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Divide Square Roots

Divide square roots

Divide Square Roots

We know that we simplify fractions by removing factors common to the numerator and the denominator. When we have a fraction with a square root in the numerator, we first simplify the square root. Then we can look for common factors.

Example

Try it.

Simplify: \(\frac{\sqrt{54}}{6}\).

Solution
\(\frac{\sqrt{54}}{6}\)
Simplify the radical.\(\frac{\sqrt{9}\cdot \sqrt{6}}{6}\)
Simplify.\(\frac{3\sqrt{6}}{6}\)
Remove the common factors.\(\frac{3\sqrt{6}}{3\cdot 2}\)
Simplify.\(\frac{\sqrt{6}}{2}\)
Example

Try it.

Simplify: \(\frac{6-\sqrt{24}}{12}\).

Solution
\(\frac{6-\sqrt{24}}{12}\)
Simplify the radical.\(\frac{6-\sqrt{4}\cdot \sqrt{6}}{12}\)
Simplify.\(\frac{6-2\sqrt{6}}{12}\)
Factor the common factor from the numerator.\(\frac{2(3-\sqrt{6})}{2\cdot 6}\)
Remove the common factors.\(\frac{2(3-\sqrt{6})}{2\cdot 6}\)
Simplify.\(\frac{3-\sqrt{6}}{6}\)

We have used the Quotient Property of Square Roots to simplify square roots of fractions. The Quotient Property of Square Roots says

\[\sqrt{\frac{a}{b}}=\frac{\sqrt{a}}{\sqrt{b}},b\ne 0\]

Sometimes we will need to use the Quotient Property of Square Roots ‘in reverse’ to simplify a fraction with square roots.

\[\frac{\sqrt{a}}{\sqrt{b}}=\sqrt{\frac{a}{b}},b\ne 0\]

We will rewrite the Quotient Property of Square Roots so we see both ways together. Remember: we assume all variables are greater than or equal to zero so that their square roots are real numbers.

We will use the Quotient Property of Square Roots ‘in reverse’ when the fraction we start with is the quotient of two square roots, and neither radicand is a perfect square. When we write the fraction in a single square root, we may find common factors in the numerator and denominator.

Example

Try it.

Simplify: \(\frac{\sqrt{27}}{\sqrt{75}}\).

Solution
\(\frac{\sqrt{27}}{\sqrt{75}}\)
Neither radicand is a perfect square, so rewrite using the quotient property of square roots.\(\sqrt{\frac{27}{75}}\)
Remove common factors in the numerator and denominator.\(\sqrt{\frac{3\cdot 9}{3\cdot 25}}\)
Simplify.\(\sqrt{\frac{9}{25}}\)
\(\frac{3}{5}\)

Condensed: the full section is in OpenStax Elementary Algebra 2e.

Rationalize a One Term Denominator

Before the calculator became a tool of everyday life, tables of square roots were used to find approximate values of square roots. shows a portion of a table of squares and square roots. Square roots are approximated to five decimal places in this table.

If someone needed to approximate a fraction with a square root in the denominator, it meant doing long division with a five decimal-place divisor. This was a very cumbersome process.

For this reason, a process called rationalizing the denominator was developed. A fraction with a radical in the denominator is converted to an equivalent fraction whose denominator is an integer. This process is still used today and is useful in other areas of mathematics, too.

Square roots of numbers that are not perfect squares are irrational numbers. When we rationalize the denominator, we write an equivalent fraction with a rational number in the denominator.

Let’s look at a numerical example.

\(\begin{array}{llll}\text{Suppose we need an approximate value for the fraction.} & & & \frac{1}{\sqrt{2}} \\ \text{A five decimal place approximation to}\ \sqrt{2}\ \text{is}\ 1.41421. & & & \frac{1}{1.41421} \\ \text{Without a calculator, would you want to do this division?} & & & 1.414211.0\end{array}\)

But we can find a fraction equivalent to \(\frac{1}{\sqrt{2}}\) by multiplying the numerator and denominator by \(\sqrt{2}\).

Example

Try it.

Simplify: \(\frac{4}{\sqrt{3}}\).

Solution

To rationalize a denominator, we can multiply a square root by itself. To keep the fraction equivalent, we multiply both the numerator and denominator by the same factor.

