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Integrate 2·pi·x·(4 - x^2) from 0 to 2

\int_{0}^{2} 2 \pi x \left(4 - x^{2}\right)\, dx

Passo dopo passo

  1. \int_{0}^{2} 2 \pi x \left(4 - x^{2}\right)\, dx

    First find an antiderivative F, then evaluate F(b) − F(a).

  2. \int 2 \pi x \left(4 - x^{2}\right)\, dx = 2 \pi \int x \left(4 - x^{2}\right)\, dx

    Pull the constant 2 \pi out of the integral.

  3. u = x^{2},\quad du = 2 x\, dx

    Substitute u = x^{2}.

  4. \int x \left(4 - x^{2}\right)\, dx = \int 2 - \frac{u}{2}\, d_u

    Rewrite the integral in terms of u.

  5. \int 2 - \frac{u}{2}\, d_u = \int 2\, d_u + \int - \frac{u}{2}\, d_u

    The integral of a sum is the sum of the integrals.

  6. \int 2\, d_u = 2 u

    The integral of a constant c is c·x.

  7. \int - \frac{u}{2}\, d_u = - \frac{1}{2} \int u\, d_u

    Pull the constant - \frac{1}{2} out of the integral.

  8. \int u\, d_u = \frac{u^{2}}{2}

    Power rule: ∫xⁿ dx = xⁿ⁺¹/(n+1) (n ≠ −1).

  9. = - \frac{x^{4}}{4} + 2 x^{2}

    Substitute back u = x^{2}.

  10. F(2) - F(0) = \left(8 \pi\right) - \left(0\right)

    Fundamental theorem of calculus: plug in the limits.

  11. = 8 \pi \approx 25.133

    Simplify.

Rivela la risposta
8 \pi