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Multiply Whole Numbers
Use multiplication notation
Use Multiplication Notation
Suppose you were asked to count all these pennies shown in .
Would you count the pennies individually? Or would you count the number of pennies in each row and add that number \(3\) times.
\[8+8+8\]Multiplication is a way to represent repeated addition. So instead of adding \(8\) three times, we could write a multiplication expression.
\[3\ \times \ 8\]We call each number being multiplied a factor and the result the product. We read \(3\ \times \ 8\) as three times eight, and the result as the product of three and eight.
There are several symbols that represent multiplication. These include the symbol \(\times\) as well as the dot, \(\cdot\), and parentheses \((\ \text{).}\)
Example
Try it.
Translate from math notation to words:
- ⓐ \(7\ \times \ 6\)
- ⓑ \(12\cdot 14\)
- ⓒ \(6(13)\)
Solution
- ⓐ We read this as seven times six and the result is the product of seven and six.
- ⓑ We read this as twelve times fourteen and the result is the product of twelve and fourteen.
- ⓒ We read this as six times thirteen and the result is the product of six and thirteen.
Model Multiplication of Whole Numbers
There are many ways to model multiplication. Unlike in the previous sections where we used \(\text{base-10}\) blocks, here we will use counters to help us understand the meaning of multiplication. A counter is any object that can be used for counting. We will use round blue counters.
Example
Try it.
Model: \(3\ \times \ 8.\)
Solution
To model the product \(3\ \times \ 8,\) we’ll start with a row of \(8\) counters.
The other factor is \(3,\) so we’ll make \(3\) rows of \(8\) counters.
Now we can count the result. There are \(24\) counters in all.
\(3\ \times \ 8=24\)
If you look at the counters sideways, you’ll see that we could have also made \(8\) rows of \(3\) counters. The product would have been the same. We’ll get back to this idea later.
Multiply Whole Numbers
In order to multiply without using models, you need to know all the one digit multiplication facts. Make sure you know them fluently before proceeding in this section.
shows the multiplication facts. Each box shows the product of the number down the left column and the number across the top row. If you are unsure about a product, model it. It is important that you memorize any number facts you do not already know so you will be ready to multiply larger numbers.
| × | 0 | 1 | 2 | 3 | 4 | 5 | 6 | 7 | 8 | 9 |
| 0 | 0 | 0 | 0 | 0 | 0 | 0 | 0 | 0 | 0 | 0 |
| 1 | 0 | 1 | 2 | 3 | 4 | 5 | 6 | 7 | 8 | 9 |
| 2 | 0 | 2 | 4 | 6 | 8 | 10 | 12 | 14 | 16 | 18 |
| 3 | 0 | 3 | 6 | 9 | 12 | 15 | 18 | 21 | 24 | 27 |
| 4 | 0 | 4 | 8 | 12 | 16 | 20 | 24 | 28 | 32 | 36 |
| 5 | 0 | 5 | 10 | 15 | 20 | 25 | 30 | 35 | 40 | 45 |
| 6 | 0 | 6 | 12 | 18 | 24 | 30 | 36 | 42 | 48 | 54 |
| 7 | 0 | 7 | 14 | 21 | 28 | 35 | 42 | 49 | 56 | 63 |
| 8 | 0 | 8 | 16 | 24 | 32 | 40 | 48 | 56 | 64 | 72 |
| 9 | 0 | 9 | 18 | 27 | 36 | 45 | 54 | 63 | 72 | 81 |
What happens when you multiply a number by zero? You can see that the product of any number and zero is zero. This is called the Multiplication Property of Zero.
Example
Try it.
Multiply:
- ⓐ \(0\cdot 11\)
- ⓑ \((42)0\)
Solution
| ⓐ | \(0\cdot 11\) |
| The product of any number and zero is zero. | \(0\) |
| ⓑ | \((42)0\) |
| Multiplying by zero results in zero. | \(0\) |
What happens when you multiply a number by one? Multiplying a number by one does not change its value. We call this fact the Identity Property of Multiplication, and \(1\) is called the multiplicative identity.
