maths.free › Combinatorics & Graph Theory › 2. Strings, Sets, and Binomial Coefficients › Multinomial Coefficients
Multinomial Coefficients
Let X be a set of n elements. Suppose that we have two colors of paint, say red and blue, and we are going to choose a subset of k elements to be painted red with the rest painted blue.
Multinomial Coefficients
Let \(X\) be a set of \(n\) elements. Suppose that we have two colors of paint, say red and blue, and we are going to choose a subset of \(k\) elements to be painted red with the rest painted blue. Then the number of different ways this can be done is just the binomial coefficient \(\binom{n}{k}\). Now suppose that we have three different colors, say red, blue, and green. We will choose \(k_1\) to be colored red, \(k_2\) to be colored blue, and the remaining \(k_3 = n - (k_1+k_2)\) are to be colored green. We may compute the number of ways to do this by first choosing \(k_1\) of the \(n\) elements to paint red, then from the remaining \(n-k_1\) elements choosing \(k_2\) to paint blue, and then painting the remaining \(k_3\) elements green. It is easy to see that the number of ways to do this is \[\begin{aligned}\end{aligned}\] Numbers of this form are called multinomial coefficients; they are an obvious generalization of the binomial coefficients. The general notation is: \[\begin{aligned}\end{aligned}\] \(\binom{n}{k_1,k_2,k_3,\dots,k_r}\) multinomial coefficient
For example, \[\begin{aligned}\end{aligned}\]
Note that there is some overkill in this notation, since the value of \(k_r\) is determined by \(n\) and the values for \(k_1\), \(k_2,\dots,k_{r-1}\). For example, with the ordinary binomial coefficients, we just write \(\binom{8}{3}\) and not \(\binom{8}{3,5}\).
Example
How many different rearrangements of the string: \[\begin{aligned}\end{aligned}\] are possible if all letters and characters must be used?
Solution
To answer this question, we note that there are a total of \(45\) characters distributed as follows: 3A's, 1C, 1D, 7E's, 1G, 1H, 4I's, 1K, 5L's, 2M's, 2N's, 1O, 4R's, 2S's, 6T's, 1U, 1W, and 2!'s. So the number of rearrangements is \[\begin{aligned}\end{aligned}\]
Just as with binomial coefficients and the Binomial Theorem, the multinomial coefficients arise in the expansion of powers of a multinomial:
Condensed — the full section is in Keller & Trotter, Applied Combinatorics.
Practice (1)
Try each one on paper first. Reveal the answer to check; verified ones can be opened in the solver for every step.
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Look again at the trinomial in . What would be the coefficient on \(x^{30}y^{80}z^{10}\) when this is expanded? Explain your reasoning.
Symbols used here
Add a_k for k = 1 up to n.
Number of k-element subsets of n things: n!/(k!(n−k)!).
n × (n−1) × … × 1; the number of orderings of n things. 0! = 1.
x belongs to A; every element of A is in B.
i² = −1.
The two sides are different.
Multiply a_k for k = 1 up to n.
The set with no elements; the number of elements of A.
Questions people ask
Permutation or combination?
Ask whether order matters. A lock code is a permutation (order matters); a hand of cards is a combination (it does not).
What is a graph in this sense?
Dots (vertices) joined by lines (edges) — not a plot. Road maps, social networks and molecules are graphs; questions like "is there a route" and "how few colours" are graph theory.
Zkuste si vlastní.
Parts of this page are adapted from Keller & Trotter, Applied Combinatorics (CC BY-SA 4.0). Condensed and re-explained here; errors are ours.
Více v Combinatorics & Graph Theory
The counting principlesPigeonhole principle and inclusion–exclusionBinomial coefficients and Pascal's triangleRecurrences and generating functionsGraphs: vertices, edges, degreesPaths, cycles, trees, Euler and HamiltonColouring and planar graphs