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Simplify Square Roots
Use the Product Property to simplify square roots
Use the Product Property to Simplify Square Roots
The properties we will use to simplify expressions with square roots are similar to the properties of exponents. We know that \({(ab)}^{m}={a}^{m}{b}^{m}\). The corresponding property of square roots says that \(\sqrt{ab}=\sqrt{a}\cdot \sqrt{b}\).
We use the Product Property of Square Roots to remove all perfect square factors from a radical. We will show how to do this in .
How To Use the Product Property to Simplify a Square Root
Try it.
Simplify: \(\sqrt{50}\).
Solution
Notice in the previous example that the simplified form of \(\sqrt{50}\) is \(5\sqrt{2}\), which is the product of an integer and a square root. We always write the integer in front of the square root.
Example
Try it.
Simplify: \(\sqrt{500}\).
Solution
| \(\sqrt{500}\) | |
| Rewrite the radicand as a product using the largest perfect square factor. | \(\sqrt{100\cdot 5}\) |
| Rewrite the radical as the product of two radicals. | \(\sqrt{100}\cdot \sqrt{5}\) |
| Simplify. | \(10\sqrt{5}\) |
We could use the simplified form \(10\sqrt{5}\) to estimate \(\sqrt{500}\). We know 5 is between 2 and 3, and \(\sqrt{500}\) is \(10\sqrt{5}\). So \(\sqrt{500}\) is between 20 and 30.
The next example is much like the previous examples, but with variables.
Example
Try it.
Simplify: \(\sqrt{{x}^{3}}\).
Solution
| \(\sqrt{{x}^{3}}\) | |
| Rewrite the radicand as a product using the largest perfect square factor. | \(\sqrt{{x}^{2}\cdot x}\) |
| Rewrite the radical as the product of two radicals. | \(\sqrt{{x}^{2}}\cdot \sqrt{x}\) |
| Simplify. | \(x\sqrt{x}\) |
We follow the same procedure when there is a coefficient in the radical, too.
Example
Try it.
Simplify: \(\sqrt{25{y}^{5}.}\)
Solution
| \(\sqrt{25{y}^{5}}\) | |
| Rewrite the radicand as a product using the largest perfect square factor. | \(\sqrt{25{y}^{4}\cdot y}\) |
| Rewrite the radical as the product of two radicals. | \(\sqrt{25{y}^{4}}\cdot \sqrt{y}\) |
| Simplify. | \(5{y}^{2}\sqrt{y}\) |
Condensed: the full section is in OpenStax Elementary Algebra 2e.
Use the Quotient Property to Simplify Square Roots
Whenever you have to simplify a square root, the first step you should take is to determine whether the radicand is a perfect square. A perfect square fraction is a fraction in which both the numerator and the denominator are perfect squares.
Example
Try it.
Simplify: \(\sqrt{\frac{9}{64}}\).
Solution
\(\begin{array}{llll} & & & \ \sqrt{\frac{9}{64}} \\ \text{Since}\ {(\frac{3}{8})}^{2}=\frac{9}{64} & & & \ \frac{3}{8}\end{array}\)
If the numerator and denominator have any common factors, remove them. You may find a perfect square fraction!
Example
Try it.
Simplify: \(\sqrt{\frac{45}{80}}\).
Solution
| \(\sqrt{\frac{45}{80}}\) | |
| Simplify inside the radical first. Rewrite showing the common factors of the numerator and denominator. | \(\sqrt{\frac{5\cdot 9}{5\cdot 16}}\) |
| Simplify the fraction by removing common factors. | \(\sqrt{\frac{9}{16}}\) |
| \(\text{Simplify.}\ {(\frac{3}{4})}^{2}=\frac{9}{16}\) | \(\frac{3}{4}\) |
In the last example, our first step was to simplify the fraction under the radical by removing common factors. In the next example we will use the Quotient Property to simplify under the radical. We divide the like bases by subtracting their exponents, \(\frac{{a}^{m}}{{a}^{n}}={a}^{m-n},a\ne 0\).
Example
Try it.
Simplify: \(\sqrt{\frac{{m}^{6}}{{m}^{4}}}\).
Solution
| \(\sqrt{\frac{{m}^{6}}{{m}^{4}}}\) | |
| Simplify the fraction inside the radical first. | |
| Divide the like bases by subtracting the exponents. | \(\sqrt{{m}^{2}}\) |
| Simplify. | \(m\) |
Example
Try it.
