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Limit of (2x^2 + 1)/(x^2 - 3) as x → oo
\lim_{x \to \infty} \frac{2 x^{2} + 1}{x^{2} - 3}
Step by step
- \lim_{x \to \infty^+-} \frac{2 x^{2} + 1}{x^{2} - 3}
Try direct substitution first.
- \
As x grows without bound, compare the fastest-growing terms (or divide top and bottom by the highest power).
- \frac{2 + \frac{1}{x^{2}}}{1 - \frac{3}{x^{2}}}
Divide numerator and denominator by x^2.
- = 2
Take the limit.
Reveal the answer
2