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Entire function
In complex analysis, an entire function, also called an integral function, is a complex-valued function that is holomorphic on the whole complex plane.
Entire function
In complex analysis, an entire function, also called an integral function, is a complex-valued function that is holomorphic on the whole complex plane. Typical examples of entire functions are polynomials and the exponential function, and any finite sums, products and compositions of these, such as the trigonometric functions sine and cosine and their hyperbolic counterparts sinh and cosh, as well as derivatives and integrals of entire functions such as the error function. If an entire function \(f(z)\) has a root at \(w\), then \(f(z)/(z-w)\), taking the limit value at \(w\), is an entire function. On the other hand, the natural logarithm, the reciprocal function, and the square root are all not entire functions, nor can they be continued analytically to an entire function.
A transcendental entire function is an entire function that is not a polynomial.
Just as meromorphic functions can be viewed as a generalization of rational functions, entire functions can be viewed as a generalization of polynomials. In particular, if for meromorphic functions one can generalize the factorization into simple fractions (the Mittag-Leffler theorem on the decomposition of a meromorphic function), then for entire functions there is a generalization of the factorization: the Weierstrass theorem on entire functions.
Properties
Every entire function \(f(z)\) can be represented as a single power series: \[\ f(z) = \sum_{n=0}^\infty a_n z^n\] that converges everywhere in the complex plane, hence uniformly on compact sets. The radius of convergence is infinite, which implies that \[\ \lim_{n\to\infty} |a_n|^{\frac{1}{n}} = 0\] or, equivalently, \[\ \lim_{n\to\infty} \frac{\ln|a_n|}n = -\infty ~.\] Any power series satisfying this criterion will represent an entire function.
If (and only if) the coefficients of the power series are all real then the function evidently takes real values for real arguments, and the value of the function at the complex conjugate of \(z\) will be the complex conjugate of the value at \(z\). Such functions are sometimes called self-conjugate (the conjugate function, \(F^*(z)\), being given by \(\bar F(\bar z)\)).
If the real part of an entire function is known in a (complex) neighborhood of a point then both the real and imaginary parts are known for the whole complex plane, up to an imaginary constant. For instance, if the real part is known in a neighborhood of zero, then we can find the coefficients for \(n>0\) from the following derivatives with respect to a real variable \(r\): \[\begin{align} \Re(a_n) &= \frac{1}{n!} \left.\frac{\textrm d^n}{\textrm dr^n}\ \Re(f(r))\right|_{r=0} \\ \Im(a_n) &= \frac{1}{n!} \left.\frac{\textrm d^n}{\textrm dr^n} \Re\Bigl(f\Bigl(re^{-\frac{i\pi}{2n}}\Bigr)\Bigr)\right|_{r=0} \end{align}\]
(Likewise, if the imaginary part is known in such a neighborhood then the function is determined up to a real constant.) In fact, if the real part is known just on an arc of a circle, then the function is determined up to an imaginary constant. Note however that an entire function is not necessarily determined by its real part on some other curves. In particular, if the real part is given on any curve in the complex plane where the real part of some other entire function is zero, then any multiple of that function can be added to the function we are trying to determine. For example, if the curve where the real part is known is the real line, then we can add \(i\) times any self-conjugate function. If the curve forms a loop, then it is determined by the real part of the function on the loop since the only functions whose real part is zero on the curve are those that are everywhere equal to some imaginary number.
The Weierstrass factorization theorem asserts that any entire function can be represented by a product involving its zeroes (or "roots").
The entire functions on the complex plane form an integral domain (in fact a Prüfer domain). They also form a commutative unital associative algebra over the complex numbers.
Liouville's theorem states that any bounded entire function must be constant.
\(\ \lim_{m\to\infty} |z_m| = \infty, \qquad \text{and} \qquad \lim_{m\to\infty} f(z_m) = w ~.\)
Condensed: the full section is in Wikipedia.
Growth
Entire functions may grow as fast as any increasing function: for any increasing function \(g:[0,\infty)\to[0,\infty)\) there exists an entire function \(f\) such that \(f(x)>g(|x|)\) for all real \(x\). Such a function \(f\) may be easily found of the form: \[f(z)=c+\sum_{k=1}^{\infty}\left(\frac{z}{k}\right)^{n_k}\] for a constant \(c\) and a strictly increasing sequence of positive integers \(n_k\). Any such sequence defines an entire function \(f(z)\), and if the powers are chosen appropriately we may satisfy the inequality \(f(x)>g(|x|)\) for all real \(x\). (For instance, it certainly holds if one chooses \(c:=g(2)\) and, for any integer \(k \ge 1\) one chooses an even exponent \(n_k\) such that \(\left(\frac{k+1}{k}\right)^{n_k} \ge g(k+2)\)).
Order and type
The order (at infinity) of an entire function \(f(z)\) is defined using the limit superior as: \[\rho = \limsup_{r\to\infty}\frac{\ln \left (\ln\| f \|_{\infty, B_r} \right ) }{\ln r},\] where \(B_r\) is the disk of radius \(r\) and \(\|f \|_{\infty, B_r}\) denotes the supremum norm of \(f(z)\) on \(B_r\). The order is a non-negative real number or infinity (except when \(f(z) = 0\) for all \(z\)). In other words, the order of \(f(z)\) is the infimum of all \(m\) such that: \[f(z) = O \left (\exp \left (|z|^m \right ) \right ), \quad \text{as } z \to \infty.\]
The example of \(f(z) = \exp(2z^2)\) shows that this does not mean \(f(z)=O(\exp(|z|^m))\) if \(f(z)\) is of order \(m\).
