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Eulerian and Lagrangian descriptions, the material derivative
Following particles versus watching fixed points, and the operator D/Dt that connects them.
There are two ways to describe a moving fluid. In the Lagrangian description you label each fluid particle by where it started, \(\mathbf{a}\), and follow its position \(\mathbf{X}(\mathbf{a},t)\). In the Eulerian description you stand at a fixed point \(\mathbf{x}\) and record the velocity \(\mathbf{u}(\mathbf{x},t)\) of whatever particle happens to be there. The two are linked by the statement that particles move with the flow: \[ \frac{\partial \mathbf{X}}{\partial t}(\mathbf{a},t) = \mathbf{u}(\mathbf{X}(\mathbf{a},t),t), \qquad \mathbf{X}(\mathbf{a},0) = \mathbf{a}. \] The map \(\mathbf{a}\mapsto\mathbf{X}(\mathbf{a},t)\) is called the flow map. Both descriptions go back to Euler; the names are a later convention.
Physical laws are stated for particles (a parcel of fluid is accelerated by the forces on it), but measurements and equations are easiest at fixed points. The bridge is the chain rule. If \(f(\mathbf{x},t)\) is any field, its rate of change along a particle path is \[ \frac{d}{dt} f(\mathbf{X}(\mathbf{a},t),t) = \frac{\partial f}{\partial t} + \frac{\partial X_j}{\partial t}\frac{\partial f}{\partial x_j} = \frac{\partial f}{\partial t} + (\mathbf{u}\cdot\nabla) f. \] This operator is the material derivative, \(\dfrac{D}{Dt} = \dfrac{\partial}{\partial t} + \mathbf{u}\cdot\nabla\). The first term is the change seen by a fixed observer; the second is the change caused by being carried to a place where the field is different.
Applied to the velocity itself it gives the acceleration of a fluid particle, \[ \frac{D\mathbf{u}}{Dt} = \frac{\partial\mathbf{u}}{\partial t} + (\mathbf{u}\cdot\nabla)\mathbf{u}. \] The second term is quadratic in \(\mathbf{u}\): it is the nonlinearity of fluid mechanics. It also means a steady flow can accelerate its particles. In the rotation \(\mathbf{u} = (-y, x)\) nothing depends on time, yet \((\mathbf{u}\cdot\nabla)\mathbf{u} = (-x,-y)\), the centripetal acceleration of a particle going round a circle.
A second useful fact is how volumes change. Let \(J = \det(\partial X_i/\partial a_j)\) be the Jacobian of the flow map, the factor by which a small blob of particles has changed volume. Differentiating the determinant gives Euler's expansion formula \[ \frac{DJ}{Dt} = (\nabla\cdot\mathbf{u})\,J. \] So the divergence of the velocity is the relative rate of volume growth of a fluid parcel, which is the key to incompressibility.
Picture it: a thermometer bolted to a bridge pier reads \(\partial T/\partial t\); a thermometer on a drifting buoy reads \(DT/Dt\). Think it: \(D/Dt\) is a directional derivative in space-time, along the vector \((\mathbf{u},1)\). For \(T = x^2+y^2\) in the rotation \(\mathbf{u} = (-y,x,0)\), \(DT/Dt = 0\): the temperature a particle carries does not change, because particles move along the circles where \(T\) is constant.
工作范例 · material derivative of T = x*t with velocity [y, 0, 0]
Material derivative of T = x*t with velocity [y, 0, 0]
一步
- T = t x,\quad \mathbf{u} = \left\langle y,\ 0,\ 0 \right\rangle,\quad \frac{D}{Dt} = \frac{\partial}{\partial t} + y\,\frac{\partial }{\partial x} + 0\,\frac{\partial }{\partial y} + 0\,\frac{\partial }{\partial z}
The material derivative follows a fluid particle: the change at a fixed point, plus the change from being carried along by the flow.
- \frac{\partial T}{\partial t} = x
The local rate of change: differentiate with respect to t at a fixed position.
- \frac{\partial T}{\partial x} = t
Differentiate with respect to x, holding t and the other coordinates constant.
- \frac{\partial T}{\partial y} = 0
Differentiate with respect to y, holding t and the other coordinates constant.
- \frac{\partial T}{\partial z} = 0
Differentiate with respect to z, holding t and the other coordinates constant.
- \mathbf{u}\cdot\nabla T = \left(y\right)\left(t\right) + \left(0\right)\left(0\right) + \left(0\right)\left(0\right) = t y
The convective part: each velocity component times the matching slope.
- \frac{DT}{Dt} = x + \left(t y\right) = t y + x
Add the local and convective parts.
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如何: Eulerian and Lagrangian descriptions, the material derivative
- Write the field f(x, y, z, t) and the velocity components (u, v, w).
- Compute the partial time derivative with position held fixed.
- Compute the gradient of f and dot it with the velocity: u f_x + v f_y + w f_z.
- Add the two parts: Df/Dt. If it is zero, f is carried unchanged by every particle.
人们对人们提出的问题
Is D/Dt the same as d/dt?
It is d/dt along a particle path, written in Eulerian variables. The capital D reminds you that the path is the one the flow itself chooses.
Why is the acceleration nonlinear when the velocity is not?
Because the velocity both is the field being differentiated and decides the direction of differentiation. That product is where turbulence, vortex stretching and every hard question about the equations come from.
What do I need before starting fluid dynamics?
Multivariable calculus (divergence, curl, the divergence and Stokes theorems), linear algebra (symmetric matrices and eigenvalues) and partial differential equations (the heat and Laplace equations). The last lessons also use Sobolev spaces, which are introduced where they are needed.
What are the Navier-Stokes equations in one sentence?
Newton's second law for each particle of a viscous incompressible fluid: acceleration equals the pressure force plus viscous diffusion of momentum, with the constraint that the velocity field is divergence-free.
Why is two-dimensional flow easier than three-dimensional flow?
In 2D the vorticity is a scalar that is only carried and diffused, so its maximum never grows; in 3D vortex lines can be stretched, which amplifies vorticity, and no known bound rules out unlimited growth.
Is this course physics or mathematics?
Both, in order. The first half derives the equations from physical principles and solves classical flows; the second half treats the equations as mathematical objects and studies which of their properties can be proved.
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