maths.free › Algebra › Roots and Radicals › Divide Square Roots
Divide Square Roots
Divide square roots
Divide Square Roots
We know that we simplify fractions by removing factors common to the numerator and the denominator. When we have a fraction with a square root in the numerator, we first simplify the square root. Then we can look for common factors.
Example
Try it.
Simplify: \(\frac{\sqrt{54}}{6}\).
Solution
| \(\frac{\sqrt{54}}{6}\) | |
| Simplify the radical. | \(\frac{\sqrt{9}\cdot \sqrt{6}}{6}\) |
| Simplify. | \(\frac{3\sqrt{6}}{6}\) |
| Remove the common factors. | \(\frac{3\sqrt{6}}{3\cdot 2}\) |
| Simplify. | \(\frac{\sqrt{6}}{2}\) |
Example
Try it.
Simplify: \(\frac{6-\sqrt{24}}{12}\).
Solution
| \(\frac{6-\sqrt{24}}{12}\) | |
| Simplify the radical. | \(\frac{6-\sqrt{4}\cdot \sqrt{6}}{12}\) |
| Simplify. | \(\frac{6-2\sqrt{6}}{12}\) |
| Factor the common factor from the numerator. | \(\frac{2(3-\sqrt{6})}{2\cdot 6}\) |
| Remove the common factors. | \(\frac{2(3-\sqrt{6})}{2\cdot 6}\) |
| Simplify. | \(\frac{3-\sqrt{6}}{6}\) |
We have used the Quotient Property of Square Roots to simplify square roots of fractions. The Quotient Property of Square Roots says
\[\sqrt{\frac{a}{b}}=\frac{\sqrt{a}}{\sqrt{b}},b\ne 0\]Sometimes we will need to use the Quotient Property of Square Roots ‘in reverse’ to simplify a fraction with square roots.
\[\frac{\sqrt{a}}{\sqrt{b}}=\sqrt{\frac{a}{b}},b\ne 0\]We will rewrite the Quotient Property of Square Roots so we see both ways together. Remember: we assume all variables are greater than or equal to zero so that their square roots are real numbers.
We will use the Quotient Property of Square Roots ‘in reverse’ when the fraction we start with is the quotient of two square roots, and neither radicand is a perfect square. When we write the fraction in a single square root, we may find common factors in the numerator and denominator.
Example
Try it.
Simplify: \(\frac{\sqrt{27}}{\sqrt{75}}\).
Solution
| \(\frac{\sqrt{27}}{\sqrt{75}}\) | |
| Neither radicand is a perfect square, so rewrite using the quotient property of square roots. | \(\sqrt{\frac{27}{75}}\) |
| Remove common factors in the numerator and denominator. | \(\sqrt{\frac{3\cdot 9}{3\cdot 25}}\) |
| Simplify. | \(\sqrt{\frac{9}{25}}\) |
| \(\frac{3}{5}\) |
Condensed: the full section is in OpenStax Elementary Algebra 2e.
Rationalize a One Term Denominator
Before the calculator became a tool of everyday life, tables of square roots were used to find approximate values of square roots. shows a portion of a table of squares and square roots. Square roots are approximated to five decimal places in this table.
If someone needed to approximate a fraction with a square root in the denominator, it meant doing long division with a five decimal-place divisor. This was a very cumbersome process.
For this reason, a process called rationalizing the denominator was developed. A fraction with a radical in the denominator is converted to an equivalent fraction whose denominator is an integer. This process is still used today and is useful in other areas of mathematics, too.
Square roots of numbers that are not perfect squares are irrational numbers. When we rationalize the denominator, we write an equivalent fraction with a rational number in the denominator.
Let’s look at a numerical example.
\(\begin{array}{llll}\text{Suppose we need an approximate value for the fraction.} & & & \frac{1}{\sqrt{2}} \\ \text{A five decimal place approximation to}\ \sqrt{2}\ \text{is}\ 1.41421. & & & \frac{1}{1.41421} \\ \text{Without a calculator, would you want to do this division?} & & & 1.414211.0\end{array}\)
But we can find a fraction equivalent to \(\frac{1}{\sqrt{2}}\) by multiplying the numerator and denominator by \(\sqrt{2}\).
