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Applications of integration: area, volume, arc length
Areas between curves, solids of revolution, average value.
Every application is the same move: slice the quantity into thin pieces whose size you can write, then add them with an integral. Area between curves is ∫(top − bottom); a solid of revolution is ∫π r² dx (discs); arc length is ∫√(1 + f′²). Picture it: the shaded region under the curve is the integral being computed. Think it: this slicing is the Riemann sum, and measure theory is what makes it rigorous.
වැඩ කළ උදාහරණය · integrate pi*(sqrt(x))^2 dx from 0 to 4
පියවරෙන් පියවර
- \int_{0}^{4} \pi x\, dx
First find an antiderivative F, then evaluate F(b) − F(a).
- \int \pi x\, dx = \pi \int x\, dx
Pull the constant \pi out of the integral.
- \int x\, dx = \frac{x^{2}}{2}
Power rule: ∫xⁿ dx = xⁿ⁺¹/(n+1) (n ≠ −1).
- F(4) - F(0) = \left(8 \pi\right) - \left(0\right)
Fundamental theorem of calculus: plug in the limits.
- = 8 \pi \approx 25.133
Simplify.
උත්තරය හෙළි කරන්න
දැන් ඔයා ප් රශ්නයක් තෝරන්න, හෝ වර්ගය හෝ ඔබේම අඳින්න. සෑම පියවරක්, පින්තූරයක්, ඔබ ඉල්ලා තෙක් පිළිතුර සැඟවුණු.
නිදහස් ගිණුමක් සෑම පාඩමක් මත සටහන් එකතු, ඔබ අවසන් කර ඇති දේ වාර්තාවක්, එක් ස්ථානයක ඔබේ විසඳා ගැටළු, හා ඔබ මෙම පිටුව ගැන විමසීමට හැකි ගුරුවරයෙකු. ගණිතය ම සියලු දෙනාට විවෘත වේ, ඇතුලත් හෝ නැත.
ලියාපදිංචි වන්න පිවිසුම්මෙහිදී භාවිත කරන සංකේත
සම්පූර්ණ අර්ථ දැක්වීම සඳහා ඕනෑම සංකේතයක් ටැප්, පින්තූරයක්, සහ එය සෑම අකුරු අදහස් කරන්නේ කුමක්ද.
කොහොමද: Applications of integration: area, volume, arc length
- First find an antiderivative F, then evaluate F(b) − F(a).
- Pull the constant \pi out of the integral.
- Power rule: ∫xⁿ dx = xⁿ⁺¹/(n+1) (n ≠ −1).
- Fundamental theorem of calculus: plug in the limits.
- Simplify.
ජනතාව අහනවා ප්රශ්න
What is a derivative in one sentence?
The slope of the graph at a point, the rate at which the output is changing there. Speed is the derivative of position.
What is an integral in one sentence?
The accumulated total of a rate: the area under the curve. Distance travelled is the integral of speed.
Why are derivatives and integrals opposites?
That is the fundamental theorem of calculus: accumulating a rate and then measuring how fast the accumulation grows gets you back the rate. Integration undoes differentiation up to a constant.
When do I use substitution and when integration by parts?
Substitution when part of the integrand is the derivative of another part (u and du both present). Parts when the integrand is a product of two unrelated kinds of function, a polynomial times an exponential, log or trig function.
තවත් Calculus
LimitsDerivativesIntegralsDefinite integralsTaylor seriesSeries and sumsMaxima and minimaThe chain ruleImplicit differentiationRelated rates and optimisationIntegration techniques: substitution, parts, partial fractionsInfinite series and convergence tests