\(\frac{4}{\sqrt{3}}\)
Multiply both the numerator and denominator by \(\sqrt{3}.\)\(\frac{4\cdot \sqrt{3}}{\sqrt{3}\cdot \sqrt{3}}\)
Simplify.\(\frac{4\sqrt{3}}{3}\)
Example

Try it.

Simplify: \(-\frac{8}{3\sqrt{6}}\).

Solution

To remove the square root from the denominator, we multiply it by itself. To keep the fractions equivalent, we multiply both the numerator and denominator by \(\sqrt{6}\).

Multiply both the numerator and the denominator by \(\sqrt{6}\).
Simplify.
Remove common factors.
Simplify.

Condensed: the full section is in OpenStax Elementary Algebra 2e.

Rationalize a Two-Term Denominator

When the denominator of a fraction is a sum or difference with square roots, we use the Product of Conjugates pattern to rationalize the denominator.

\[\begin{array}{llll}(a-b)(a+b) & & & \ (2-\sqrt{5})(2+\sqrt{5}) \\ {a}^{2}-{b}^{2} & & & \ {2}^{2}-{(\sqrt{5})}^{2} \\ & & & \ 4-5 \\ & & & \ -1\end{array}\]

When we multiply a binomial that includes a square root by its conjugate, the product has no square roots.

Example

Try it.

Simplify: \(\frac{4}{4+\sqrt{2}}\).

Solution

Multiply the numerator and denominator by the conjugate of the denominator.
Multiply the conjugates in the denominator.
Simplify the denominator.
Simplify the denominator.
Remove common factors from the numerator and denominator.
We leave the numerator in factored form to make it easier to look for common factors after we have simplified the denominator.

Example

Try it.

Simplify: \(\frac{5}{2-\sqrt{3}}\).

Solution

Multiply the numerator and denominator by the conjugate of the denominator.
Multiply the conjugates in the denominator.
Simplify the denominator.
Simplify the denominator.
Simplify.

Example

Try it.

Simplify: \(\frac{\sqrt{3}}{\sqrt{u}-\sqrt{6}}\).

Solution

Multiply the numerator and denominator by the conjugate of the denominator.
Multiply the conjugates in the denominator.
Simplify the denominator.

Example

Try it.

Simplify: \(\frac{\sqrt{x}+\sqrt{7}}{\sqrt{x}-\sqrt{7}}\).

Solution

Multiply the numerator and denominator by the conjugate of the denominator.
Multiply the conjugates in the denominator.
Simplify the denominator.
We do not square the numerator. In factored form, we can see there are no common factors to remove from the numerator and denominator.

Key Concepts

  • Quotient Property of Square Roots
    • If a, b are non-negative real numbers and \(b\ne 0\), then \[\sqrt{\frac{a}{b}}=\frac{\sqrt{a}}{\sqrt{b}}\ \text{and}\ \frac{\sqrt{a}}{\sqrt{b}}=\sqrt{\frac{a}{b}}\]
  • Simplified Square Roots
    A square root is considered simplified if there are
    • no perfect square factors in the radicand
    • no fractions in the radicand
    • no square roots in the denominator of a fraction

Divide Square Roots

Divide Square Roots

In the following exercises, simplify.

Try it.

\(\frac{\sqrt{27}}{6}\)

Solution

\(\frac{\sqrt{3}}{2}\)

Try it.

\(\frac{\sqrt{50}}{10}\)

Try it.

\(\frac{\sqrt{72}}{9}\)

Solution

\(\frac{2\sqrt{2}}{3}\)

Try it.

\(\frac{\sqrt{243}}{6}\)

Try it.

\(\frac{2-\sqrt{32}}{8}\)

Solution

\(\frac{1-2\sqrt{2}}{4}\)

Try it.

\(\frac{3+\sqrt{27}}{9}\)

Try it.

\(\frac{6+\sqrt{45}}{6}\)

Solution

\(\frac{2+\sqrt{5}}{2}\)

Try it.

\(\frac{10-\sqrt{200}}{20}\)

Try it.

\(\frac{\sqrt{80}}{\sqrt{125}}\)

Solution

\(\frac{4}{5}\)

Try it.

\(\frac{\sqrt{72}}{\sqrt{200}}\)

Try it.

\(\frac{\sqrt{128}}{\sqrt{72}}\)

Solution

\(\frac{4}{3}\)

Try it.

