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The Stable Matching Theorem
Now we present a light hearted optimization problem with a quite clever solution, called the Stable Matching Theorem. There are n eligible homebuyers b_1, b_2,\dots,b_n and n eligible homesellers s_1, s_2,\dots,s_n.
The Stable Matching Theorem
Now we present a light hearted optimization problem with a quite clever solution, called the Stable Matching Theorem. There are \(n\) eligible homebuyers \(b_1\), \(b_2,\dots,b_n\) and \(n\) eligible homesellers \(s_1\), \(s_2,\dots,s_n\). We will arrange \(n\) home sales, each involving one buyer and one seller. In the process, we will try to make everyone happyor at least we will try to keep things stable.
Each seller linearly orders the buyers in the order of their preference, i.e., for each \(i=1,2,\dots,n\), there is a permutation \(\sigma_i\) of \([n]\) so that if \(s_i\) prefers \(b_j\) to \(b_k\), then \(\sigma_i(j)\gt \sigma_i(k)\). Different sellers may have quite different preference orders. Also, each buyer linearly orders the sellers (really, the homes they are selling!) in order of their preference, i.e., for each \(i=1,2,\dots,n\), there is a permutation \(\tau_i\) of \([n]\) so that if \(b_i\) prefers \(s_j\) to \(s_k\), then \(\tau_i(j)\gt\tau_i(k)\).
A \(1\)\(1\) matching of the \(n\) buyers to the \(n\) sellers is stable if there do not exist two buyers \(b\) and \(b'\) and two sellers \(s\) and \(s'\) so that
- \(b\)\(s\)
- \(b'\)\(s'\)
- \(b\)\(s'\)\(s\)
- \(s'\)\(b\)\(b'\)
The question is whether, regardless of their respective preferences, we can always generate a stable matching. The answer is yes and there is a clever argument. In fact, it is one that yields an efficient algorithm. To start, each buyer knocks on the front door of the seller who is tops on their list. It may happen that some sellers have more than one prospective buyer on their doorstep while others have none. However, if a seller has one or more buyers at their door, then the seller invites the buyer on their doorstep which they prefer most to come in and tells the others, if there are any, to go away. Any buyer rejected at this step proceeds to the front door of the home that is second on their list. Again, a seller with one or more buyers at their door (including the one previously invited to come in, if applicable) chooses the best among them and sends the others away. This process continues until eventually, each seller is has exactly one buyer in their home.
Condensed: the full section is in Keller & Trotter, Applied Combinatorics.
Tani ti. Asnjë kalkulator nuk e zgjidh këtë, por pjesët e saj janë të llogaritura. Provo një më poshtë, ose shkruaj tënde.
Një llogari e lirë shtohet shënime në çdo mësim, një regjistrim të asaj që ju keni përfunduar, problemet tuaja të zgjidhura në një vend, dhe një mësues që ju mund të pyesni rreth kësaj faqeje. Matematika vetë është e hapur për të gjithë, të regjistruar apo jo.
Regjistrohu HyrSimbolet e përdorura këtu
Prek çdo simbol për përkufizimin e plotë, një fotografi dhe se çfarë do të thotë çdo shkronjë në të.
Pyetja që bëjnë njerëzit
Permutation or combination?
Ask whether order matters. A lock code is a permutation (order matters); a hand of cards is a combination (it does not).
What is a graph in this sense?
Dots (vertices) joined by lines (edges), not a plot. Road maps, social networks and molecules are graphs; questions like "is there a route" and "how few colours" are graph theory.
Pjesa e kësaj faqeje është adaptuar nga Keller & Trotter, Applied Combinatorics (CC BY-SA 4.0). E përmbledhur dhe ri-shkruar këtu; gabimet janë tona.
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