Simplify: \(\sqrt{\frac{48{p}^{7}}{3{p}^{3}}}\).
Solution
| \(\sqrt{\frac{48{p}^{7}}{3{p}^{3}}}\) | |
| Simplify the fraction inside the radical first. | \(\sqrt{16{p}^{4}}\) |
| Simplify. | \(4{p}^{2}\) |
Remember the Quotient to a Power Property? It said we could raise a fraction to a power by raising the numerator and denominator to the power separately.
\[{(\frac{a}{b})}^{m}=\frac{{a}^{m}}{{b}^{m}},b\ne 0\]We can use a similar property to simplify a square root of a fraction. After removing all common factors from the numerator and denominator, if the fraction is not a perfect square we simplify the numerator and denominator separately.
Condensed: the full section is in OpenStax Elementary Algebra 2e.
Key Concepts
- Simplified Square Root \(\sqrt{a}\) is considered simplified if \(a\) has no perfect-square factors.
- Product Property of Square Roots If a, b are non-negative real numbers, then
\[\sqrt{ab}=\sqrt{a}\cdot \sqrt{b}\] - Simplify a Square Root Using the Product Property To simplify a square root using the Product Property:
- Find the largest perfect square factor of the radicand. Rewrite the radicand as a product using the perfect square factor.
- Use the product rule to rewrite the radical as the product of two radicals.
- Simplify the square root of the perfect square.
- Quotient Property of Square Roots If a, b are non-negative real numbers and \(b\ne 0\), then
\[\sqrt{\frac{a}{b}}=\frac{\sqrt{a}}{\sqrt{b}}\] - Simplify a Square Root Using the Quotient Property To simplify a square root using the Quotient Property:
- Simplify the fraction in the radicand, if possible.
- Use the Quotient Rule to rewrite the radical as the quotient of two radicals.
- Simplify the radicals in the numerator and the denominator.
Simplify Square Roots
Use the Product Property to Simplify Square Roots
In the following exercises, simplify.
Try it.
\(\sqrt{27}\)
Solution
\(3\sqrt{3}\)
Try it.
\(\sqrt{80}\)
Try it.
\(\sqrt{125}\)
Solution
\(5\sqrt{5}\)
Try it.
\(\sqrt{96}\)
Try it.
\(\sqrt{200}\)
Solution
\(10\sqrt{2}\)
Try it.
\(\sqrt{147}\)
Try it.
\(\sqrt{450}\)
Solution
\(15\sqrt{2}\)
Try it.
\(\sqrt{252}\)
Try it.
\(\sqrt{800}\)
Solution
\(20\sqrt{2}\)
Try it.
\(\sqrt{288}\)
Try it.
\(\sqrt{675}\)
Solution
\(15\sqrt{3}\)
Try it.
\(\sqrt{1250}\)
Try it.
\(\sqrt{{x}^{7}}\)
Solution
\({x}^{3}\sqrt{x}\)
Try it.
\(\sqrt{{y}^{11}}\)
Try it.
\(\sqrt{{p}^{3}}\)
Solution
\(p\sqrt{p}\)
Try it.
\(\sqrt{{q}^{5}}\)
Try it.
\(\sqrt{{m}^{13}}\)
Solution
\({m}^{6}\sqrt{m}\)
Try it.
\(\sqrt{{n}^{21}}\)
Try it.
\(\sqrt{{r}^{25}}\)
Solution
\({r}^{12}\sqrt{r}\)
Try it.
\(\sqrt{{s}^{33}}\)
Try it.
\(\sqrt{49{n}^{17}}\)
Solution
\(7{n}^{8}\sqrt{n}\)
Try it.
\(\sqrt{25{m}^{9}}\)
Try it.
\(\sqrt{81{r}^{15}}\)
Solution
\(9{r}^{7}\sqrt{r}\)
Try it.
\(\sqrt{100{s}^{19}}\)
Try it.
\(\sqrt{98{m}^{5}}\)
Solution
\(7{m}^{2}\sqrt{2m}\)
Try it.
\(\sqrt{32{n}^{11}}\)
Try it.
\(\sqrt{125{r}^{13}}\)
Solution
\(5{r}^{6}\sqrt{5r}\)
Try it.
\(\sqrt{80{s}^{15}}\)
Try it.
\(\sqrt{200{p}^{13}}\)
Solution
\(10{p}^{6}\sqrt{2p}\)
Try it.
\(\sqrt{128{q}^{3}}\)
Try it.