\(\frac{\sqrt{48}}{\sqrt{75}}\)

Try it.

ⓐ \(\frac{\sqrt{8{x}^{6}}}{\sqrt{2{x}^{2}}}\) ⓑ \(\frac{\sqrt{200{m}^{5}}}{\sqrt{98m}}\)

Solution

ⓐ \(2{x}^{2}\) ⓑ \(\frac{10{m}^{2}}{7}\)

Try it.

ⓐ \(\frac{\sqrt{10{y}^{3}}}{\sqrt{5y}}\) ⓑ \(\frac{\sqrt{108{n}^{7}}}{\sqrt{243{n}^{3}}}\)

Try it.

\(\frac{\sqrt{75{r}^{3}}}{\sqrt{108r}}\)

Solution

\(\frac{5r}{6}\)

Try it.

\(\frac{\sqrt{196{q}^{5}}}{\sqrt{484q}}\)

Try it.

\(\frac{\sqrt{108{p}^{5}{q}^{2}}}{\sqrt{3{p}^{3}{q}^{6}}}\)

Solution

\(\frac{6p\sqrt{102}}{{q}^{2}}\)

Try it.

\(\frac{\sqrt{98r{s}^{10}}}{\sqrt{2{r}^{3}{s}^{4}}}\)

Try it.

\(\frac{\sqrt{320m{n}^{5}}}{\sqrt{45{m}^{7}{n}^{3}}}\)

Solution

\(\frac{8n}{3{m}^{3}}\)

Try it.

\(\frac{\sqrt{810{c}^{3}{d}^{7}}}{\sqrt{1000{c}^{5}d}}\)

Try it.

\(\frac{\sqrt{98}}{14}\)

Solution

\(\frac{\sqrt{2}}{2}\)

Try it.

\(\frac{\sqrt{72}}{18}\)

Try it.

\(\frac{5+\sqrt{125}}{15}\)

Solution

\(\frac{1+\sqrt{5}}{3}\)

Try it.

\(\frac{6-\sqrt{45}}{12}\)

Try it.

\(\frac{\sqrt{96}}{\sqrt{150}}\)

Solution

\(\frac{4}{5}\)

Try it.

\(\frac{\sqrt{28}}{\sqrt{63}}\)

Try it.

\(\frac{\sqrt{26{y}^{7}}}{\sqrt{2y}}\)

Solution

\({y}^{3}\sqrt{13}\)

Try it.

\(\frac{\sqrt{15{x}^{3}}}{\sqrt{3x}}\)

Rationalize a One-Term Denominator

In the following exercises, simplify and rationalize the denominator.

Try it.

\(\frac{10}{\sqrt{6}}\)

Solution

\(\frac{5\sqrt{6}}{3}\)

Try it.

\(\frac{8}{\sqrt{3}}\)

Try it.

\(\frac{6}{\sqrt{7}}\)

Solution

\(\frac{6\sqrt{7}}{7}\)

Try it.

\(\frac{4}{\sqrt{5}}\)

Try it.

\(\frac{3}{\sqrt{13}}\)

Solution

\(\frac{3\sqrt{13}}{13}\)

Try it.

\(\frac{10}{\sqrt{11}}\)

Try it.

\(\frac{10}{3\sqrt{10}}\)

Solution

\(\frac{\sqrt{10}}{3}\)

Try it.

\(\frac{2}{5\sqrt{2}}\)

Try it.

\(\frac{4}{9\sqrt{5}}\)

Solution

\(\frac{4\sqrt{5}}{45}\)

Try it.

\(\frac{9}{2\sqrt{7}}\)

Try it.

\(-\frac{9}{2\sqrt{3}}\)

Solution

\(-\frac{3\sqrt{3}}{2}\)

Try it.

\(-\frac{8}{3\sqrt{6}}\)

Try it.

\(\sqrt{\frac{3}{20}}\)

Solution

\(\frac{\sqrt{15}}{10}\)

Try it.

\(\sqrt{\frac{4}{27}}\)

Try it.

\(\sqrt{\frac{7}{40}}\)

Solution

\(\frac{\sqrt{70}}{20}\)

Try it.

\(\sqrt{\frac{8}{45}}\)

Try it.

\(\sqrt{\frac{19}{175}}\)

Solution

\(\frac{\sqrt{133}}{35}\)

Try it.

