maths.free › Combinatorics & Graph Theory › The Many Faces of Combinatorics › The Stable Matching Theorem
The Stable Matching Theorem
Now we present a light hearted optimization problem with a quite clever solution, called the Stable Matching Theorem. There are n eligible homebuyers b_1, b_2,\dots,b_n and n eligible homesellers s_1, s_2,\dots,s_n.
The Stable Matching Theorem
Now we present a light hearted optimization problem with a quite clever solution, called the Stable Matching Theorem. There are \(n\) eligible homebuyers \(b_1\), \(b_2,\dots,b_n\) and \(n\) eligible homesellers \(s_1\), \(s_2,\dots,s_n\). We will arrange \(n\) home sales, each involving one buyer and one seller. In the process, we will try to make everyone happyor at least we will try to keep things stable.
Each seller linearly orders the buyers in the order of their preference, i.e., for each \(i=1,2,\dots,n\), there is a permutation \(\sigma_i\) of \([n]\) so that if \(s_i\) prefers \(b_j\) to \(b_k\), then \(\sigma_i(j)\gt \sigma_i(k)\). Different sellers may have quite different preference orders. Also, each buyer linearly orders the sellers (really, the homes they are selling!) in order of their preference, i.e., for each \(i=1,2,\dots,n\), there is a permutation \(\tau_i\) of \([n]\) so that if \(b_i\) prefers \(s_j\) to \(s_k\), then \(\tau_i(j)\gt\tau_i(k)\).
A \(1\)\(1\) matching of the \(n\) buyers to the \(n\) sellers is stable if there do not exist two buyers \(b\) and \(b'\) and two sellers \(s\) and \(s'\) so that
- \(b\)\(s\)
- \(b'\)\(s'\)
- \(b\)\(s'\)\(s\)
- \(s'\)\(b\)\(b'\)
The question is whether, regardless of their respective preferences, we can always generate a stable matching. The answer is yes and there is a clever argument. In fact, it is one that yields an efficient algorithm. To start, each buyer knocks on the front door of the seller who is tops on their list. It may happen that some sellers have more than one prospective buyer on their doorstep while others have none. However, if a seller has one or more buyers at their door, then the seller invites the buyer on their doorstep which they prefer most to come in and tells the others, if there are any, to go away. Any buyer rejected at this step proceeds to the front door of the home that is second on their list. Again, a seller with one or more buyers at their door (including the one previously invited to come in, if applicable) chooses the best among them and sends the others away. This process continues until eventually, each seller is has exactly one buyer in their home.
Condensed: the full section is in Keller & Trotter, Applied Combinatorics.
Ahora tú Ninguna calculadora resuelve este, pero las piezas son computables. Pruebe uno abajo, o escriba el suyo.
Una cuenta gratuita añade notas sobre cada lección, un registro de lo que has terminado, tus problemas resueltos en un lugar, y un tutor que puedes preguntar sobre esta página. Las matemáticas en sí están abiertas a todos, se han registrado o no.
Registrarse Inicio de sesiónSímbolos utilizados aquí
Toque cualquier símbolo para la definición completa, una imagen, y lo que cada letra en ella significa.
Preguntas que la gente hace
Permutation or combination?
Ask whether order matters. A lock code is a permutation (order matters); a hand of cards is a combination (it does not).
What is a graph in this sense?
Dots (vertices) joined by lines (edges), not a plot. Road maps, social networks and molecules are graphs; questions like "is there a route" and "how few colours" are graph theory.
Partes de esta página están adaptadas de Keller & Trotter, Applied Combinatorics (CC BY-SA 4.0). Condensados y re-explicados aquí; los errores son nuestros.
Más en Combinatorics & Graph Theory
The counting principlesPigeonhole principle and inclusion, exclusionBinomial coefficients and Pascal's triangleRecurrences and generating functionsGraphs: vertices, edges, degreesPaths, cycles, trees, Euler and HamiltonColouring and planar graphs