\(\sqrt{242{m}^{23}}\)
Solution
\(11{m}^{11}\sqrt{2m}\)
Try it.
\(\sqrt{175{n}^{13}}\)
Try it.
\(\sqrt{147{m}^{7}{n}^{11}}\)
Solution
\(7{m}^{3}{n}^{5}\sqrt{3mn}\)
Try it.
\(\sqrt{48{m}^{7}{n}^{5}}\)
Try it.
\(\sqrt{75{r}^{13}{s}^{9}}\)
Solution
\(5{r}^{6}{s}^{4}\sqrt{3rs}\)
Try it.
\(\sqrt{96{r}^{3}{s}^{3}}\)
Try it.
\(\sqrt{300{p}^{9}{q}^{11}}\)
Solution
\(10{p}^{4}{q}^{5}\sqrt{3pq}\)
Try it.
\(\sqrt{192{q}^{3}{r}^{7}}\)
Try it.
\(\sqrt{242{m}^{13}{n}^{21}}\)
Solution
\(11{m}^{6}{n}^{10}\sqrt{2mn}\)
Try it.
\(\sqrt{150{m}^{9}{n}^{3}}\)
Try it.
\(5+\sqrt{12}\)
Solution
\(5+2\sqrt{3}\)
Try it.
\(8+\sqrt{96}\)
Try it.
\(1+\sqrt{45}\)
Solution
\(1+3\sqrt{5}\)
Try it.
\(3+\sqrt{125}\)
Try it.
\(\frac{10-\sqrt{24}}{2}\)
Solution
\(5-\sqrt{6}\)
Try it.
\(\frac{8-\sqrt{80}}{4}\)
Try it.
\(\frac{3+\sqrt{90}}{3}\)
Solution
\(1+\sqrt{10}\)
Try it.
\(\frac{15+\sqrt{75}}{5}\)
Use the Quotient Property to Simplify Square Roots
In the following exercises, simplify.
Try it.
\(\sqrt{\frac{49}{64}}\)
Solution
\(\frac{7}{8}\)
Try it.
\(\sqrt{\frac{100}{36}}\)
Try it.
\(\sqrt{\frac{121}{16}}\)
Solution
\(\frac{11}{4}\)
Try it.
\(\sqrt{\frac{144}{169}}\)
Try it.
\(\sqrt{\frac{72}{98}}\)
Solution
\(\frac{6}{7}\)
Try it.
\(\sqrt{\frac{75}{12}}\)
Try it.
\(\sqrt{\frac{45}{125}}\)
Solution
\(\frac{3}{5}\)
Try it.
\(\sqrt{\frac{300}{243}}\)
Try it.
\(\sqrt{\frac{{x}^{10}}{{x}^{6}}}\)
Solution
\({x}^{2}\)
Try it.
\(\sqrt{\frac{{p}^{20}}{{p}^{10}}}\)
Try it.
\(\sqrt{\frac{{y}^{4}}{{y}^{8}}}\)
Solution
\(\frac{1}{{y}^{2}}\)
Try it.
\(\sqrt{\frac{{q}^{8}}{{q}^{14}}}\)
Try it.
\(\sqrt{\frac{200{x}^{7}}{2{x}^{3}}}\)
Solution
\(10{x}^{2}\)
Try it.
\(\sqrt{\frac{98{y}^{11}}{2{y}^{5}}}\)
Try it.
\(\sqrt{\frac{96{p}^{9}}{6p}}\)
Solution
\(4{p}^{4}\)
Try it.
\(\sqrt{\frac{108{q}^{10}}{3{q}^{2}}}\)
Try it.
\(\sqrt{\frac{36}{35}}\)
Solution
\(\frac{6}{\sqrt{35}}\)
Try it.
\(\sqrt{\frac{144}{65}}\)
Try it.
\(\sqrt{\frac{20}{81}}\)
Solution
\(\frac{2\sqrt{5}}{9}\)
Try it.
\(\sqrt{\frac{21}{196}}\)
Try it.
\(\sqrt{\frac{96{x}^{7}}{121}}\)
Solution
\(\frac{4{x}^{3}\sqrt{6x}}{11}\)
Try it.
\(\sqrt{\frac{108{y}^{4}}{49}}\)
Try it.
\(\sqrt{\frac{300{m}^{5}}{64}}\)
Solution
\(\frac{5{m}^{2}\sqrt{3m}}{4}\)
Try it.
\(\sqrt{\frac{125{n}^{7}}{169}}\)
Try it.
