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Integrate sin(x)·sin(2x) from -pi to pi
\int_{- \pi}^{\pi} \sin{\left(x \right)} \sin{\left(2 x \right)}\, dx
चरण द्वारा कदम
- \int_{- \pi}^{\pi} \sin{\left(x \right)} \sin{\left(2 x \right)}\, dx
First find an antiderivative F, then evaluate F(b) − F(a).
- \int 2 \sin^{2}{\left(x \right)} \cos{\left(x \right)}\, dx = 2 \int \sin^{2}{\left(x \right)} \cos{\left(x \right)}\, dx
Pull the constant 2 out of the integral.
- u = \sin{\left(x \right)},\quad du = \cos{\left(x \right)}\, dx
Substitute u = \sin{\left(x \right)}.
- \int \sin^{2}{\left(x \right)} \cos{\left(x \right)}\, dx = \int u^{2}\, d_u
Rewrite the integral in terms of u.
- \int u^{2}\, d_u = \frac{u^{3}}{3}
Power rule: ∫xⁿ dx = xⁿ⁺¹/(n+1) (n ≠ −1).
- = \frac{\sin^{3}{\left(x \right)}}{3}
Substitute back u = \sin{\left(x \right)}.
- F(\pi) - F(- \pi) = \left(0\right) - \left(0\right)
Fundamental theorem of calculus: plug in the limits.
- = 0
Simplify.
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