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The Idea of a Line Integral
This section relies heavily on understanding vector fields from , understanding curves in space (from ), and the work interpretation of the dot product from .
The Idea of a Line Integral
This section relies heavily on understanding vector fields from , understanding curves in space (from ), and the work interpretation of the dot product from .
A suggestion to check that students understand the material in is to ask them to draw \(-C_2\) and explain why \(C_1-C_2\) does not make sense in that example.
Introduction
Movement by things like air or water will exert a force on objects, so wind velocity vector fields are related to a force field but the relationship between a moving fluid and the force a fluid exerts on an object in the fluid can be complicated. Specifically, issues like drag/friction and cross sectional area are a critical part of this relationship but are not something that we will focus on in our discussion. In the exploration below, we will look at a simplified version of this situation.
As we discussed in , vector fields are often used to represent forces such as gravity or electromagnetism, as well as the velocity of movement for things like wind or flowing water. We learned in that the dot product of a force vector and a displacement vector tells us how much work the force did on the object as it moved from the start of its displacement vector to the end. However, this calculation assumes that the force is constant in the region of movement and that the object moves in a straight line along the displacement vector. The situation is more complicated than a dot product calculation when an object's movement is not in a straight line and when the force is not uniform throughout the area in which the object moves.
The preview activity uses cardinal directions to specify the direction of displacement vectors. These directions can be described by a Copyright 2013-2026 . The Copyright 2013-2026 given in is an example of a sixteen point rose. Note that directions like ESE are read as east-southeast half way between east and southeast.
Condensed — the full section is in Boelkins et al., Active Calculus Multivariable.
Orientations of Curves
Given our motivation for calculating the work that a force field does on an object as it moves through the field, it is natural to concern ourselves with how the object moves. In particular, in many circumstances it will be different if an object moves from the point \((0,1)\) to the point \((4,3)\) by first going up the \(y\)-axis to \((0,3)\) and then moving horizontally to \((4,3)\) (illustrated by \(C_1\) in ) than if the object moves along the line segment from \((0,1)\) directly to \((4,3)\)(illustrated by \(C_2\) in ). Similarly, given a fixed force field, we would expect the work done to be different (in fact, opposite) if the object moves from \((4,3)\) to \((0,1)\) directly along a line segment (\(C_3\) in ). We say that a curve in \(\R^2\) or \(\R^3\) is oriented if we have specified the direction of travel along the curve. When a curve is given parametrically (including as a vector-valued function), our convention will be that the orientation follows from the smallest allowable value of the parameter to the largest.
Activity
For each curve below, find a parametrization of the curve. Ensure that each curve's orientation matches the one specified.
The line segment in \(\R^3\) from \((0,1,-2)\) to \((3,-1,2)\).
The line segment in \(\R^3\) from \((3,-1,2)\) to \((0,1,-2)\).
The circle of radius \(3\) (in \(\R^2\)) centered at the origin, beginning at the point \((0,-3)\) and proceeding clockwise around the circle.
In \(\R^2\), the portion of the parabola \(y^2 = x\) from the point \((4,2)\) to the point \((1,-1)\).
In general, there are many ways to parametrize an oriented curve. With line segments, it is common to have the parameter range from \(0\) to \(1\), although there are sometimes good reasons to choose another method. For circles and ellipses, you may find it useful to interchange the placement of \(\cos(t)\) and \(\sin(t)\) to change the orientation, but then careful attention will need to be paid to the start and end points. The interactive graph below allows you to plot parametric curves. You should experiment with the graph below and try to make sense of how changing different elements affects the graph shown below. Remember that you can change the highlighted point using the slider. You should take time now to at least try the following:
- \(2 \pi\)
- \(r_1\)\(r_2\)
- \(t\)\(-t\)
- \(-t\)\(e^t\)
- Change the upper and lower bounds to get the same curve plotted as in the earlier parts
Line Integrals
showed how we can break up the work done along a path into a sum of work done on each piece. This will be a very helpful idea, especially if we consider the work done by a vector field that is not constant.
