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Geometry · Solids

Pyramid side 4 height 6

Step by step

  1. s = 4,\ h = 6

    Square pyramid.

  2. V = \tfrac{1}{3} s^2 h = 32

    Volume: a third of the box around it.

  3. S = s^2 + 2 s \ell,\ \ell = \sqrt{h^2 + (s/2)^2} = 2 \sqrt{10}

    Surface area = base + four triangles.

Reveal the answer
V = 32,\quad S = 16 + 16 \sqrt{10}