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Basic Notation and Terminology
A partially ordered set or poset \bfP is a pair (X,P) where X is a set and P is a reflexive, antisymmetric, and transitive binary relation on X.
Basic Notation and Terminology
A partially ordered set or poset \(\bfP\) is a pair \((X,P)\) where \(X\) is a set and \(P\) is a reflexive, antisymmetric, and transitive binary relation on \(X\). (Refer to for a refresher of what these properties are if you need to.) We call \(X\) the ground set while \(P\) is a partial order on \(X\). Elements of the ground set \(X\) are also called points, and the poset \(\bfP\) is finite if its ground set \(X\) is a finite set.
Example
Let \(X=\{a,b,c,d,e,f\}\). Consider the following binary relations on \(X\). \[\begin{aligned}R_1=\{\amp (a,a),(b,b),(c,c),(d,d),(e,e),(f,f),(a,b),(a,c),(e,f)\} \\ R_2=\{\amp (a,a),(b,b),(c,c),(d,d),(e,e),(f,f),(d,b),(d,e),(b,a),(e,a), \\ \amp(d,a),(c,f)\} \\ R_3=\{\amp(a,a),(b,b),(c,c),(d,d),(e,e),(f,f),(a,c),(a,e),(a,f),(b,c), \\ \amp(b,d),(b,e),(b,f),(d,e),(d,f),(e,f)\} \\ R_4=\{\amp(a,a),(b,b),(c,c),(d,d),(e,e),(f,f),(d,b),(b,a),(e,a),(c,f)\} \\ R_5=\{\amp(a,a),(c,c),(d,d),(e,e),(a,e),(c,a),(c,e),(d,e)\} \\ R_6=\{\amp(a,a),(b,b),(c,c),(d,d),(e,e),(f,f),(d,f),(b,e),(c,a),(e,b)\}\end{aligned}\] Which of the binary relations are partial orders on \(X\)? For those that are not partial orders on \(X\), which property or properties are violated?
Solution
A bit of checking confirms that \(R_1\), \(R_2\) and \(R_3\) are partial orders on \(X\), so \(\bfP_1=(X,R_1)\), \(\bfP_2=(X,R_2)\) and \(\bfP_3=(X,R_3)\) are posets. Several of the other examples we will discuss in this chapter will use the poset \(\bfP_3=(X,R_3)\).
On the other hand, \(R_4\), \(R_5\) and \(R_6\) are not partial orders on \(X\). Note that \(R_4\) is not transitive, as it contains \((d,b)\) and \((b,a)\) but not \((d,a)\). The relation \(R_5\) is not reflexive, since it doesn't contain \((b,b)\). (Also, it also doesn't contain \((f,f)\), but one shortcoming is enough.) Note that \(R_5\) is a partial order on \(\{a,c,d,e\}\). The relation \(R_6\) is not antisymmetric, as it contains both \((b,e)\) and \((e,b)\).
For posets of moderate size, diagrams are frequently used to define a posetrather than the explicit binary relation notation illustrated in . In , we illustrate a poset \(\PXP\) with ground set \(X=[17]=\{1,2,\dots,17\}\). It would take several lines of text to write out the binary relation \(P\), and somehow the diagram serves to give us a more tactile sense of the properties of the poset.
When \(\PXP\) is a poset and \(Y\subseteq X\), the binary relation \(Q=P\cap(Y\times Y)\) is a partial order on \(Y\), and we call the poset \((Y,Q)\) a subposet of \(\bfP\). In , we show a subposet of the poset first presented in .
Condensed — the full section is in Keller & Trotter, Applied Combinatorics.
Practice (3)
Try each one on paper first. Reveal the answer to check; verified ones can be opened in the solver for every step.
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Consider the poset in . List all of the elements that are comparable to point \(6\).
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Consider the middle poset in . Give an example of a chain with three elements that contains the point \(21\).
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Consider the rightmost poset in . Give an example of an antichain with three elements that contains the point \((6,4,5)\).
Symbols used here
x belongs to A; every element of A is in B.
In either; in both; in A but not B.
n × (n−1) × … × 1; the number of orderings of n things. 0! = 1.
Number of k-element subsets of n things: n!/(k!(n−k)!).
Add a_k for k = 1 up to n.
Multiply a_k for k = 1 up to n.
The set with no elements; the number of elements of A.
Questions people ask
Permutation or combination?
Ask whether order matters. A lock code is a permutation (order matters); a hand of cards is a combination (it does not).
What is a graph in this sense?
Dots (vertices) joined by lines (edges) — not a plot. Road maps, social networks and molecules are graphs; questions like "is there a route" and "how few colours" are graph theory.
Try your own
Parts of this page are adapted from Keller & Trotter, Applied Combinatorics (CC BY-SA 4.0). Condensed and re-explained here; errors are ours.
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