\(\sqrt{\frac{17}{192}}\)

Rationalize a Two-Term Denominator

In the following exercises, simplify by rationalizing the denominator.

Try it.

ⓐ \(\frac{3}{3+\sqrt{11}}\) ⓑ \(\frac{8}{1-\sqrt{5}}\)

Solution

ⓐ \(\frac{3(3-\sqrt{11})}{-2}\) ⓑ \(-2(1+\sqrt{5})\)

Try it.

ⓐ \(\frac{4}{4+\sqrt{7}}\) ⓑ \(\frac{7}{2-\sqrt{6}}\)

Try it.

ⓐ \(\frac{5}{5+\sqrt{6}}\) ⓑ \(\frac{6}{3-\sqrt{7}}\)

Solution

ⓐ \(\frac{5(5-\sqrt{6})}{19}\) ⓑ \(3(3+\sqrt{7})\)

Try it.

ⓐ \(\frac{6}{6+\sqrt{5}}\) ⓑ \(\frac{5}{4-\sqrt{11}}\)

Try it.

\(\frac{\sqrt{3}}{\sqrt{m}-\sqrt{5}}\)

Solution

\(\frac{\sqrt{3}(\sqrt{m}+\sqrt{5})}{m-5}\)

Try it.

\(\frac{\sqrt{5}}{\sqrt{n}-\sqrt{7}}\)

Try it.

\(\frac{\sqrt{2}}{\sqrt{x}-\sqrt{6}}\)

Solution

\(\frac{\sqrt{2}(\sqrt{x}+\sqrt{6})}{x-6}\)

Try it.

\(\frac{\sqrt{7}}{\sqrt{y}+\sqrt{3}}\)

Try it.

\(\frac{\sqrt{r}+\sqrt{5}}{\sqrt{r}-\sqrt{5}}\)

Solution

\({\frac{(\sqrt{r}+\sqrt{5})}{r-5}}^{2}\)

Try it.

\(\frac{\sqrt{s}-\sqrt{6}}{\sqrt{s}+\sqrt{6}}\)

Try it.

\(\frac{\sqrt{150{x}^{2}{y}^{6}}}{\sqrt{6{x}^{4}{y}^{2}}}\)

Solution

\(\frac{5{y}^{2}}{x}\)

Try it.

\(\frac{\sqrt{80{p}^{3}q}}{\sqrt{5p{q}^{5}}}\)

Try it.

\(\frac{15}{\sqrt{5}}\)

Solution

\(3\sqrt{5}\)

Try it.

\(\frac{3}{5\sqrt{8}}\)

Try it.

\(\sqrt{\frac{8}{54}}\)

Solution

\(\frac{2\sqrt{3}}{9}\)

Try it.

\(\sqrt{\frac{12}{20}}\)

Try it.

\(\frac{3}{5+\sqrt{5}}\)

Solution

\(\frac{3(5-\sqrt{5})}{20}\)

Try it.

\(\frac{20}{4-\sqrt{3}}\)

Try it.

\(\frac{\sqrt{2}}{\sqrt{x}-\sqrt{3}}\)

Solution

\(\frac{\sqrt{2}(\sqrt{x}+\sqrt{3})}{x-3}\)

Try it.

\(\frac{\sqrt{5}}{\sqrt{y}-\sqrt{7}}\)

Try it.

\(\frac{\sqrt{x}+\sqrt{8}}{\sqrt{x}-\sqrt{8}}\)

Solution

\({\frac{(\sqrt{x}+2\sqrt{2})}{x-8}}^{2}\)

Try it.

\(\frac{\sqrt{m}-\sqrt{3}}{\sqrt{m}+\sqrt{3}}\)

Condensed: the full section is in OpenStax Elementary Algebra 2e.

Энди сизлар Буни ҳисоблаш учун ҳисоблагич керак эмас, лекин унинг қисмлари ҳисоблаш мумкин. Қуйида бирор нарсани синаб кўринг ёки ўзингиз ёзинг.

Машқ (40)

Ҳар бир саволни аввал қоғозда синаб кўринг. Сўнг жавобни текшириш учун кўрсатинг; текширилган жавоблар ҳар бир қадамда ҳал қилувчида очилиши мумкин.

