maths.free › Calculus › Related rates and optimisation
Related rates and optimisation
Turning a word problem into a derivative: what is changing, what is fixed, what is extreme.
Related rates differentiate a relation with respect to time; optimisation sets a derivative to zero. Both begin by naming the variables and writing the one equation that ties them. Picture it: the graph of the quantity being optimised; the peak is where the tangent is flat. Think it: Lagrange multipliers extend the same idea to constrained problems in many variables.
Töötatud näide · maximum of -x^2 + 4x
Samm-sammult
- f(x) = - x^{2} + 4 x
Critical points are where f′(x) = 0 or is undefined.
- f'(x) = 4 - 2 x
Differentiate.
- x = 2
Solve f′(x) = 0.
- f''(x) = -2
Second-derivative test: f″ < 0 → maximum, f″ > 0 → minimum.
- f''(2) = -2 \Rightarrow (2, 4) \text{ is a local maximum}
Vastuse avalikustamine
Nüüd sina. Vali probleem, või kirjuta või joonista oma. Iga samm, pilt, vastus peidetud, kuni küsid.
Tasuta konto lisab märkmeid igale õppetunnile, ülestähenduse, oma lahendatud probleemide kohta ühes kohas ja juhendaja kohta, kellelt võid küsida selle lehekülje kohta. Matemaatika ise on avatud kõigile, allkirjastatud või mitte.
Registreeru SisselogimineSiin kasutatavad sümbolid
Koputage kõiki sümboleid, mis on mõeldud täieliku definitsiooni, pildi ja iga tähe all.
Kuidas: Related rates and optimisation
- Critical points are where f′(x) = 0 or is undefined.
- Differentiate.
- Solve f′(x) = 0.
- Second-derivative test: f″ < 0 → maximum, f″ > 0 → minimum.
Küsimusi, mida inimesed küsivad
What is a derivative in one sentence?
The slope of the graph at a point, the rate at which the output is changing there. Speed is the derivative of position.
What is an integral in one sentence?
The accumulated total of a rate: the area under the curve. Distance travelled is the integral of speed.
Why are derivatives and integrals opposites?
That is the fundamental theorem of calculus: accumulating a rate and then measuring how fast the accumulation grows gets you back the rate. Integration undoes differentiation up to a constant.
When do I use substitution and when integration by parts?
Substitution when part of the integrand is the derivative of another part (u and du both present). Parts when the integrand is a product of two unrelated kinds of function, a polynomial times an exponential, log or trig function.
Rohkem Calculus
LimitsDerivativesIntegralsDefinite integralsTaylor seriesSeries and sumsMaxima and minimaThe chain ruleImplicit differentiationIntegration techniques: substitution, parts, partial fractionsApplications of integration: area, volume, arc lengthInfinite series and convergence tests