If \(0 < \rho < \infty\), one can also define the type: \[\sigma=\limsup_{r\to\infty}\frac{\ln \| f\|_{\infty, B_r}} {r^\rho}.\]
If the order is 1 and the type is \(\sigma\), the function is said to be "of exponential type \(\sigma\)". If it is of order less than 1 it is said to be of exponential type 0.
If \[f(z)=\sum_{n=0}^\infty a_n z^n,\] then the order and type can be found by the formulas \[\begin{align} \rho &=\limsup_{n\to\infty} \frac{n\ln n}{-\ln|a_n|} \\[6pt] (e\rho\sigma)^{\frac{1}{\rho}} &= \limsup_{n\to\infty} n^{\frac{1}{\rho}} |a_n|^{\frac{1}{n}} \end{align}\]
Let \(f^{(n)}\) denote the \(n\)th derivative of \(f\). Then we may restate these formulas in terms of the derivatives at any arbitrary point \(z_0\): \[\begin{align} \rho &=\limsup_{n\to\infty}\frac{n\ln n}{n\ln n-\ln|f^{(n)}(z_0)|}=\left(1-\limsup_{n\to\infty}\frac{\ln|f^{(n)}(z_0)|}{n\ln n}\right)^{-1} \\[6pt] (\rho\sigma)^{\frac{1}{\rho}} &=e^{1-\frac{1}{\rho}} \limsup_{n\to\infty}\frac{|f^{(n)}(z_0)|^{\frac{1}{n}}}{n^{1-\frac{1}{\rho}}} \end{align}\]
The type may be infinite, as in the case of the reciprocal gamma function, or zero (see example below under § Order 1).
Condensed: the full section is in Wikipedia.
Genus
Entire functions of finite order have Hadamard's canonical representation (Hadamard factorization theorem): \[f(z)=z^me^{P(z)}\prod_{n=1}^\infty\left(1-\frac{z}{z_n}\right)\exp\left(\frac{z}{z_n}+\cdots+\frac{1}{p} \left(\frac{z}{z_n}\right)^p\right),\] where \(z_k\) are those roots of \(f\) that are not zero (\(z_k \neq 0\)), \(m\) is the order of the zero of \(f\) at \(z = 0\) (the case \(m = 0\) being taken to mean \(f(0) \neq 0\)), \(P\) a polynomial (whose degree we shall call \(q\)), and \(p\) is the smallest non-negative integer such that the series \[\sum_{n=1}^\infty\frac{1}{|z_n|^{p+1}}\] converges. The non-negative integer \(g=\max\{p, q\}\) is called the genus of the entire function \(f\).
If the order \(\rho\) is not an integer, then \(g = \lfloor\rho\rfloor\) is the integer part of \(\rho\). If the order is a positive integer, then there are two possibilities: \(g = \rho-1\) or \(g = \rho\).
For example, \(\sin\), \(\cos\) and \(\exp\) are entire functions of genus \(g = \rho = 1\).
Other examples
According to J. E. Littlewood, the Weierstrass sigma function is a 'typical' entire function. This statement can be made precise in the theory of random entire functions: the asymptotic behavior of almost all entire functions is similar to that of the sigma function. Other examples include the Fresnel integrals, the Jacobi theta function, and the reciprocal Gamma function. The exponential function and the error function are special cases of the Mittag-Leffler function. According to the fundamental theorem of Paley and Wiener, Fourier transforms of functions (or distributions) with bounded support are entire functions of order \(1\) and finite type.
Other examples are solutions of linear differential equations with polynomial coefficients. If the coefficient at the highest derivative is constant, then all solutions of such equations are entire functions. For example, the exponential function, sine, cosine, Airy functions and Parabolic cylinder functions arise in this way. The class of entire functions is closed with respect to compositions. This makes it possible to study dynamics of entire functions.
An entire function of the square root of a complex number is entire if the original function is even, for example \(\cos(\sqrt{z})\).
If a sequence of polynomials all of whose roots are real converges in a neighborhood of the origin to a limit which is not identically equal to zero, then this limit is an entire function. Such entire functions form the Laguerre-Pólya class, which can also be characterized in terms of the Hadamard product, namely, \(f\) belongs to this class if and only if in the Hadamard representation all \(z_n\) are real, \(\rho\leq 1\), and \(P(z)=a+bz+cz^2\), where \(b\) and \(c\) are real, and \(c\leq 0\). For example, the sequence of polynomials \[\left (1-\frac{(z-d)^2}{n} \right )^n\] converges, as \(n\) increases, to \(\exp(-(z-d)^2)\). The polynomials \[\frac{1}{2}\left ( \left (1+\frac{iz}{n} \right )^n+ \left (1-\frac{iz}{n} \right )^n \right )\] have all real roots, and converge to \(\cos(z)\). The polynomials \[\prod_{m=1}^n \left(1-\frac{z^2}{\left ( \left (m-\frac{1}{2} \right )\pi \right )^2}\right)\] also converge to \(\cos(z)\), showing the buildup of the Hadamard product for cosine.
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Why is complex differentiability so much stronger than real?
The limit must be the same from every direction in the plane, not just two. That forces the Cauchy-Riemann equations, which in turn force infinitely many derivatives and a convergent Taylor series.
What is a residue?
The coefficient of 1/(z − a) in the Laurent series at a singularity a. The residue theorem says a contour integral equals 2πi times the sum of the residues inside, which evaluates many real integrals in one line.
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