For example, let's consider how to measure the work done by \(\vF\), a vector field, along \(C\), the curve shown below that goes from \(P\) to \(Q\).
You can see that there will be parts of \(C\) such that the dot product of the direction of travel and the vector field will be positive and some parts where the dot product is negative. We don't need to consider the output of the vector field except at the points on the curve. Thus, we will look at the following plot of the output of \(\vF\) at a collection of points on the curve \(C\). Remember that when the vector field is plotted on the whole space, the lengths are rescaled to not be visually cluttered. In the actual output vectors are plotted for some points on \(C\).
Since the output of \(\vF\) is changing as you move along the path, we will use a classic calculus approach. For step 1 of our CCA, we will break our region up into smaller pieces to approximate the work done on each piece. shows how we can break \(C\) into \(n\) pieces, which we will call \(C_i\). Note that \(C_i\) goes from the point \(\mathbf{r}_{i-1}\) to \(\mathbf{r}_{i}\).
If we look at one of these smaller pieces (as show in ), we can see that vector field still changes at these points, but the output vectors are very similar. We can also see that the vector \(\Delta \mathbf{r}_i= \mathbf{r}_i-\mathbf{r}_{i-1}\) is a good approximation of the curve piece \(C_i\). Therefore we can approximate the work done by the vector field \(\vF\) on the piece \(C_i\) by \(\vF(\mathbf{r}_i)\cdot \Delta \mathbf{r}_i\). Remember that this is the same idea as in ; Namely, the work done is the dot product of the force and the displacement, but this is done on many small pieces instead of the whole path.
Our approximation with \(n\) pieces of \(C\) would be \[\begin{aligned}\end{aligned}\] which completes step 1 of the CCA.
Note that as we increase \(n\), the number of pieces of \(C\) in our approximation, and make sure the length of each piece, \(C_i\), goes to zero, the vector field \(\vF\) will be nearly constant on each piece. Additionally, the displacement vector, \(\Delta \mathbf{r}_i\), will be a better approximation of \(C_i\) as \(n\) increases. This all combines to ensure that as we increase \(n\), the number of smaller segments, our approximation will improve even more quickly.
Condensed — the full section is in Boelkins et al., Active Calculus Multivariable.
Properties of Line Integrals
In , we implicitly made use of the idea that if \(C\) can be broken up into two curves \(C_1\) and \(C_2\) such that the terminal point of \(C_1\) is the initial point of \(C_2\), then the line integral of \(\vF\) along \(C\) is the sum of the line integrals of \(\vF\) along \(C_1\) and along \(C_2\). This is a generalization of the property for definite integrals that tells us if \(c\in [a,b]\), then \[\begin{aligned}\end{aligned}\]. We next describe some common ways of breaking line integrals into pieces.
For a constant scalar \(k\), vector fields \(\vF\) and \(\vG\), and oriented curves \(C\), \(C_1\), and \(C_2\), the following properties hold:
\(\displaystyle\int_C (k\vF)\cdot d\vr = k\int_C\vF\cdot d\vr\)
\(\displaystyle\int_C(\vF+\vG)\cdot d\vr = \int_C \vF\cdot d\vr + \int_C\vG\cdot d\vr\)
\(\displaystyle\int_{-C}\vF\cdot d\vr = -\int_C \vF\cdot d\vr\)
\(\displaystyle\int_{C_1+C_2} \vF\cdot d\vr = \int_{C_1}\vF\cdot d\vr + \int_{C_2}\vF\cdot d\vr\).
Activity
shows a vector field \(\vF\) as well as six oriented curves, as labeled in the plot.
Is \(\int_{C_6}\vF\cdot d\vr\) positive, negative, or zero? Explain.
Let \(C = C_1+C_2+C_3+C_4\). Determine if \(\displaystyle\int_C\vF\cdot d\vr\) is positive, negative, or zero.
