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Hindu-Arabic Positional System

Evaluate an exponential expression.

Learning Objectives

After completing this section, you should be able to:

  1. Evaluate an exponential expression.
  2. Convert a Hindu-Arabic numeral to expanded form.
  3. Convert a number in expanded form to a Hindu-Arabic numeral.

Evaluating Exponential Expressions

Most modern numerical systems depend on place values, where the quantity represented depends not only on the digit, but also on where the digit is in the number. The place value is a power of some specific number, which means most numbering systems are actually exponential expressions. An exponential expression is any mathematical expression that includes exponents. So, evaluating such an expression means performing the calculation. In this chapter, we will be using exponents that are positive integer values. Before we do so, let’s remind ourselves about exponents and what they represent. Suppose you want to multiply a number. Let’s label that number \(a\), by itself some number of times. Let’s label the number of times \(b\). We denote that as \({a}^{b}\). We say \(a\), or the base, raised to the \(b\)th power, or the exponent. For example, if we are multiplying 13 by itself eight times, we write \({13}^{8}\) and say 13 to the eighth power.

When computing exponential expressions, we should be careful to remember the order of operations. Using the order of operation rules, calculations inside the parentheses are done first, then exponents are calculated, then multiplication and division calculations are performed, and then addition and subtraction.

Evaluating an Exponential Expression

Try it.

Evaluate the following exponential expressions.

  1. \(4\times {5}^{2}+2\times {6}^{3}\)
  2. \(6\times {8}^{2}+3\times {8}^{1}+4\times {8}^{0}\)
  3. \(3\times {10}^{2}+0\times {10}^{1}+6\times {10}^{0}\)
Solution
  1. To evaluate, or calculate, this expression, we use order of operations, which means the exponents are done first, then multiplications, and then additions. \[4\times {5}^{2}+2\times {6}^{3}=4\times 5\times 5+2\times 6\times 6\times 6=4\times 25+2\times 216=100+432=532\]
  2. To evaluate the expression, we use the order of operations, which means the exponents are done first, then the multiplications, then the additions. Remember that any base raised to the exponent 0 is 1. \[6\times {8}^{2}+3\times {8}^{1}+4\times {8}^{0}=6\times 8\times 8+3\times 8+4\times 1=6\times 64+3\times 8+4\times 1=384+24+4=412\]
  3. To evaluate the expression, we use the order of operations, which means the exponents are done first, then the multiplications, and then the additions. Remember that any base raised to the exponent 0 is 1. \[3\times {10}^{2}+0\times {10}^{1}+6\times {10}^{0}=3\times 100+0\times 10+6\times 1=300+0+6=306\]

Converting Hindu-Arabic Numerals to Expanded Form

When you see the number 738, and you speak the number out loud, what do you say? You probably said “seven hundred thirty-eight” while wondering what point could possibly be made by asking this. What you didn’t say was “seven, and three, and eight.” A pre-K student might say that. Which should make you wonder, why?

The reason is that you’ve been taught place values, or the positions of digits in a number that determine the values of those digits. You know that in a three-digit number, the first digit is hundreds, the second digit is tens, and the last digit is ones. These place values rely on powers of 10, which makes this system a base 10 system.

This sense of place value is what makes our system of numbers so useful. You’ve also been taught the Hindu-Arabic numeration system. This system, which uses the digits 0, 1, 2, 3, 4, 5, 6, 7, 8 and 9, and also employs place value based on powers of 10, is in use today.

Writing a number using these place values is writing them in expanded form. For a number with \(n\) digits, the expanded form is the first digit times 10 raised to one less than \(n\), plus each following digit times 10 raised to one less than the previous power of 10. For example, the number 738 would be written as \(7\times {10}^{2}+3\times {10}^{1}+8\times {10}^{0}\).

What about a four-digit number, like 5,825? Out loud, we’d say five thousand, seven hundred twenty-five. In expanded form, it would be \(5\times {10}^{3}+8\times {10}^{2}+2\times {10}^{1}+5\times {10}^{0}\). Notice that the largest exponent is one less than the number of digits, and that the exponents go down by one as we move through the number.

Condensed — the full section is in OpenStax Contemporary Mathematics.

Converting Numbers in Expanded Form to Hindu-Arabic Numerals

Converting from expanded form back into a Hindu-Arabic numeral is the reverse process of expanding a number, and is equivalent to evaluating the exponential expression.

Converting a Number from Expanded Form to a Hindu-Arabic Numeral

Try it.

