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Binomial Coefficients Revisited
The binomial coefficient \binom{n}{k} was originally defined in terms of the factorial notation, and with our recursive definitions of the factorial notation, we also have a complete and legally-correct definition of…
Binomial Coefficients Revisited
The binomial coefficient \(\binom{n}{k}\) was originally defined in terms of the factorial notation, and with our recursive definitions of the factorial notation, we also have a complete and legally-correct definition of binomial coefficients. The following recursive formula provides an efficient computational scheme.
Let \(n\) and \(k\) be integers with \(0\le k\le n\). If \(k=0\) or \(k=n\), set \(\binom{n}{k}=1\). If \(0\lt k\lt n\), set \[\begin{aligned}\end{aligned}\] This recursion has a natural combinatorial interpretation. Both sides count the number of \(k\)-element subsets of \(\{1,2,\dots,n\}\), with the right-hand side first grouping them into those which contain the element\(n\) and then those which don't. The traditional form of displaying this recursion is This pattern is called Pascal's triangle. Other than the \(1\)s at the ends of each row, an entry of the triangle is determined by adding the entry to the left and the entry to the right in the row above.
Xing was intrigued by the fact that he now had two fundamentally different ways to calculate binomial coefficients. One way is to write \(\binom{n}{m}=P(n,m)/m!\) and just carry out the specified arithmetic. The second way is to use the recursion of Pascal's triangle, so that you are just performing additions. So he experimented by writing a computer program to calculate binomial coefficients, using a library that treats big integers as strings. Which of the two ways do you think proved to be faster when \(n\) say was between \(1800\) and \(2000\) and \(m\) was around \(800\)?
Sekarang kau Tiada kalkulator yang dapat menyelesaikan ini, tetapi bahagian-bahagian boleh dikira. Cuba salah satu di bawah, atau taipkan sendiri.
Latihan (1)
Cuba setiap satu di atas kertas dahulu. Tunjukkan jawapan untuk semak; yang disahkan boleh dibuka dalam penyelesai bagi setiap langkah.
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Write a couple of sentences to explain why \(C(n-1,k-1)\) counts the number of \(k\)-element subsets of \(\{1,2,\dots,n\}\) that contain the element \(n\).
Akaun percuma menambah nota pada setiap pengajaran, rekod apa yang anda selesaikan, masalah yang anda selesaikan di satu tempat, dan seorang guru yang anda boleh tanya tentang halaman ini. Matematik itu sendiri terbuka kepada semua orang, sama ada anda log masuk atau tidak.
Daftar Masuk Log masukSimbol yang digunakan di sini
Tekan simbol mana-mana untuk definisi penuh, gambar, dan apa makna setiap huruf dalamnya.
Soalan yang orang tanya
Permutation or combination?
Ask whether order matters. A lock code is a permutation (order matters); a hand of cards is a combination (it does not).
What is a graph in this sense?
Dots (vertices) joined by lines (edges), not a plot. Road maps, social networks and molecules are graphs; questions like "is there a route" and "how few colours" are graph theory.
Bahagian halaman ini diadaptasi dari Keller & Trotter, Applied Combinatorics (CC BY-SA 4.0). Dikemas kini dan dijelaskan di sini; kesilapan adalah kami.
Lebih dalam Combinatorics & Graph Theory
The counting principlesPigeonhole principle and inclusion, exclusionBinomial coefficients and Pascal's triangleRecurrences and generating functionsGraphs: vertices, edges, degreesPaths, cycles, trees, Euler and HamiltonColouring and planar graphs