\(\sqrt{\frac{98{r}^{5}}{100}}\)
Solution
\(\frac{7{r}^{2}\sqrt{2r}}{10}\)
Try it.
\(\sqrt{\frac{180{s}^{10}}{144}}\)
Try it.
\(\sqrt{\frac{28{q}^{6}}{225}}\)
Solution
\(\frac{2{q}^{3}\sqrt{7}}{15}\)
Try it.
\(\sqrt{\frac{150{r}^{3}}{256}}\)
Try it.
\(\sqrt{\frac{75{r}^{9}}{{s}^{8}}}\)
Solution
\(\frac{5{r}^{4}\sqrt{3r}}{{s}^{4}}\)
Try it.
\(\sqrt{\frac{72{x}^{5}}{{y}^{6}}}\)
Try it.
\(\sqrt{\frac{28{p}^{7}}{{q}^{2}}}\)
Solution
\(\frac{2{p}^{3}\sqrt{7p}}{q}\)
Try it.
\(\sqrt{\frac{45{r}^{3}}{{s}^{10}}}\)
Try it.
\(\sqrt{\frac{100{x}^{5}}{36{x}^{3}}}\)
Solution
\(\frac{5x}{3}\)
Try it.
\(\sqrt{\frac{49{r}^{12}}{16{r}^{6}}}\)
Try it.
\(\sqrt{\frac{121{p}^{5}}{81{p}^{2}}}\)
Solution
\(\frac{11p\sqrt{p}}{9}\)
Try it.
\(\sqrt{\frac{25{r}^{8}}{64r}}\)
Try it.
\(\sqrt{\frac{32{x}^{5}{y}^{3}}{18{x}^{3}y}}\)
Solution
\(\frac{4xy}{3}\)
Try it.
\(\sqrt{\frac{75{r}^{6}{s}^{8}}{48r{s}^{4}}}\)
Try it.
\(\sqrt{\frac{27{p}^{2}q}{108{p}^{5}{q}^{3}}}\)
Solution
\(\frac{1}{2pq\sqrt{p}}\)
Try it.
\(\sqrt{\frac{50{r}^{5}{s}^{2}}{128{r}^{2}{s}^{5}}}\)
Condensed: the full section is in OpenStax Elementary Algebra 2e.
이제 너 계산기는 이것을 해결하지 않지만, 그 조각은 계산 가능합니다. 아래의 하나를 시도하거나 자신의 것을 입력하십시오.
연습 (40)
먼저 종이에 각각을 시도해 보세요. 확인하기 위해 답을 드러내세요. 확인된 답은 각 단계의 솔버에서 열 수 있습니다.
-
Simplify: \(\frac{80}{176}\).
답을 드러내세요
\(\frac{5}{11}\)
-
Simplify: \(\frac{{n}^{9}}{{n}^{3}}\).
답을 드러내세요
\({n}^{6}\)
-
Simplify: \(\frac{{q}^{4}}{{q}^{12}}\).
답을 드러내세요
\(\frac{1}{{q}^{8}}\)
-
Simplify: \(\sqrt{50}\).
-
Simplify: \(\sqrt{48}\).
답을 드러내세요
\(4\sqrt{3}\)
-
Simplify: \(\sqrt{45}\).
답을 드러내세요
\(3\sqrt{5}\)
-
Simplify: \(\sqrt{500}\).
답을 드러내세요
\(\sqrt{500}\) Rewrite the radicand as a product using the
largest perfect square factor.\(\sqrt{100\cdot 5}\) Rewrite the radical as the product of two radicals. \(\sqrt{100}\cdot \sqrt{5}\) Simplify. \(10\sqrt{5}\) -
Simplify: \(\sqrt{288}\).
답을 드러내세요
\(12\sqrt{2}\)
-
Simplify: \(\sqrt{432}\).
답을 드러내세요
\(12\sqrt{3}\)
-
Simplify: \(\sqrt{{x}^{3}}\).
답을 드러내세요
\(\sqrt{{x}^{3}}\) Rewrite the radicand as a product using the
largest perfect square factor.\(\sqrt{{x}^{2}\cdot x}\) Rewrite the radical as the product of two radicals. \(\sqrt{{x}^{2}}\cdot \sqrt{x}\) Simplify. \(x\sqrt{x}\) -
Simplify: \(\sqrt{{b}^{5}}\).
답을 드러내세요
\({b}^{2}\sqrt{b}\)
-
Simplify: \(\sqrt{{p}^{9}}\).