Example
Try it.
Simplify: \(\frac{4}{\sqrt{3}}\).
Solution
To rationalize a denominator, we can multiply a square root by itself. To keep the fraction equivalent, we multiply both the numerator and denominator by the same factor.
| \(\frac{4}{\sqrt{3}}\) | |
| Multiply both the numerator and denominator by \(\sqrt{3}.\) | \(\frac{4\cdot \sqrt{3}}{\sqrt{3}\cdot \sqrt{3}}\) |
| Simplify. | \(\frac{4\sqrt{3}}{3}\) |
Example
Try it.
Simplify: \(-\frac{8}{3\sqrt{6}}\).
Solution
To remove the square root from the denominator, we multiply it by itself. To keep the fractions equivalent, we multiply both the numerator and denominator by \(\sqrt{6}\).
| Multiply both the numerator and the denominator by \(\sqrt{6}\). | |
| Simplify. | |
| Remove common factors. | |
| Simplify. |
Condensed: the full section is in OpenStax Elementary Algebra 2e.
Rationalize a Two-Term Denominator
When the denominator of a fraction is a sum or difference with square roots, we use the Product of Conjugates pattern to rationalize the denominator.
\[\begin{array}{llll}(a-b)(a+b) & & & \ (2-\sqrt{5})(2+\sqrt{5}) \\ {a}^{2}-{b}^{2} & & & \ {2}^{2}-{(\sqrt{5})}^{2} \\ & & & \ 4-5 \\ & & & \ -1\end{array}\]When we multiply a binomial that includes a square root by its conjugate, the product has no square roots.
Example
Try it.
Simplify: \(\frac{4}{4+\sqrt{2}}\).
Solution
| Multiply the numerator and denominator by the conjugate of the denominator. | |
| Multiply the conjugates in the denominator. | |
| Simplify the denominator. | |
| Simplify the denominator. | |
| Remove common factors from the numerator and denominator. | |
| We leave the numerator in factored form to make it easier to look for common factors after we have simplified the denominator. |
Example
Try it.
Simplify: \(\frac{5}{2-\sqrt{3}}\).
Solution
| Multiply the numerator and denominator by the conjugate of the denominator. | |
| Multiply the conjugates in the denominator. | |
| Simplify the denominator. | |
| Simplify the denominator. | |
| Simplify. |
Example
Try it.
Simplify: \(\frac{\sqrt{3}}{\sqrt{u}-\sqrt{6}}\).
Solution
| Multiply the numerator and denominator by the conjugate of the denominator. | |
| Multiply the conjugates in the denominator. | |
| Simplify the denominator. |
Example
Try it.
Simplify: \(\frac{\sqrt{x}+\sqrt{7}}{\sqrt{x}-\sqrt{7}}\).
Solution
| Multiply the numerator and denominator by the conjugate of the denominator. | |
| Multiply the conjugates in the denominator. | |
| Simplify the denominator. | |
| We do not square the numerator. In factored form, we can see there are no common factors to remove from the numerator and denominator. |
Key Concepts
- Quotient Property of Square Roots
- If a, b are non-negative real numbers and \(b\ne 0\), then \[\sqrt{\frac{a}{b}}=\frac{\sqrt{a}}{\sqrt{b}}\ \text{and}\ \frac{\sqrt{a}}{\sqrt{b}}=\sqrt{\frac{a}{b}}\]
- Simplified Square Roots
A square root is considered simplified if there are- no perfect square factors in the radicand
- no fractions in the radicand
- no square roots in the denominator of a fraction
Divide Square Roots
Divide Square Roots
In the following exercises, simplify.
Try it.
\(\frac{\sqrt{27}}{6}\)
Solution
\(\frac{\sqrt{3}}{2}\)
Try it.
\(\frac{\sqrt{50}}{10}\)
Try it.
\(\frac{\sqrt{72}}{9}\)
Solution
\(\frac{2\sqrt{2}}{3}\)
Try it.
\(\frac{\sqrt{243}}{6}\)
Try it.
