maths.free › Numerical Methods › Floating point and error

Floating point and error

Why 0.1 + 0.2 ≠ 0.3 on a computer, and how error propagates.

Computers store numbers in binary with ~16 significant digits; 0.1 is not representable exactly. Round-off accumulates, and subtracting nearly equal numbers destroys digits (cancellation). Picture it: 255 in binary is 11111111, and 0.1 in binary never terminates. Think it: a stable algorithm keeps error growth linear; conditioning is a property of the problem, stability of the method.

Mfano wenye matokeo · 0.1 + 0.2

Evaluate 0.1 + 0.2

0.1 + 0.2

Hatua kwa hatua

  1. 0.3 = \frac{3}{10}

    Add: 0.1 + 0.2 = 3/10.

  2. \frac{3}{10} = 0.3

    Simplify.

Lafunua jibu
0.3

Sasa Chagua tatizo, au aina ya barua au uchore.

Keep your own working

Akaunti la bure laongezea mambo makuu juu ya kila somo, rekodi ya yale ambayo umemaliza, matatizo yako ya kutatua katika sehemu moja, na mtunzaji unayeweza kuuliza juu ya ukurasa huu.

Jisajili Login

Ishara zinazotumiwa hapa

Vaa alama yoyote ya ufafanuzi kamili, picha, na maana ya kila herufi.

Jinsi ya Kufaulu: Floating point and error

  1. Add: 0.1 + 0.2 = 3/10.
  2. Simplify.

Maswali ambayo watu huuliza

Why not just solve exactly?

Most equations have no closed-form solution at all, and many that do are unusable in practice. A numerical method delivers as many correct digits as you need, and a good one tells you how many that is.

Why can Newton's method fail?

If it starts where the tangent is nearly flat it shoots far away; near a repeated root it slows to a crawl; and with several roots it may land on the wrong one. A bracketing method like bisection is slower but cannot fail.

Mengi zaidi katika Numerical Methods