maths.free › Calculus › Definite integrals

Definite integrals

Area under a curve and the fundamental theorem of calculus.

A definite integral is the signed area between the curve and the axis on an interval. Find an antiderivative F, then compute F(b) − F(a): the fundamental theorem of calculus. The shaded region in the graph is the area being computed.

Apstrādāts piemērs · integrate x^2 dx from 0 to 1

Integrate x^2 from 0 to 1

\int_{0}^{1} x^{2}\, dx

Solis pēc kārtas

  1. \int_{0}^{1} x^{2}\, dx

    First find an antiderivative F, then evaluate F(b) − F(a).

  2. \int x^{2}\, dx = \frac{x^{3}}{3}

    Power rule: ∫xⁿ dx = xⁿ⁺¹/(n+1) (n ≠ −1).

  3. F(1) - F(0) = \left(\frac{1}{3}\right) - \left(0\right)

    Fundamental theorem of calculus: plug in the limits.

  4. = \frac{1}{3}

    Simplify.

Atbildēt uz šo jautājumu
\frac{1}{3}

Tagad tu Izvēlieties problēmu, vai ierakstiet vai zīmējiet savu. Katrs solis, attēls, atbilde slēpta, līdz jūs lūgt.

Saglabāt savu darbu

Bezmaksas konts pievieno piezīmes par katru nodarbību, ierakstu par to, ko esat pabeidzis, jūsu atrisinātās problēmas vienā vietā, un pasniedzēju, kuru varat jautāt par šo lapu. Pati matemātika ir pieejama ikvienam, kas ir vai nav parakstījies.

Pierakstīties Pieteikšanās

Šeit izmantotie simboli

Piesitiet visiem simboliem, kas apzīmē pilnu definīciju, attēlu un ko katrs burts tajā nozīmē.

Kā lietot: Definite integrals

  1. First find an antiderivative F, then evaluate F(b) − F(a).
  2. Power rule: ∫xⁿ dx = xⁿ⁺¹/(n+1) (n ≠ −1).
  3. Fundamental theorem of calculus: plug in the limits.
  4. Simplify.

Jautājumi, ko cilvēki vaicā

What is a derivative in one sentence?

The slope of the graph at a point, the rate at which the output is changing there. Speed is the derivative of position.

What is an integral in one sentence?

The accumulated total of a rate: the area under the curve. Distance travelled is the integral of speed.

Why are derivatives and integrals opposites?

That is the fundamental theorem of calculus: accumulating a rate and then measuring how fast the accumulation grows gets you back the rate. Integration undoes differentiation up to a constant.

When do I use substitution and when integration by parts?

Substitution when part of the integrand is the derivative of another part (u and du both present). Parts when the integrand is a product of two unrelated kinds of function, a polynomial times an exponential, log or trig function.

Vairāk Calculus