \(\cgS_i\) of all maximal chains which pass through \(S_i\). It is easy to see that if \(|S_i|=k_i\), then \(|\cgS_i|=k_i!(t-k_i)!\). This follows from the observation that to form such a maximum chain beginning with \(S_i\) as an intermediate point, you delete the elements of \(S_i\) one at a time to form the sets of the lower part of the chain. Also, to form the upper part of the chain, you add the elements not in \(S_i\) one at a time.

Note further that if \(1\le i \lt j\le w\), then \(\cgS_i\cap \cgS_j =\emptyset\), for if there was a maximum chain belonging to both \(\cgS_i\) and \(\cgS_j\), then it would imply that one of \(S_i\) and \(S_j\) is a subset of the other.

Altogether, there are exactly \(t!\) maximum chains in \(\bftwo^t\). This implies that \[\begin{aligned}\end{aligned}\]. This implies that \[\begin{aligned}\end{aligned}\] It follows that \[\begin{aligned}\end{aligned}\]. Thus \[\begin{aligned}\end{aligned}\].

Symbols used here

\binom{n}{k}

binomial coefficient, "n choose k"
Number of k-element subsets of n things: n!/(k!(n−k)!).

A \cup B,\ A \cap B,\ A \setminus B

union, intersection, difference
In either; in both; in A but not B.

imaginary unit
i² = −1.

\leq,\ \geq

less/greater than or equal
Inequalities that allow equality; < and > exclude it.

factorial
n × (n−1) × … × 1; the number of orderings of n things. 0! = 1.

\sum_{k=1}^{n} a_k

summation
Add a_k for k = 1 up to n.

\prod_{k=1}^{n} a_k

product
Multiply a_k for k = 1 up to n.

\emptyset,\ |A|

empty set, cardinality
The set with no elements; the number of elements of A.

Questions people ask

Permutation or combination?

Ask whether order matters. A lock code is a permutation (order matters); a hand of cards is a combination (it does not).

What is a graph in this sense?

Dots (vertices) joined by lines (edges) — not a plot. Road maps, social networks and molecules are graphs; questions like "is there a route" and "how few colours" are graph theory.

Обиди се со себе.

Parts of this page are adapted from Keller & Trotter, Applied Combinatorics (CC BY-SA 4.0). Condensed and re-explained here; errors are ours.

Повеќе во Combinatorics & Graph Theory

The counting principles Pigeonhole principle and inclusion–exclusion Binomial coefficients and Pascal's triangle Recurrences and generating functions Graphs: vertices, edges, degrees Paths, cycles, trees, Euler and Hamilton Colouring and planar graphs