Order the line integrals below from smallest to largest. \[\begin{aligned}\end{aligned}\]
The Circulation of a Vector Field
If an oriented curve \(C\) ends at the same point where it started, we say that \(C\) is closed. The line integral of a vector field \(\vF\) along a closed curve \(C\) is called the circulation of \(\vF\) around \(C\). To emphasize the fact that \(C\) is closed, we sometimes write \(\oint_C \vF\cdot d\vr\) for \(\int_C \vF\cdot d\vr\). Circulation serves as a measure of a vector field's tendency to rotate in a manner consistent with the orientation of the (closed) curve and is measured by looking at whether the vector field is working with or against the motion along the path.
Activity
Determine if the circulation of the vector field around each of the closed curves shown in is positive, negative, or zero.
Solution
The circular curve is oriented consistently with the vector field. Thus, the circulation is positive. The larger rectangular curve is either orthogonal to the vector field or oriented consistently with the vector field. Thus, the circulation is positive. The smaller rectangular curve is orthogonal to the vector field or has the opposite orientation. Thus, its circulation is negative.
Practice (1)
Try each one on paper first. Reveal the answer to check; verified ones can be opened in the solver for every step.
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Let \(C\) be the path given below from \(P\) to \(Q\) with pieces \(C_1\), \(C_2\), and \(C_3\) as labeled. Let \(\vF\) be a vector field such that \(\int_C \vF\cdot d\vr = 9\), \(\int_{C_1} \vF\cdot d\vr = 6\),and \(\int_{C_3} \vF\cdot d\vr = 7\).
Find the following:
- \(\int_{-C_3} \vec{\vF}\cdot d\vec{\vr}\)
- \(\int_{C_2} \vec{\vF}\cdot d\vec{\vr}\)
- \(\int_{-C_1-C_3} \vec{\vF}\cdot d\vec{\vr}\)
Cevabı açıkla.
- \(\int_{-C_3} \vec{\vF}\cdot d\vec{\vr} =-7\)
- \(\int_{C_2} \vec{\vF}\cdot d\vec{\vr}=-4\)\(C=C_1+C_2+C_3\)\(C_1\)\(C_3\)
- \(\int_{-C_1-C_3} \vec{\vF}\cdot d\vec{\vr}=-13\)\(\int_{C_1+C_3} \vec{\vF}\cdot d\vec{\vr}=13\)\(\int_{-C} \vec{\vF}\cdot d\vec{\vr}=- \int_{C} \vec{\vF}\cdot d\vec{\vr}\)
Symbols used here
Antiderivative (indefinite) or signed area from a to b (definite).
Integral over a region of the plane; integral around a closed curve.
Ratio of a circle's circumference to its diameter, 3.14159…
Ratios of sides in a right triangle; coordinates on the unit circle.
x belongs to A; every element of A is in B.
2.71828…, the base whose exponential is its own derivative.
i² = −1.
Derivative with respect to x, holding the other variables fixed.
Vector of partial derivatives; points uphill.
A quantity with magnitude and direction; a column of numbers.
Σ u_i v_i; the length of v, √(v·v).
How to: The Idea of a Line Integral
- What is an oriented curve and how can we represent one algebraically?
- What is the meaning of the line integral of a vector-valued function along a curve and how can we estimate if its value is positive, negative, or zero?
- What are important properties of the line integral of a vector-valued functions along a curve?
Questions people ask
What is a partial derivative?
The ordinary derivative with respect to one variable while every other variable is frozen — the slope of the surface in one coordinate direction.
What does the gradient point at?
Uphill: the direction of steepest increase, with length equal to that steepest slope. It is perpendicular to the level curves.
Kendini dene.
Parts of this page are adapted from Boelkins et al., Active Calculus Multivariable (CC BY-SA 4.0). Condensed and re-explained here; errors are ours.
Daha fazlası Multivariable Calculus
Functions of several variablesPartial derivatives and the gradientOptimisation in several variablesDouble and triple integralsVector fields, line integrals and the big theorems