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Graphs of sine, cosine and tangent

Amplitude, period, phase shift and the shape of periodic motion.

y = A sin(Bx + C) + D has amplitude |A|, period 2π/B, phase shift −C/B and midline D. Picture it: the graph is a wave; changing each parameter stretches, squeezes or slides it. Think it: every periodic signal (sound, light, tides) is a sum of such waves (Fourier), so these four parameters describe all of them.

Eżempju maħdum · y = sin(x) + cos(2x)

Graph and analyse sin(x) + cos(2x)

y = \sin{\left(x \right)} + \cos{\left(2 x \right)}

Pass b'pass

  1. \sin{\left(x \right)} + \cos{\left(2 x \right)}

    An expression in x. Here is what it does.

  2. x = - \frac{5 \pi}{6}, x = - \frac{\pi}{6}, x = \frac{\pi}{2}

    Real zeros (where the graph crosses the axis).

  3. \frac{d}{dx} = - 2 \sin{\left(2 x \right)} + \cos{\left(x \right)}

    Derivative (slope).

Jiżvelaw it-tweġiba
\sin{\left(x \right)} + \cos{\left(2 x \right)}

Issa inti Agħżel problema, jew ittajpja jew iġbed tiegħek stess.Kull pass, stampa, it-tweġiba moħbija sakemm inti tistaqsi.

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Kif għandek tuża: Graphs of sine, cosine and tangent

  1. An expression in x. Here is what it does.
  2. Real zeros (where the graph crosses the axis).
  3. Derivative (slope).

Mistoqsijiet li n-nies jistaqsu

Why radians instead of degrees?

A radian is the angle whose arc equals the radius, so it is a pure ratio rather than an arbitrary 1/360 of a turn. With radians the derivative of sin x is exactly cos x; with degrees a factor of π/180 appears everywhere.

Why does sin x = 1/2 have infinitely many solutions?

Sine repeats every full turn, and within one turn it reaches 1/2 twice (at π/6 and 5π/6). Add any whole number of turns to either and it is still true.

How do I remember the exact values?

Two triangles: the 45-45-90 with sides 1, 1, √2 and the 30-60-90 with sides 1, √3, 2. Every value for 30°, 45° and 60° is a ratio of those sides; symmetry gives the rest of the circle.

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