  1. Find a fraction equivalent to \(\frac{5}{8}\) with denominator 48.

    Жавобни кўрсатиш

    \(\frac{30}{48}\)

  2. Simplify: \({(\sqrt{5})}^{2}\).

    Жавобни кўрсатиш

    \(5\)

  3. Multiply: \((7+3x)(7-3x)\).

    Жавобни кўрсатиш

    \(49-9{x}^{2}\)

  4. Simplify: \(\frac{\sqrt{54}}{6}\).

    Жавобни кўрсатиш
    \(\frac{\sqrt{54}}{6}\)
    Simplify the radical.\(\frac{\sqrt{9}\cdot \sqrt{6}}{6}\)
    Simplify.\(\frac{3\sqrt{6}}{6}\)
    Remove the common factors.\(\frac{3\sqrt{6}}{3\cdot 2}\)
    Simplify.\(\frac{\sqrt{6}}{2}\)
  5. Simplify: \(\frac{\sqrt{32}}{8}\).

    Жавобни кўрсатиш

    \(\frac{\sqrt{2}}{2}\)

  6. Simplify: \(\frac{\sqrt{75}}{15}\).

    Жавобни кўрсатиш

    \(\frac{\sqrt{3}}{3}\)

  7. Simplify: \(\frac{6-\sqrt{24}}{12}\).

    Жавобни кўрсатиш
    \(\frac{6-\sqrt{24}}{12}\)
    Simplify the radical.\(\frac{6-\sqrt{4}\cdot \sqrt{6}}{12}\)
    Simplify.\(\frac{6-2\sqrt{6}}{12}\)
    Factor the common factor from the numerator.\(\frac{2(3-\sqrt{6})}{2\cdot 6}\)
    Remove the common factors.\(\frac{2(3-\sqrt{6})}{2\cdot 6}\)
    Simplify.\(\frac{3-\sqrt{6}}{6}\)
  8. Simplify: \(\frac{8-\sqrt{40}}{10}\).

    Жавобни кўрсатиш

    \(\frac{4-\sqrt{10}}{5}\)

  9. Simplify: \(\frac{10-\sqrt{75}}{20}\).

    Жавобни кўрсатиш

    \(\frac{2-\sqrt{3}}{4}\)

  10. Simplify: \(\frac{\sqrt{27}}{\sqrt{75}}\).

    Жавобни кўрсатиш
    \(\frac{\sqrt{27}}{\sqrt{75}}\)
    Neither radicand is a perfect square, so rewrite using the quotient property of square roots.\(\sqrt{\frac{27}{75}}\)
    Remove common factors in the numerator and denominator.\(\sqrt{\frac{3\cdot 9}{3\cdot 25}}\)
    Simplify.\(\sqrt{\frac{9}{25}}\)
    \(\frac{3}{5}\)
  11. Simplify: \(\frac{\sqrt{48}}{\sqrt{108}}\).

    Жавобни кўрсатиш

    \(\frac{2}{3}\)

  12. Simplify: \(\frac{\sqrt{96}}{\sqrt{54}}\).

    Жавобни кўрсатиш

    \(\frac{4}{3}\)

  13. Simplify: \(\frac{\sqrt{6{y}^{5}}}{\sqrt{2y}}\).

    Жавобни кўрсатиш
    \(\frac{\sqrt{6{y}^{5}}}{\sqrt{2y}}\)
    Neither radicand is a perfect square, so rewrite using the quotient property of square roots.\(\sqrt{\frac{6{y}^{5}}{2y}}\)
    Remove common factors in the numerator and denominator.\(\sqrt{\frac{2\cdot 3\cdot {y}^{4}\cdot y}{2\cdot y}}\)
    Simplify.\(\sqrt{3{y}^{4}}\)
    Simplify the radical.\({y}^{2}\sqrt{3}\)
  14. Simplify: \(\frac{\sqrt{12{r}^{3}}}{\sqrt{6r}}\).