\(\frac{2-\sqrt{32}}{8}\)
Solution
\(\frac{1-2\sqrt{2}}{4}\)
Try it.
\(\frac{3+\sqrt{27}}{9}\)
Try it.
\(\frac{6+\sqrt{45}}{6}\)
Solution
\(\frac{2+\sqrt{5}}{2}\)
Try it.
\(\frac{10-\sqrt{200}}{20}\)
Try it.
\(\frac{\sqrt{80}}{\sqrt{125}}\)
Solution
\(\frac{4}{5}\)
Try it.
\(\frac{\sqrt{72}}{\sqrt{200}}\)
Try it.
\(\frac{\sqrt{128}}{\sqrt{72}}\)
Solution
\(\frac{4}{3}\)
Try it.
\(\frac{\sqrt{48}}{\sqrt{75}}\)
Try it.
ⓐ \(\frac{\sqrt{8{x}^{6}}}{\sqrt{2{x}^{2}}}\) ⓑ \(\frac{\sqrt{200{m}^{5}}}{\sqrt{98m}}\)
Solution
ⓐ \(2{x}^{2}\) ⓑ \(\frac{10{m}^{2}}{7}\)
Try it.
ⓐ \(\frac{\sqrt{10{y}^{3}}}{\sqrt{5y}}\) ⓑ \(\frac{\sqrt{108{n}^{7}}}{\sqrt{243{n}^{3}}}\)
Try it.
\(\frac{\sqrt{75{r}^{3}}}{\sqrt{108r}}\)
Solution
\(\frac{5r}{6}\)
Try it.
\(\frac{\sqrt{196{q}^{5}}}{\sqrt{484q}}\)
Try it.
\(\frac{\sqrt{108{p}^{5}{q}^{2}}}{\sqrt{3{p}^{3}{q}^{6}}}\)
Solution
\(\frac{6p\sqrt{102}}{{q}^{2}}\)
Try it.
\(\frac{\sqrt{98r{s}^{10}}}{\sqrt{2{r}^{3}{s}^{4}}}\)
Try it.
\(\frac{\sqrt{320m{n}^{5}}}{\sqrt{45{m}^{7}{n}^{3}}}\)
Solution
\(\frac{8n}{3{m}^{3}}\)
Try it.
\(\frac{\sqrt{810{c}^{3}{d}^{7}}}{\sqrt{1000{c}^{5}d}}\)
Try it.
\(\frac{\sqrt{98}}{14}\)
Solution
\(\frac{\sqrt{2}}{2}\)
Try it.
\(\frac{\sqrt{72}}{18}\)
Try it.
\(\frac{5+\sqrt{125}}{15}\)
Solution
\(\frac{1+\sqrt{5}}{3}\)
Try it.
\(\frac{6-\sqrt{45}}{12}\)
Try it.
\(\frac{\sqrt{96}}{\sqrt{150}}\)
Solution
\(\frac{4}{5}\)
Try it.
\(\frac{\sqrt{28}}{\sqrt{63}}\)
Try it.
\(\frac{\sqrt{26{y}^{7}}}{\sqrt{2y}}\)
Solution
\({y}^{3}\sqrt{13}\)
Try it.
\(\frac{\sqrt{15{x}^{3}}}{\sqrt{3x}}\)
Rationalize a One-Term Denominator
In the following exercises, simplify and rationalize the denominator.
Try it.
\(\frac{10}{\sqrt{6}}\)
Solution
\(\frac{5\sqrt{6}}{3}\)
Try it.
\(\frac{8}{\sqrt{3}}\)
Try it.
\(\frac{6}{\sqrt{7}}\)
Solution
\(\frac{6\sqrt{7}}{7}\)
Try it.
\(\frac{4}{\sqrt{5}}\)
Try it.
\(\frac{3}{\sqrt{13}}\)
Solution
\(\frac{3\sqrt{13}}{13}\)
Try it.
\(\frac{10}{\sqrt{11}}\)
Try it.
\(\frac{10}{3\sqrt{10}}\)
Solution
\(\frac{\sqrt{10}}{3}\)
Try it.
\(\frac{2}{5\sqrt{2}}\)
Try it.
