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Multinomial Coefficients

Let X be a set of n elements. Suppose that we have two colors of paint, say red and blue, and we are going to choose a subset of k elements to be painted red with the rest painted blue.

Multinomial Coefficients

Let \(X\) be a set of \(n\) elements. Suppose that we have two colors of paint, say red and blue, and we are going to choose a subset of \(k\) elements to be painted red with the rest painted blue. Then the number of different ways this can be done is just the binomial coefficient \(\binom{n}{k}\). Now suppose that we have three different colors, say red, blue, and green. We will choose \(k_1\) to be colored red, \(k_2\) to be colored blue, and the remaining \(k_3 = n - (k_1+k_2)\) are to be colored green. We may compute the number of ways to do this by first choosing \(k_1\) of the \(n\) elements to paint red, then from the remaining \(n-k_1\) elements choosing \(k_2\) to paint blue, and then painting the remaining \(k_3\) elements green. It is easy to see that the number of ways to do this is \[\begin{aligned}\end{aligned}\] Numbers of this form are called multinomial coefficients; they are an obvious generalization of the binomial coefficients. The general notation is: \[\begin{aligned}\end{aligned}\] \(\binom{n}{k_1,k_2,k_3,\dots,k_r}\) multinomial coefficient

For example, \[\begin{aligned}\end{aligned}\]

Note that there is some overkill in this notation, since the value of \(k_r\) is determined by \(n\) and the values for \(k_1\), \(k_2,\dots,k_{r-1}\). For example, with the ordinary binomial coefficients, we just write \(\binom{8}{3}\) and not \(\binom{8}{3,5}\).

Example

How many different rearrangements of the string: \[\begin{aligned}\end{aligned}\] are possible if all letters and characters must be used?

Solution

To answer this question, we note that there are a total of \(45\) characters distributed as follows: 3A's, 1C, 1D, 7E's, 1G, 1H, 4I's, 1K, 5L's, 2M's, 2N's, 1O, 4R's, 2S's, 6T's, 1U, 1W, and 2!'s. So the number of rearrangements is \[\begin{aligned}\end{aligned}\]

Just as with binomial coefficients and the Binomial Theorem, the multinomial coefficients arise in the expansion of powers of a multinomial:

Condensed: the full section is in Keller & Trotter, Applied Combinatorics.

ປັດຈຸບັນ​ທ່ານ ບໍ່ມີ​ເຄື່ອງ​ຄິດໄລ່​ທີ່​ຈະ​ແກ້ໄຂ​ບັນຫາ​ນີ້​ໄດ້, ແຕ່​ສ່ວນ​ຂອງ​ມັນ​ສາມາດ​ຄິດໄລ່​ໄດ້. ພະຍາຍາມ​ອັນ​ໃດ​ອັນ​ໜຶ່ງ​ຂ້າງ​ລຸ່ມນີ້ ຫຼື ພິມ​ຕົວ​ເອງ​ເອງ.

ທົດລອງ (1)

ທົດລອງ​ທຸກ​ຢ່າງ​ກ່ອນ​ໜ້າ​ນີ້​ໃນ​ເຈ້ຍ. ເປີດ​ເຜີຍ​ຄໍາຕອບ​ເພື່ອ​ກວດ​ສອບ; ຄໍາຕອບ​ທີ່​ໄດ້​ຮັບ​ການ​ກວດ​ສອບ​ສາມາດ​ເປີດ​ໃນ​ຕົວ​ແກ້​ໄຂ​ສຳລັບ​ທຸກ​ບາດກ້າວ.

  1. Look again at the trinomial in . What would be the coefficient on \(x^{30}y^{80}z^{10}\) when this is expanded? Explain your reasoning.

ຮັກສາ​ການ​ເຮັດວຽກ​ຂອງ​ທ່ານ​ໄວ້

ບັນຊີຟຣີ ເພີ່ມ​ຂໍ້​ມູນ​ໃສ່​ບົດຮຽນ​ທຸກ​ບົດ, ບັນທຶກ​ຂອງ​ສິ່ງທີ່​ທ່ານ​ໄດ້​ເຮັດ​ແລ້ວ, ບັນຫາ​ທີ່​ທ່ານ​ໄດ້​ແກ້​ໄຂ​ໄວ້​ໃນ​ບ່ອນ​ດຽວ ແລະ ຄູ​ສອນ​ທີ່​ທ່ານ​ສາມາດ​ຖາມ​ກ່ຽວກັບ​ໜ້າ​ນີ້. ຄະນິດສາດ​ເອງ​ແມ່ນ​ເປີດ​ໃຫ້​ທຸກ​ຄົນ, ບໍ່​ວ່າ​ຈະ​ໄດ້​ເຂົ້າ​ສູ່​ລະບົບ ຫຼື ບໍ່.

ລົງທະບຽນ ចូល

ຕົວ​ສະ​ແດງ​ທີ່​ໃຊ້​ຢູ່​ທີ່​ນີ້

ກົດ​ຕົວ​ອັກສອນ​ໃດ​ໜຶ່ງ​ເພື່ອ​ເບິ່ງ​ຄວາມ​ໝາຍ​ເຕັມ, ຮູບ ແລະ ຕົວອັກສອນ​ແຕ່ລະ​ຕົວ​ໃນ​ມັນ​ໝາຍ​ຄວາມ​ວ່າ​ແນວໃດ.

ຄໍາຖາມທີ່ຄົນຖາມ

Permutation or combination?

Ask whether order matters. A lock code is a permutation (order matters); a hand of cards is a combination (it does not).

What is a graph in this sense?

Dots (vertices) joined by lines (edges), not a plot. Road maps, social networks and molecules are graphs; questions like "is there a route" and "how few colours" are graph theory.

ບາງສ່ວນຂອງ ໜ້າ ນີ້ ຖືກປັບແຕ່ງຈາກ Keller & Trotter, Applied Combinatorics (CC BY-SA 4.0). ຖືກ​ປະສົມ​ປະສານ​ແລະ​ອະທິບາຍ​ຄືນ​ໃໝ່​ທີ່​ນີ້; ຄວາມ​ຜິດ​ພາດ​ແມ່ນ​ຂອງ​ເຮົາ.

ເພີ່ມເຕີມໃນ Combinatorics & Graph Theory