    Жавобни кўрсатиш

    \(r\sqrt{2}\)

  15. Simplify: \(\frac{\sqrt{14{p}^{9}}}{\sqrt{2{p}^{5}}}\).

    Жавобни кўрсатиш

    \({p}^{2}\sqrt{7}\)

  16. Simplify: \(\frac{\sqrt{72{x}^{3}}}{\sqrt{162x}}\).

    Жавобни кўрсатиш
    \(\frac{\sqrt{72{x}^{3}}}{\sqrt{162x}}\)
    Rewrite using the quotient property of square roots.\(\sqrt{\frac{72{x}^{3}}{162x}}\)
    Remove common factors.\(\sqrt{\frac{18\cdot 4\cdot {x}^{2}\cdot x}{18\cdot 9\cdot x}}\)
    Simplify.\(\sqrt{\frac{4{x}^{2}}{9}}\)
    Simplify the radical.\(\frac{2x}{3}\)
  17. Simplify: \(\frac{\sqrt{50{s}^{3}}}{\sqrt{128s}}\).

    Жавобни кўрсатиш

    \(\frac{5s}{8}\)

  18. Simplify: \(\frac{\sqrt{75{q}^{5}}}{\sqrt{108q}}\).

    Жавобни кўрсатиш

    \(\frac{5{q}^{2}}{6}\)

  19. Simplify: \(\frac{\sqrt{147a{b}^{8}}}{\sqrt{3{a}^{3}{b}^{4}}}\).

    Жавобни кўрсатиш
    \(\frac{\sqrt{147a{b}^{8}}}{\sqrt{3{a}^{3}{b}^{4}}}\)
    Rewrite using the quotient property of square roots.\(\sqrt{\frac{147a{b}^{8}}{3{a}^{3}{b}^{4}}}\)
    Remove common factors.\(\sqrt{\frac{49{b}^{4}}{{a}^{2}}}\)
    Simplify the radical.\(\frac{7{b}^{2}}{a}\)
  20. Simplify: \(\frac{\sqrt{162{x}^{10}{y}^{2}}}{\sqrt{2{x}^{6}{y}^{6}}}\).

    Жавобни кўрсатиш

    \(\frac{9{x}^{2}}{{y}^{2}}\)

  21. Simplify: \(\frac{\sqrt{300{m}^{3}{n}^{7}}}{\sqrt{3{m}^{5}n}}\).

    Жавобни кўрсатиш

    \(\frac{10{n}^{3}}{m}\)

  22. Simplify: \(\frac{4}{\sqrt{3}}\).

    Жавобни кўрсатиш

    To rationalize a denominator, we can multiply a square root by itself. To keep the fraction equivalent, we multiply both the numerator and denominator by the same factor.

    \(\frac{4}{\sqrt{3}}\)
    Multiply both the numerator and denominator by \(\sqrt{3}.\)\(\frac{4\cdot \sqrt{3}}{\sqrt{3}\cdot \sqrt{3}}\)
    Simplify.\(\frac{4\sqrt{3}}{3}\)
  23. Simplify: \(\frac{5}{\sqrt{3}}\).

    Жавобни кўрсатиш

    \(\frac{5\sqrt{3}}{3}\)

  24. Simplify: \(\frac{6}{\sqrt{5}}\).

    Жавобни кўрсатиш

    \(\frac{6\sqrt{5}}{5}\)

  25. Simplify: \(-\frac{8}{3\sqrt{6}}\).

    Жавобни кўрсатиш

    To remove the square root from the denominator, we multiply it by itself. To keep the fractions equivalent, we multiply both the numerator and denominator by \(\sqrt{6}\).

    Multiply both the numerator and the denominator by \(\sqrt{6}\).
    Simplify.
    Remove common factors.
    Simplify.
  26. Simplify: \(\frac{5}{2\sqrt{5}}\).

    Жавобни кўрсатиш

    \(\frac{\sqrt{5}}{2}\)

  27. Simplify: \(-\frac{9}{4\sqrt{3}}\).

    Жавобни кўрсатиш

    \(-\frac{3\sqrt{3}}{4}\)

  28. Simplify: \(\sqrt{\frac{5}{12}}\).

    Жавобни кўрсатиш

    The fraction is not a perfect square, so rewrite using the
    Quotient Property.
    Simplify the denominator
    Rationalize the denominator.
    Simplify.
    Simplify.

  29. Simplify: \(\sqrt{\frac{7}{18}}\).

    Жавобни кўрсатиш

    \(\frac{\sqrt{14}}{6}\)

  30. Simplify: \(\sqrt{\frac{3}{32}}\).

    Жавобни кўрсатиш

    \(\frac{\sqrt{6}}{8}\)

  31. Simplify: \(\sqrt{\frac{11}{28}}\).

    Жавобни кўрсатиш

    Rewrite using the Quotient Property.
    Simplify the denominator.
    Rationalize the denominator.
    Simplify.
    Simplify.

