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Holomorphic functions and the Cauchy-Riemann equations
What complex differentiability demands, and why it is so restrictive.
f = u + iv is holomorphic when u_x = v_y and u_y = −v_x. Then u and v are harmonic and f is infinitely differentiable. Picture it: z² = (x² − y²) + i(2xy): the level curves of the real and imaginary parts cross at right angles. Think it: the derivative at a point is a rotation-and-scaling, so holomorphic maps preserve angles (conformal).
Çözümlü örnek · derivative of x^2 - y^2 wrt x
Adım adım
- \frac{d}{dx}\left[x^{2} - y^{2}\right]
Start from the derivative to compute.
- \frac{d}{d x} x^{2} + \frac{d}{d x} \left(- y^{2}\right)
Sum rule: differentiate term by term.
- 2 x + \frac{d}{d x} \left(- y^{2}\right)
Power rule: (xⁿ)′ = n·xⁿ⁻¹ with n = 2.
- 2 x
The derivative of a constant is 0.
Cevabı göster
Şimdi sen Bir problem seçin, ya da kendi probleminizi yazın ya da çizin. Her adım, bir resim, cevap sorulana kadar gizli.
Burada kullanılan sembolleri
Tüm tanım, resim ve her harfin anlamı için herhangi bir sembolü tıklayın.
Nasıl: Holomorphic functions and the Cauchy-Riemann equations
- Start from the derivative to compute.
- Sum rule: differentiate term by term.
- Power rule: (xⁿ)′ = n·xⁿ⁻¹ with n = 2.
- The derivative of a constant is 0.
Sık sorulan sorular
Why is complex differentiability so much stronger than real?
The limit must be the same from every direction in the plane, not just two. That forces the Cauchy-Riemann equations, which in turn force infinitely many derivatives and a convergent Taylor series.
What is a residue?
The coefficient of 1/(z − a) in the Laurent series at a singularity a. The residue theorem says a contour integral equals 2πi times the sum of the residues inside, which evaluates many real integrals in one line.
More in Complex Analysis
The complex plane and Euler's formulaContour integrals and the residue theoremPower series and analytic continuation