답을 드러내세요
\({p}^{4}\sqrt{p}\)
-
Simplify: \(\sqrt{25{y}^{5}.}\)
답을 드러내세요
\(\sqrt{25{y}^{5}}\) Rewrite the radicand as a product using the
largest perfect square factor.\(\sqrt{25{y}^{4}\cdot y}\) Rewrite the radical as the product of two radicals. \(\sqrt{25{y}^{4}}\cdot \sqrt{y}\) Simplify. \(5{y}^{2}\sqrt{y}\) -
Simplify: \(\sqrt{16{x}^{7}}\).
답을 드러내세요
\(4{x}^{3}\sqrt{x}\)
-
Simplify: \(\sqrt{49{v}^{9}}\).
답을 드러내세요
\(7{v}^{4}\sqrt{v}\)
-
Simplify: \(\sqrt{72{n}^{7}}\).
답을 드러내세요
\(\sqrt{72{n}^{7}}\) Rewrite the radicand as a product using the
largest perfect square factor.\(\sqrt{36{n}^{6}\cdot 2n}\) Rewrite the radical as the product of two radicals. \(\sqrt{36{n}^{6}}\cdot \sqrt{2n}\) Simplify. \(6{n}^{3}\sqrt{2n}\) -
Simplify: \(\sqrt{32{y}^{5}}\).
답을 드러내세요
\(4{y}^{2}\sqrt{2y}\)
-
Simplify: \(\sqrt{75{a}^{9}}\).
답을 드러내세요
\(5{a}^{4}\sqrt{3a}\)
-
Simplify: \(\sqrt{63{u}^{3}{v}^{5}}\).
답을 드러내세요
\(\sqrt{63{u}^{3}{v}^{5}}\) Rewrite the radicand as a product using the
largest perfect square factor.\(\sqrt{9{u}^{2}{v}^{4}\cdot 7uv}\) Rewrite the radical as the product of two radicals. \(\sqrt{9{u}^{2}{v}^{4}}\cdot \sqrt{7uv}\) Simplify. \(3u{v}^{2}\sqrt{7uv}\) -
Simplify: \(\sqrt{98{a}^{7}{b}^{5}}\).
답을 드러내세요
\(7{a}^{3}{b}^{2}{\sqrt{2ab}}^{}\)
-
Simplify: \(\sqrt{180{m}^{9}{n}^{11}}\).
답을 드러내세요
\(6{m}^{4}{n}^{5}\sqrt{5mn}\)
-
Simplify: \(3+\sqrt{32}\).
답을 드러내세요
\(3+\sqrt{32}\) Rewrite the radicand as a product using the
largest perfect square factor.\(3+\sqrt{16\cdot 2}\) Rewrite the radical as the product of two radicals. \(3+\sqrt{16}\cdot \sqrt{2}\) Simplify. \(3+4\sqrt{2}\) The terms are not like and so we cannot add them. Trying to add an integer and a radical is like trying to add an integer and a variable, they are not like terms!
-
Simplify: \(5+\sqrt{75}\).
답을 드러내세요
\(5+5\sqrt{3}\)
-
Simplify: \(2+\sqrt{98}\).
답을 드러내세요
\(2+7\sqrt{2}\)
-
Simplify: \(\frac{4-\sqrt{48}}{2}\).
답을 드러내세요
\(\frac{4-\sqrt{48}}{2}\) Rewrite the radicand as a product using the
largest perfect square factor.\(\frac{4-\sqrt{16\cdot 3}}{2}\) Rewrite the radical as the product of two radicals. \(\frac{4-\sqrt{16}\cdot \sqrt{3}}{2}\) Simplify. \(\frac{4-4\sqrt{3}}{2}\) Factor the common factor from the numerator. \(\frac{4(1-\sqrt{3})}{2}\) Remove the common factor, 2, from the
numerator and denominator.\(\frac{2\cdot 2(1-\sqrt{3})}{2}\) Simplify. \(2(1-\sqrt{3})\) -
Simplify: \(\frac{10-\sqrt{75}}{5}\).
답을 드러내세요
\(2-\sqrt{3}\)
-
Simplify: \(\frac{6-\sqrt{45}}{3}\).
답을 드러내세요
\(2-\sqrt{5}\)
-
Simplify: \(\sqrt{\frac{9}{64}}\).
답을 드러내세요
\(\begin{array}{llll} & & & \ \sqrt{\frac{9}{64}} \\ \text{Since}\ {(\frac{3}{8})}^{2}=\frac{9}{64} & & & \ \frac{3}{8}\end{array}\)
-
Simplify: \(\sqrt{\frac{25}{16}}\).
