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Sum k^3 for k = 1 to n

\sum_{k=1}^{n} k^{3}

Stap met stap

  1. \sum_{k=1}^{n} k^{3}

    Write the sum out.

  2. 1 + 8 + 27 + 64 + \cdots

    The first few terms.

  3. = \frac{n^{2} \left(n + 1\right)^{2}}{4}

    Closed form (a standard summation formula, provable by induction).

Openbaar die antwoord
\frac{n^{2} \left(n + 1\right)^{2}}{4}