\(\frac{4}{9\sqrt{5}}\)
Solution
\(\frac{4\sqrt{5}}{45}\)
Try it.
\(\frac{9}{2\sqrt{7}}\)
Try it.
\(-\frac{9}{2\sqrt{3}}\)
Solution
\(-\frac{3\sqrt{3}}{2}\)
Try it.
\(-\frac{8}{3\sqrt{6}}\)
Try it.
\(\sqrt{\frac{3}{20}}\)
Solution
\(\frac{\sqrt{15}}{10}\)
Try it.
\(\sqrt{\frac{4}{27}}\)
Try it.
\(\sqrt{\frac{7}{40}}\)
Solution
\(\frac{\sqrt{70}}{20}\)
Try it.
\(\sqrt{\frac{8}{45}}\)
Try it.
\(\sqrt{\frac{19}{175}}\)
Solution
\(\frac{\sqrt{133}}{35}\)
Try it.
\(\sqrt{\frac{17}{192}}\)
Rationalize a Two-Term Denominator
In the following exercises, simplify by rationalizing the denominator.
Try it.
ⓐ \(\frac{3}{3+\sqrt{11}}\) ⓑ \(\frac{8}{1-\sqrt{5}}\)
Solution
ⓐ \(\frac{3(3-\sqrt{11})}{-2}\) ⓑ \(-2(1+\sqrt{5})\)
Try it.
ⓐ \(\frac{4}{4+\sqrt{7}}\) ⓑ \(\frac{7}{2-\sqrt{6}}\)
Try it.
ⓐ \(\frac{5}{5+\sqrt{6}}\) ⓑ \(\frac{6}{3-\sqrt{7}}\)
Solution
ⓐ \(\frac{5(5-\sqrt{6})}{19}\) ⓑ \(3(3+\sqrt{7})\)
Try it.
ⓐ \(\frac{6}{6+\sqrt{5}}\) ⓑ \(\frac{5}{4-\sqrt{11}}\)
Try it.
\(\frac{\sqrt{3}}{\sqrt{m}-\sqrt{5}}\)
Solution
\(\frac{\sqrt{3}(\sqrt{m}+\sqrt{5})}{m-5}\)
Try it.
\(\frac{\sqrt{5}}{\sqrt{n}-\sqrt{7}}\)
Try it.
\(\frac{\sqrt{2}}{\sqrt{x}-\sqrt{6}}\)
Solution
\(\frac{\sqrt{2}(\sqrt{x}+\sqrt{6})}{x-6}\)
Try it.
\(\frac{\sqrt{7}}{\sqrt{y}+\sqrt{3}}\)
Try it.
\(\frac{\sqrt{r}+\sqrt{5}}{\sqrt{r}-\sqrt{5}}\)
Solution
\({\frac{(\sqrt{r}+\sqrt{5})}{r-5}}^{2}\)
Try it.
\(\frac{\sqrt{s}-\sqrt{6}}{\sqrt{s}+\sqrt{6}}\)
Try it.
\(\frac{\sqrt{150{x}^{2}{y}^{6}}}{\sqrt{6{x}^{4}{y}^{2}}}\)
Solution
\(\frac{5{y}^{2}}{x}\)
Try it.
\(\frac{\sqrt{80{p}^{3}q}}{\sqrt{5p{q}^{5}}}\)
Try it.
\(\frac{15}{\sqrt{5}}\)
Solution
\(3\sqrt{5}\)
Try it.
\(\frac{3}{5\sqrt{8}}\)
Try it.
\(\sqrt{\frac{8}{54}}\)
Solution
\(\frac{2\sqrt{3}}{9}\)
Try it.
\(\sqrt{\frac{12}{20}}\)
Try it.
\(\frac{3}{5+\sqrt{5}}\)
Solution
\(\frac{3(5-\sqrt{5})}{20}\)
Try it.
\(\frac{20}{4-\sqrt{3}}\)
Try it.
\(\frac{\sqrt{2}}{\sqrt{x}-\sqrt{3}}\)
Solution
\(\frac{\sqrt{2}(\sqrt{x}+\sqrt{3})}{x-3}\)
Try it.