답을 드러내세요
\(\frac{5}{4}\)
-
Simplify: \(\sqrt{\frac{49}{81}}\).
답을 드러내세요
\(\frac{7}{9}\)
-
Simplify: \(\sqrt{\frac{45}{80}}\).
답을 드러내세요
\(\sqrt{\frac{45}{80}}\) Simplify inside the radical first. Rewrite
showing the common factors of the
numerator and denominator.\(\sqrt{\frac{5\cdot 9}{5\cdot 16}}\) Simplify the fraction by removing common factors. \(\sqrt{\frac{9}{16}}\) \(\text{Simplify.}\ {(\frac{3}{4})}^{2}=\frac{9}{16}\) \(\frac{3}{4}\) -
Simplify: \(\sqrt{\frac{75}{48}}\).
답을 드러내세요
\(\frac{5}{4}\)
-
Simplify: \(\sqrt{\frac{98}{162}}\).
답을 드러내세요
\(\frac{7}{9}\)
-
Simplify: \(\sqrt{\frac{{m}^{6}}{{m}^{4}}}\).
답을 드러내세요
\(\sqrt{\frac{{m}^{6}}{{m}^{4}}}\) Simplify the fraction inside the radical first. Divide the like bases by subtracting the exponents. \(\sqrt{{m}^{2}}\) Simplify. \(m\) -
Simplify: \(\sqrt{\frac{{a}^{8}}{{a}^{6}}}\).
답을 드러내세요
\(a\)
-
Simplify: \(\sqrt{\frac{{x}^{14}}{{x}^{10}}}\).
답을 드러내세요
\({x}^{2}\)
-
Simplify: \(\sqrt{\frac{48{p}^{7}}{3{p}^{3}}}\).
답을 드러내세요
\(\sqrt{\frac{48{p}^{7}}{3{p}^{3}}}\) Simplify the fraction inside the radical first. \(\sqrt{16{p}^{4}}\) Simplify. \(4{p}^{2}\) -
Simplify: \(\sqrt{\frac{75{x}^{5}}{3x}}\).
답을 드러내세요
\(5{x}^{2}\)
-
Simplify: \(\sqrt{\frac{72{z}^{12}}{2{z}^{10}}}\).
답을 드러내세요
\(6z\)
-
Simplify: \(\sqrt{\frac{21}{64}}\).
답을 드러내세요
\(\sqrt{\frac{21}{64}}\) We cannot simplify the fraction inside the
radical. Rewrite using the quotient property.\(\frac{\sqrt{21}}{\sqrt{64}}\) Simplify the square root of 64. The
numerator cannot be simplified.\(\frac{\sqrt{21}}{8}\)
여기서 사용된 기호
기호를 탭하면 전체 정의, 이미지 및 각 문자의 의미를 확인할 수 있습니다.
어떻게: Simplify Square Roots
- Use the Product Property to simplify square roots
- Use the Quotient Property to simplify square roots
- Find the largest perfect square factor of the radicand. Rewrite the radicand as a product using the perfect-square factor.
- Use the product rule to rewrite the radical as the product of two radicals.
- Simplify the square root of the perfect square.
- Simplify the fraction in the radicand, if possible.
- Use the Quotient Property to rewrite the radical as the quotient of two radicals.
- Simplify the radicals in the numerator and the denominator.
사람들이 묻는 질문
What does it mean to solve an equation?
To find every value of the unknown that makes both sides equal. Each step is an operation applied to both sides that keeps the solution set the same, until the unknown stands alone.
Why do I sometimes get two answers?
A quadratic can cross the axis twice, so it can have two solutions. A degree-n polynomial has up to n. The graph shows where each one comes from.
How do I know whether to factor or use the quadratic formula?
Try factoring for a few seconds: look for two numbers that multiply to a·c and add to b. If nothing obvious appears, the discriminant b² − 4ac tells you how many real roots there are, and the formula finds them without guessing.
이 페이지의 일부는 다음에서 변경되었습니다. OpenStax Elementary Algebra 2e (CC BY-NC-SA 4.0). 여기서 압축하고 다시 설명; 오류는 우리의. 소스가 비상업적 사용을 위해 라이선스되어 있기 때문에, 이 레슨은 무료이며, 아무것도 판매하지 않으며, 동일한 라이선스로 공유됩니다.
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