maths.free › Combinatorics & Graph Theory › The Many Faces of Combinatorics › Applying the Local Lemma

Applying the Local Lemma

The list of applications of the Local Lemma has been growing steadily, as has the interest in how the lemma can be applied algorithmically, , in a constructive setting.

Applying the Local Lemma

The list of applications of the Local Lemma has been growing steadily, as has the interest in how the lemma can be applied algorithmically, , in a constructive setting. But here we present one of the early applications to Ramsey theoryestimating the Ramsey number \((R,3,n)\). Recall that we have the basic inequality \(R(3,n)\le \binom{n+1}{3}\) from , and it is natural to turn to the probabilistic method to look for good lower bounds. But a few minutes thought shows that there are challenges to this approach.

First, let's try a direct computation. Suppose we try a random graph on \(t\) vertices with edge probability \(p\). So we would want no triangles, and that would say we need \(t^3p^3=1\), , \(p=1/t\). Then we would want no independent sets of size \(n\), which would require \(n^te^{-pn^2}=1\), , \(t\ln n=pn^2\), so we can't even make \(t\) larger than \(n\). That's not helpful.

We can do a bit better by allowing some triangles and then removing one point from each, as was done in the proof for . Along these lines, we would set \(t^3p^3=t\), , \(p=t^{-2/3}\). And the calculation now yields the lower bound \(R(3,n)\ge n^{6/5}/\ln^{-3/5} n\), so even the exponent of \(n\) is different from the upper bound.

So which one is right, or is the answer somewhere in between? In a classic 1961 paper, Erdős used a very clever application of the probabilistic method to show the existence of a graph from which a good lower bound could be extracted. His technique yielded the lower bound \(R(3,n)\ge n^2/\ln^2 n\), so the two on the exponent of \(n\) is correct.

Here we will use the Lovász Local Lemma to obtain this same lower bound in a much more direct manner. We consider a random graph on \(t\) vertices with edge probability \(p\). For each \(3\)-element subset \(S\), we have the event \(E_S\) which is true when \(S\) forms a triangle. For each \(n\)-element set \(T\), we have the event \(E_T\) which is true when \(T\) is an independent set. In the discussion to follow, we abuse notation slightly and refer to events \(E_S\) and \(E_T\) as just \(S\) and \(T\), respectively. Note that the probability of \(S\) is \(p^3\) for each \(3\)-element set \(S\), while the probability of \(T\) is \(q=(1-p)^{C(n,2)}\sim e^{-pn^2/2}\) for each \(n\)-element set \(T\).

When we apply the Local Lemma, we will set \(x=x(S)\) to be \(e^2p^3\), for each \(3\)-element set \(S\). And we will set \(y=Y(T)=q^{1/2}\sim e^{-pn^2/4}\). It will be clear in a moment where we got those values.

Condensed: the full section is in Keller & Trotter, Applied Combinatorics.

Jetzt du Kein Rechner löst diese Frage, aber ihre Teile sind berechenbar. Probieren Sie unten eine aus oder geben Sie Ihre eigene ein.

Behalten Sie Ihre eigenen Lösungswege

Ein kostenloses Konto fügt Notizen zu jeder Lektion, eine Aufzeichnung von dem, was Sie beendet haben, Ihre gelösten Probleme an einem Ort, und ein Tutor können Sie über diese Seite fragen. Die Mathematik selbst ist offen für alle, angemeldet oder nicht.

Registrieren Anmelden

Hier verwendete Symbole

Tippen Sie auf jedes Symbol für die vollständige Definition, ein Bild und was jeder Buchstabe darin bedeutet.

Fragen, die die Leute stellen

Permutation or combination?

Ask whether order matters. A lock code is a permutation (order matters); a hand of cards is a combination (it does not).

What is a graph in this sense?

Dots (vertices) joined by lines (edges), not a plot. Road maps, social networks and molecules are graphs; questions like "is there a route" and "how few colours" are graph theory.

Teile dieser Seite sind adaptiert aus Keller & Trotter, Applied Combinatorics (CC BY-SA 4.0). Hier gekürzt und neu erklärt; Fehler gehen auf uns.

Mehr in Combinatorics & Graph Theory