\(\frac{\sqrt{5}}{\sqrt{y}-\sqrt{7}}\)
Try it.
\(\frac{\sqrt{x}+\sqrt{8}}{\sqrt{x}-\sqrt{8}}\)
Solution
\({\frac{(\sqrt{x}+2\sqrt{2})}{x-8}}^{2}\)
Try it.
\(\frac{\sqrt{m}-\sqrt{3}}{\sqrt{m}+\sqrt{3}}\)
Condensed: the full section is in OpenStax Elementary Algebra 2e.
이제 너 계산기는 이것을 해결하지 않지만, 그 조각은 계산 가능합니다. 아래의 하나를 시도하거나 자신의 것을 입력하십시오.
연습 (40)
먼저 종이에 각각을 시도해 보세요. 확인하기 위해 답을 드러내세요. 확인된 답은 각 단계의 솔버에서 열 수 있습니다.
-
Find a fraction equivalent to \(\frac{5}{8}\) with denominator 48.
답을 드러내세요
\(\frac{30}{48}\)
-
Simplify: \({(\sqrt{5})}^{2}\).
답을 드러내세요
\(5\)
-
Multiply: \((7+3x)(7-3x)\).
답을 드러내세요
\(49-9{x}^{2}\)
-
Simplify: \(\frac{\sqrt{54}}{6}\).
답을 드러내세요
\(\frac{\sqrt{54}}{6}\) Simplify the radical. \(\frac{\sqrt{9}\cdot \sqrt{6}}{6}\) Simplify. \(\frac{3\sqrt{6}}{6}\) Remove the common factors. \(\frac{3\sqrt{6}}{3\cdot 2}\) Simplify. \(\frac{\sqrt{6}}{2}\) -
Simplify: \(\frac{\sqrt{32}}{8}\).
답을 드러내세요
\(\frac{\sqrt{2}}{2}\)
-
Simplify: \(\frac{\sqrt{75}}{15}\).
답을 드러내세요
\(\frac{\sqrt{3}}{3}\)
-
Simplify: \(\frac{6-\sqrt{24}}{12}\).
답을 드러내세요
\(\frac{6-\sqrt{24}}{12}\) Simplify the radical. \(\frac{6-\sqrt{4}\cdot \sqrt{6}}{12}\) Simplify. \(\frac{6-2\sqrt{6}}{12}\) Factor the common factor from the numerator. \(\frac{2(3-\sqrt{6})}{2\cdot 6}\) Remove the common factors. \(\frac{2(3-\sqrt{6})}{2\cdot 6}\) Simplify. \(\frac{3-\sqrt{6}}{6}\) -
Simplify: \(\frac{8-\sqrt{40}}{10}\).
답을 드러내세요
\(\frac{4-\sqrt{10}}{5}\)
-
Simplify: \(\frac{10-\sqrt{75}}{20}\).
답을 드러내세요
\(\frac{2-\sqrt{3}}{4}\)
-
Simplify: \(\frac{\sqrt{27}}{\sqrt{75}}\).
답을 드러내세요
\(\frac{\sqrt{27}}{\sqrt{75}}\) Neither radicand is a perfect square, so rewrite using the quotient property of square roots. \(\sqrt{\frac{27}{75}}\) Remove common factors in the numerator and denominator. \(\sqrt{\frac{3\cdot 9}{3\cdot 25}}\) Simplify. \(\sqrt{\frac{9}{25}}\) \(\frac{3}{5}\) -
Simplify: \(\frac{\sqrt{48}}{\sqrt{108}}\).
답을 드러내세요
\(\frac{2}{3}\)
-
Simplify: \(\frac{\sqrt{96}}{\sqrt{54}}\).
답을 드러내세요
\(\frac{4}{3}\)
-
Simplify: \(\frac{\sqrt{6{y}^{5}}}{\sqrt{2y}}\).