Convert the following into Hindu-Arabic numerals.

  1. \(3\times {10}^{2}+4\times {10}^{1}+8\times {10}^{0}\)
  2. \(5\times {10}^{3}+0\times {10}^{2}+9\times {10}^{1}+9\times {10}^{0}\)
  3. \(6\times {10}^{6}+2\times {10}^{5}+0\times {10}^{4}+9\times {10}^{3}+1\times {10}^{2}+1\times {10}^{1}+7\times {10}^{0}\)
Solution
  1. Evaluating the expression results in: \(3\times {10}^{2}+4\times {10}^{1}+8\times {10}^{0}=3\times 100+4\times 10+8\times 1=300+40+8=348\)
  2. Evaluating the expression results in: \(5\times {10}^{3}+0\times {10}^{2}+9\times {10}^{1}+9\times {10}^{0}=5\times 1000+0\times 100+9\times 10+9\times 1=5000+0+90+9=5099\)
  3. Evaluating the expression results in: \(\begin{array}{l}6\times {10}^{6}+2\times {10}^{5}+0\times {10}^{4}+9\times {10}^{3}+1\times {10}^{2}+1\times {10}^{1}+7\times {10}^{0} \\ =6\times 1,000,000+2\times 100,000+0\times 10,000+9\times 1,000+1\times 100+1\times 10+7\times 1 \\ =6,000,000+200,000+0+9,000+100+10+7 \\ =6,209,117\end{array}\)

Key Concepts

  • Exponents are used to represent repeated multiplication of a base.
  • In arithmetic, exponents are computed before multiplication, division, addition, and subtraction. Computing an exponent is done by multiplying the base by itself the number of times equal to the exponent.
  • The system of numbers currently used is the Hindu-Arabic system. Digits in this system take on values based on their place in the number. The place values are determined by multiplying the digit by 10 raised to the appropriate power.
  • The expanded form of a Hindu-Arabic number is the sum of each digit times 10 raised to the exponent for that place value.

Practice (3)

Try each one on paper first. Reveal the answer to check; verified ones can be opened in the solver for every step.

  1. Evaluate the following exponential expressions.

    1. \(4\times {5}^{2}+2\times {6}^{3}\)
    2. \(6\times {8}^{2}+3\times {8}^{1}+4\times {8}^{0}\)
    3. \(3\times {10}^{2}+0\times {10}^{1}+6\times {10}^{0}\)
    जवाब दिखाएँ
    1. To evaluate, or calculate, this expression, we use order of operations, which means the exponents are done first, then multiplications, and then additions. \[4\times {5}^{2}+2\times {6}^{3}=4\times 5\times 5+2\times 6\times 6\times 6=4\times 25+2\times 216=100+432=532\]
    2. To evaluate the expression, we use the order of operations, which means the exponents are done first, then the multiplications, then the additions. Remember that any base raised to the exponent 0 is 1. \[6\times {8}^{2}+3\times {8}^{1}+4\times {8}^{0}=6\times 8\times 8+3\times 8+4\times 1=6\times 64+3\times 8+4\times 1=384+24+4=412\]
    3. To evaluate the expression, we use the order of operations, which means the exponents are done first, then the multiplications, and then the additions. Remember that any base raised to the exponent 0 is 1. \[3\times {10}^{2}+0\times {10}^{1}+6\times {10}^{0}=3\times 100+0\times 10+6\times 1=300+0+6=306\]

  2. Write the following in expanded form.

    1. 563
    2. 4,821
    3. 903,786
    जवाब दिखाएँ

    1. Step 1: Since there are three digits in 563, \(n\) is 3. So, this is the first digit times 10 raised to the power of 2, so we start with \(5\times {10}^{2}\).

      Step 2: Then we add the next digit, 6, multiplied by 10 to a power one less than the previous, at which point we have \(5\times {10}^{2}+6\times {10}^{1}\).

      Step 3: Finally, the last digit is multiplied by 10 to the zeroth power and added to the previous. This results in \(5\times {10}^{2}+6\times {10}^{1}+3\times {10}^{0}\).

    2. Step 1: Since there are four digits in 4,821, \(n\) is 4. We multiply the first digit, 4, by 10 raised to the power of 3, which is \(4\times {10}^{3}\).

      Step 2: Then we add the next digit, 8, multiplied by 10 to a power one less than the previous, at which point we have \(4\times {10}^{3}+8\times {10}^{2}\).

      Step 3: We continue to the next digit, lowering the exponent of 10 by one. Now we have \(4\times {10}^{3}+8\times {10}^{2}+2\times {10}^{1}\).

