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Linear equations

Isolate the unknown by doing the same thing to both sides.

A linear equation has the unknown to the first power only. Solving it is a sequence of legal moves (add, subtract, multiply or divide both sides by the same thing) chosen to leave the unknown alone. The graph shows the line y = 2x + 3 − 7; the solution is where it crosses the axis.

Намунаи коркардашуда · 2x + 3 = 7

Algebra · Linear-Equations

Solve 2x + 3 = 7

2 x + 3 = 7

Қадами ба қадам

  1. 2 x + 3 = 7

    Start from the equation as given.

  2. 2 x - 4 = 0

    Bring everything to one side and collect like terms so the right-hand side is 0.

  3. 2 x = 4

    Move the constant term to the other side: subtract -4 from both sides.

  4. x = \frac{4}{2}

    Divide both sides by 2, the coefficient of x.

  5. x = 2

    Simplify the fraction.

Ҷавоби ҷавобро нишон диҳед
x = 2

Ҳоло шумо Масъаларо интихоб кунед, ё ки онро навишта ё кашед. Ҳар қадам, тасвир, ҷавоб то он даме, ки шумо пурсед, пинҳон мешавад.

Кор кардан

Дар ҳисоби ройгон ба ҳар як дарс қайдҳо илова карда мешаванд, қайди он, ки шумо чӣ кор кардаед, масъалаҳои ҳалшуда дар як ҷо ва муаллиме, ки шумо метавонед дар бораи ин саҳифа пурсед. Математика барои ҳама кушода аст, хоҳ ворид шуда бошад ё на.

Бақайдгирӣ Ворид шудан

Символы, используемые здесь

Барои муайянкунии пурраи маъно, тасвир ва маънои ҳар як ҳарф дар он, ба ҳар як аломат пахш кунед.

Чӣ тавр: Linear equations

  1. Start from the equation as given.
  2. Bring everything to one side and collect like terms so the right-hand side is 0.
  3. Move the constant term to the other side: subtract -4 from both sides.
  4. Divide both sides by 2, the coefficient of x.
  5. Simplify the fraction.

Саволҳои маъмул

What does it mean to solve an equation?

To find every value of the unknown that makes both sides equal. Each step is an operation applied to both sides that keeps the solution set the same, until the unknown stands alone.

Why do I sometimes get two answers?

A quadratic can cross the axis twice, so it can have two solutions. A degree-n polynomial has up to n. The graph shows where each one comes from.

How do I know whether to factor or use the quadratic formula?

Try factoring for a few seconds: look for two numbers that multiply to a·c and add to b. If nothing obvious appears, the discriminant b² − 4ac tells you how many real roots there are, and the formula finds them without guessing.

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