  32. Simplify: \(\sqrt{\frac{3}{27}}\).

    Жавобни кўрсатиш

    \(\frac{1}{3}\)

  33. Simplify: \(\sqrt{\frac{10}{50}}\).

    Жавобни кўрсатиш

    \(\frac{\sqrt{5}}{5}\)

  34. Simplify: \(\frac{4}{4+\sqrt{2}}\).

    Жавобни кўрсатиш

    Multiply the numerator and denominator by the conjugate of the denominator.
    Multiply the conjugates in the denominator.
    Simplify the denominator.
    Simplify the denominator.
    Remove common factors from the numerator and denominator.
    We leave the numerator in factored form to make it easier to look for common factors after we have simplified the denominator.

  35. Simplify: \(\frac{2}{2+\sqrt{3}}\).

    Жавобни кўрсатиш

    \(\frac{2(2-\sqrt{3})}{1}\)

  36. Simplify: \(\frac{5}{5+\sqrt{3}}\).

    Жавобни кўрсатиш

    \(\frac{5(5-\sqrt{3})}{22}\)

  37. Simplify: \(\frac{5}{2-\sqrt{3}}\).

    Жавобни кўрсатиш

    Multiply the numerator and denominator by the conjugate of the denominator.
    Multiply the conjugates in the denominator.
    Simplify the denominator.
    Simplify the denominator.
    Simplify.

  38. Simplify: \(\frac{3}{1-\sqrt{5}}\).

    Жавобни кўрсатиш

    \(-\frac{3(1+\sqrt{5})}{4}\)

  39. Simplify: \(\frac{2}{4-\sqrt{6}}\).

    Жавобни кўрсатиш

    \(\frac{4+\sqrt{6}}{5}\)

  40. Simplify: \(\frac{\sqrt{3}}{\sqrt{u}-\sqrt{6}}\).

    Жавобни кўрсатиш

    Multiply the numerator and denominator by the conjugate of the denominator.
    Multiply the conjugates in the denominator.
    Simplify the denominator.

Ўзингиз ишлашда давом этинг

Бепул ҳисоб ҳар бир дарсга ёзув қўшиб беради, сиз тугатган нарсалар ва ҳал қилинган масалалар бир жойда қайд этилади ва сиз бу саҳифа ҳақида устоздан сўрашингиз мумкин. Математика ўзида очиқ бўлиб, унга кириш ёки киришни истамаган ҳар кимга очиқ.

Ройхатдан ўтиш Кириш

Бу ерда қўлланилган белгилар

Барча белгилар учун тўлиқ таъриф, сурат ва ҳар бир ҳарфнинг маъносини кўриш учун белгини босинг.

Қандай: Divide Square Roots

  1. Divide square roots
  2. Rationalize a one-term denominator
  3. Rationalize a two-term denominator
  4. no perfect-square factors in the radicand
  5. no fractions in the radicand
  6. no square roots in the denominator of a fraction
  7. If
  8. no perfect square factors in the radicand

Одамлар сўрайдиган саволлар

What does it mean to solve an equation?

To find every value of the unknown that makes both sides equal. Each step is an operation applied to both sides that keeps the solution set the same, until the unknown stands alone.

Why do I sometimes get two answers?

A quadratic can cross the axis twice, so it can have two solutions. A degree-n polynomial has up to n. The graph shows where each one comes from.

How do I know whether to factor or use the quadratic formula?

Try factoring for a few seconds: look for two numbers that multiply to a·c and add to b. If nothing obvious appears, the discriminant b² − 4ac tells you how many real roots there are, and the formula finds them without guessing.

Бу саҳифанинг қисмлари OpenStax Elementary Algebra 2e (CC BY-NC-SA 4.0). (Ушбу оятда Аллоҳ таоло Пайғамбаримиз Муҳаммадга (с. а. в.) Қуръони Каримни туширишни амр қилмоқда.) Маҳсулот манбаи лицензияси нотижорат мақсадлари учун берилгани учун, бу дарс бепул, ҳеч нарса сотмайди ва шу лицензия асосида тарқатилади.

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