답을 드러내세요
\(\frac{\sqrt{6{y}^{5}}}{\sqrt{2y}}\) Neither radicand is a perfect square, so rewrite using the quotient property of square roots. \(\sqrt{\frac{6{y}^{5}}{2y}}\) Remove common factors in the numerator and denominator. \(\sqrt{\frac{2\cdot 3\cdot {y}^{4}\cdot y}{2\cdot y}}\) Simplify. \(\sqrt{3{y}^{4}}\) Simplify the radical. \({y}^{2}\sqrt{3}\) -
Simplify: \(\frac{\sqrt{12{r}^{3}}}{\sqrt{6r}}\).
답을 드러내세요
\(r\sqrt{2}\)
-
Simplify: \(\frac{\sqrt{14{p}^{9}}}{\sqrt{2{p}^{5}}}\).
답을 드러내세요
\({p}^{2}\sqrt{7}\)
-
Simplify: \(\frac{\sqrt{72{x}^{3}}}{\sqrt{162x}}\).
답을 드러내세요
\(\frac{\sqrt{72{x}^{3}}}{\sqrt{162x}}\) Rewrite using the quotient property of square roots. \(\sqrt{\frac{72{x}^{3}}{162x}}\) Remove common factors. \(\sqrt{\frac{18\cdot 4\cdot {x}^{2}\cdot x}{18\cdot 9\cdot x}}\) Simplify. \(\sqrt{\frac{4{x}^{2}}{9}}\) Simplify the radical. \(\frac{2x}{3}\) -
Simplify: \(\frac{\sqrt{50{s}^{3}}}{\sqrt{128s}}\).
답을 드러내세요
\(\frac{5s}{8}\)
-
Simplify: \(\frac{\sqrt{75{q}^{5}}}{\sqrt{108q}}\).
답을 드러내세요
\(\frac{5{q}^{2}}{6}\)
-
Simplify: \(\frac{\sqrt{147a{b}^{8}}}{\sqrt{3{a}^{3}{b}^{4}}}\).
답을 드러내세요
\(\frac{\sqrt{147a{b}^{8}}}{\sqrt{3{a}^{3}{b}^{4}}}\) Rewrite using the quotient property of square roots. \(\sqrt{\frac{147a{b}^{8}}{3{a}^{3}{b}^{4}}}\) Remove common factors. \(\sqrt{\frac{49{b}^{4}}{{a}^{2}}}\) Simplify the radical. \(\frac{7{b}^{2}}{a}\) -
Simplify: \(\frac{\sqrt{162{x}^{10}{y}^{2}}}{\sqrt{2{x}^{6}{y}^{6}}}\).
답을 드러내세요
\(\frac{9{x}^{2}}{{y}^{2}}\)
-
Simplify: \(\frac{\sqrt{300{m}^{3}{n}^{7}}}{\sqrt{3{m}^{5}n}}\).
답을 드러내세요
\(\frac{10{n}^{3}}{m}\)
-
Simplify: \(\frac{4}{\sqrt{3}}\).
답을 드러내세요
To rationalize a denominator, we can multiply a square root by itself. To keep the fraction equivalent, we multiply both the numerator and denominator by the same factor.
\(\frac{4}{\sqrt{3}}\) Multiply both the numerator and denominator by \(\sqrt{3}.\) \(\frac{4\cdot \sqrt{3}}{\sqrt{3}\cdot \sqrt{3}}\) Simplify. \(\frac{4\sqrt{3}}{3}\) -
Simplify: \(\frac{5}{\sqrt{3}}\).
답을 드러내세요
\(\frac{5\sqrt{3}}{3}\)
-
Simplify: \(\frac{6}{\sqrt{5}}\).
답을 드러내세요
\(\frac{6\sqrt{5}}{5}\)
-
Simplify: \(-\frac{8}{3\sqrt{6}}\).
답을 드러내세요
To remove the square root from the denominator, we multiply it by itself. To keep the fractions equivalent, we multiply both the numerator and denominator by \(\sqrt{6}\).
Multiply both the numerator and the denominator by \(\sqrt{6}\). Simplify. Remove common factors. Simplify. -
Simplify: \(\frac{5}{2\sqrt{5}}\).
답을 드러내세요
\(\frac{\sqrt{5}}{2}\)
-
Simplify: \(-\frac{9}{4\sqrt{3}}\).
답을 드러내세요
\(-\frac{3\sqrt{3}}{4}\)
-
Simplify: \(\sqrt{\frac{5}{12}}\).
