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Integrate (x^2 + 1)^(-2) from -oo to oo
\int_{-\infty}^{\infty} \frac{1}{\left(x^{2} + 1\right)^{2}}\, dx
चरण द्वारा कदम
- \int_{-\infty}^{\infty} \frac{1}{\left(x^{2} + 1\right)^{2}}\, dx
First find an antiderivative F, then evaluate F(b) − F(a).
- x = \tan{\left(\theta \right)}
Trigonometric substitution.
- \cos^{2}{\left(\theta \right)} = \frac{\cos{\left(2 \theta \right)}}{2} + \frac{1}{2}
Rewrite the integrand into a friendlier form.
- \int \frac{\cos{\left(2 \theta \right)}}{2} + \frac{1}{2}\, d_theta = \int \frac{\cos{\left(2 \theta \right)}}{2}\, d_theta + \int \frac{1}{2}\, d_theta
The integral of a sum is the sum of the integrals.
- \int \frac{\cos{\left(2 \theta \right)}}{2}\, d_theta = \frac{1}{2} \int \cos{\left(2 \theta \right)}\, d_theta
Pull the constant \frac{1}{2} out of the integral.
- u = 2 \theta,\quad du = 2\, d_theta
Substitute u = 2 \theta.
- \int \cos{\left(2 \theta \right)}\, d_theta = \int \frac{\cos{\left(u \right)}}{2}\, d_u
Rewrite the integral in terms of u.
- \int \frac{\cos{\left(u \right)}}{2}\, d_u = \frac{1}{2} \int \cos{\left(u \right)}\, d_u
Pull the constant \frac{1}{2} out of the integral.
- \int \cos{\left(u \right)}\, d_u = \sin{\left(u \right)}
Standard trigonometric antiderivative.
- = \frac{\sin{\left(2 \theta \right)}}{2}
Substitute back u = 2 \theta.
- \int \frac{1}{2}\, d_theta = \frac{\theta}{2}
The integral of a constant c is c·x.
- = \frac{x}{2 \left(x^{2} + 1\right)} + \frac{\operatorname{atan}{\left(x \right)}}{2}
Substitute back.
- F(\infty) - F(-\infty) = \left(\text{NaN}\right) - \left(\text{NaN}\right)
Fundamental theorem of calculus: plug in the limits.
- = \frac{\pi}{2} \approx 1.5708
Simplify.
जवाब दिखाएँ
\frac{\pi}{2}