      Step 4: Finally, the last digit is multiplied by 10 to the zeroth power and added to the previous. This results in \(4\times {10}^{3}+8\times {10}^{2}+2\times {10}^{1}+1\times {10}^{0}\).

    3. Since there are six digits in 903,786, \(n\) is 6. So, we begin the process with 9 times 10 raised to the 5th power and continue through the numbers, reducing the exponent of 10 by one each time. This results in \(9\times {10}^{5}+0\times {10}^{4}+3\times {10}^{3}+7\times {10}^{2}+8\times {10}^{1}+6\times {10}^{0}\).

  3. Convert the following into Hindu-Arabic numerals.

    1. \(3\times {10}^{2}+4\times {10}^{1}+8\times {10}^{0}\)
    2. \(5\times {10}^{3}+0\times {10}^{2}+9\times {10}^{1}+9\times {10}^{0}\)
    3. \(6\times {10}^{6}+2\times {10}^{5}+0\times {10}^{4}+9\times {10}^{3}+1\times {10}^{2}+1\times {10}^{1}+7\times {10}^{0}\)
    जवाब दिखाएँ
    1. Evaluating the expression results in: \(3\times {10}^{2}+4\times {10}^{1}+8\times {10}^{0}=3\times 100+4\times 10+8\times 1=300+40+8=348\)
    2. Evaluating the expression results in: \(5\times {10}^{3}+0\times {10}^{2}+9\times {10}^{1}+9\times {10}^{0}=5\times 1000+0\times 100+9\times 10+9\times 1=5000+0+90+9=5099\)
    3. Evaluating the expression results in: \(\begin{array}{l}6\times {10}^{6}+2\times {10}^{5}+0\times {10}^{4}+9\times {10}^{3}+1\times {10}^{2}+1\times {10}^{1}+7\times {10}^{0} \\ =6\times 1,000,000+2\times 100,000+0\times 10,000+9\times 1,000+1\times 100+1\times 10+7\times 1 \\ =6,000,000+200,000+0+9,000+100+10+7 \\ =6,209,117\end{array}\)

Symbols used here

\log_b x,\ \ln x
logarithm, natural log
The exponent b must be raised to for x; ln uses base e.
\sum_{k=1}^{n} a_k
summation
Add a_k for k = 1 up to n.
\prod_{k=1}^{n} a_k
product
Multiply a_k for k = 1 up to n.
\mathbb{N},\ \mathbb{Z},\ \mathbb{Q},\ \mathbb{R},\ \mathbb{C}
number sets
Naturals, integers, rationals, reals, complex numbers.
a \equiv b \pmod n
congruent modulo n
n divides a − b; a and b have the same remainder.
a \mid b,\ \gcd(a,b)
divides, greatest common divisor
b is a multiple of a; the largest number dividing both.
\varphi(n),\ \pi(x)
Euler's totient, prime-counting function
Count of 1..n coprime to n; number of primes up to x.
\mathbb{Z}/n\mathbb{Z},\ \mathbb{Z}_n
integers modulo n
The remainders 0…n−1 with clock arithmetic.
a \bmod n
remainder
What is left after dividing a by n.

How to: Hindu-Arabic Positional System

  1. Evaluate an exponential expression.
  2. Convert a Hindu-Arabic numeral to expanded form.
  3. Convert a number in expanded form to a Hindu-Arabic numeral.
  4. To evaluate, or calculate, this expression, we use order of operations, which means the exponents are done first, then multiplications, and then additions.
  5. To evaluate the expression, we use the order of operations, which means the exponents are done first, then the multiplications, then the additions. Remember that any base raised to the exponent 0 is 1.
  6. To evaluate the expression, we use the order of operations, which means the exponents are done first, then the multiplications, and then the additions. Remember that any base raised to the exponent 0 is 1.
  7. 563
  8. 4,821

Questions people ask

Why are primes so important?

Every integer factors into primes in exactly one way, so primes are the atoms of multiplication. Cryptography relies on that factoring being easy to state and hard to do.

How do I tell whether a big number is prime?

Trial division up to the square root works for small numbers. For large ones, probabilistic tests (Miller–Rabin) give an answer that is wrong with negligible probability, and deterministic tests (AKS) exist but are slower.

अपने आप की कोशिश करें

Parts of this page are adapted from OpenStax Contemporary Mathematics (CC BY-NC-SA 4.0). Condensed and re-explained here; errors are ours.

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