답을 드러내세요
The fraction is not a perfect square, so rewrite using the
Quotient Property.Simplify the denominator Rationalize the denominator. Simplify. Simplify. -
Simplify: \(\sqrt{\frac{7}{18}}\).
답을 드러내세요
\(\frac{\sqrt{14}}{6}\)
-
Simplify: \(\sqrt{\frac{3}{32}}\).
답을 드러내세요
\(\frac{\sqrt{6}}{8}\)
-
Simplify: \(\sqrt{\frac{11}{28}}\).
답을 드러내세요
Rewrite using the Quotient Property. Simplify the denominator. Rationalize the denominator. Simplify. Simplify. -
Simplify: \(\sqrt{\frac{3}{27}}\).
답을 드러내세요
\(\frac{1}{3}\)
-
Simplify: \(\sqrt{\frac{10}{50}}\).
답을 드러내세요
\(\frac{\sqrt{5}}{5}\)
-
Simplify: \(\frac{4}{4+\sqrt{2}}\).
답을 드러내세요
Multiply the numerator and denominator by the conjugate of the denominator. Multiply the conjugates in the denominator. Simplify the denominator. Simplify the denominator. Remove common factors from the numerator and denominator. We leave the numerator in factored form to make it easier to look for common factors after we have simplified the denominator. -
Simplify: \(\frac{2}{2+\sqrt{3}}\).
답을 드러내세요
\(\frac{2(2-\sqrt{3})}{1}\)
-
Simplify: \(\frac{5}{5+\sqrt{3}}\).
답을 드러내세요
\(\frac{5(5-\sqrt{3})}{22}\)
-
Simplify: \(\frac{5}{2-\sqrt{3}}\).
답을 드러내세요
Multiply the numerator and denominator by the conjugate of the denominator. Multiply the conjugates in the denominator. Simplify the denominator. Simplify the denominator. Simplify. -
Simplify: \(\frac{3}{1-\sqrt{5}}\).
답을 드러내세요
\(-\frac{3(1+\sqrt{5})}{4}\)
-
Simplify: \(\frac{2}{4-\sqrt{6}}\).
답을 드러내세요
\(\frac{4+\sqrt{6}}{5}\)
-
Simplify: \(\frac{\sqrt{3}}{\sqrt{u}-\sqrt{6}}\).
답을 드러내세요
Multiply the numerator and denominator by the conjugate of the denominator. Multiply the conjugates in the denominator. Simplify the denominator.
여기서 사용된 기호
기호를 탭하면 전체 정의, 이미지 및 각 문자의 의미를 확인할 수 있습니다.
어떻게: Divide Square Roots
- Divide square roots
- Rationalize a one-term denominator
- Rationalize a two-term denominator
- no perfect-square factors in the radicand
- no fractions in the radicand
- no square roots in the denominator of a fraction
- If
- no perfect square factors in the radicand
사람들이 묻는 질문
What does it mean to solve an equation?
To find every value of the unknown that makes both sides equal. Each step is an operation applied to both sides that keeps the solution set the same, until the unknown stands alone.
Why do I sometimes get two answers?
A quadratic can cross the axis twice, so it can have two solutions. A degree-n polynomial has up to n. The graph shows where each one comes from.
How do I know whether to factor or use the quadratic formula?
Try factoring for a few seconds: look for two numbers that multiply to a·c and add to b. If nothing obvious appears, the discriminant b² − 4ac tells you how many real roots there are, and the formula finds them without guessing.
이 페이지의 일부는 다음에서 변경되었습니다. OpenStax Elementary Algebra 2e (CC BY-NC-SA 4.0). 여기서 압축하고 다시 설명; 오류는 우리의. 소스가 비상업적 사용을 위해 라이선스되어 있기 때문에, 이 레슨은 무료이며, 아무것도 판매하지 않으며, 동일한 라이선스로 공유됩니다.
에 더 Algebra
Linear equationsQuadratic equationsSystems of equationsInequalitiesFactoringExpandingSimplifying expressionsFunctions and graphsExponential and logarithmic equationsPolynomial equationsAbsolute value