Example
Try it.
Multiply:
- ⓐ \((11)1\)
- ⓑ \(1\cdot 42\)
Solution
| ⓐ | \((11)1\) |
| The product of any number and one is the number. | \(11\) |
| ⓑ | \(1\cdot 42\) |
| Multiplying by one does not change the value. | \(42\) |
Earlier in this chapter, we learned that the Commutative Property of Addition states that changing the order of addition does not change the sum. We saw that \(8+9=17\) is the same as \(9+8=17.\)
Is this also true for multiplication? Let’s look at a few pairs of factors.
\[4\cdot 7=28\ 7\cdot 4=28\]\[9\cdot 7=63\ 7\cdot 9=63\]\[8\cdot 9=72\ 9\cdot 8=72\]When the order of the factors is reversed, the product does not change. This is called the Commutative Property of Multiplication.
Example
Try it.
Multiply:
- ⓐ \(8\cdot 7\)
- ⓑ \(7\cdot 8\)
Solution
| ⓐ | \(8\cdot 7\) |
| Multiply. | \(56\) |
| ⓑ | \(7\cdot 8\) |
| Multiply. | \(56\) |
Changing the order of the factors does not change the product.
Condensed — the full section is in OpenStax Prealgebra 2e.
Translate Word Phrases to Math Notation
Earlier in this section, we translated math notation into words. Now we’ll reverse the process and translate word phrases into math notation. Some of the words that indicate multiplication are given in .
| Operation | Word Phrase | Example | Expression |
| Multiplication | times product twice | \(3\) times \(8\) the product of \(3\) and \(8\) twice \(4\) | \(3\ \times \ 8,3\cdot 8,(3)(8),\) \((3)8,\ \text{or}\ 3(8)\) \(2\cdot 4\) |
Example
Try it.
Translate and simplify: the product of \(12\) and \(27.\)
Solution
The word product tells us to multiply. The words of \(12\) and \(27\) tell us the two factors.
| the product of 12 and 27 | |
| Translate. | \(12⋅27\) |
| Multiply. | \(324\) |
Example
Try it.
Translate and simplify: twice two hundred eleven.
Solution
The word twice tells us to multiply by \(2.\)
| twice two hundred eleven | |
| Translate. | 2(211) |
| Multiply. | 422 |
Multiply Whole Numbers in Applications
We will use the same strategy we used previously to solve applications of multiplication. First, we need to determine what we are looking for. Then we write a phrase that gives the information to find it. We then translate the phrase into math notation and simplify to get the answer. Finally, we write a sentence to answer the question.
Example
Try it.
Humberto bought \(4\) sheets of stamps. Each sheet had \(20\) stamps. How many stamps did Humberto buy?
Solution
We are asked to find the total number of stamps.
| Write a phrase for the total. | the product of 4 and 20 |
| Translate to math notation. | \(4⋅20\) |
| Multiply. | |
| Write a sentence to answer the question. | Humberto bought 80 stamps. |
Example
Try it.
When Rena cooks rice, she uses twice as much water as rice. How much water does she need to cook \(4\) cups of rice?
Solution
We are asked to find how much water Rena needs.
| Write as a phrase. | twice as much as 4 cups |
| Translate to math notation. | \(2⋅4\) |
| Multiply to simplify. | 8 |
| Write a sentence to answer the question. | Rena needs 8 cups of water for 4 cups of rice. |
Example
Try it.
Van is planning to build a patio. He will have \(8\) rows of tiles, with \(14\) tiles in each row. How many tiles does he need for the patio?
Solution
We are asked to find the total number of tiles.
| Write a phrase. | the product of 8 and 14 |
| Translate to math notation. | \(8⋅14\) |
| Multiply to simplify. | \(\begin{array}{l}\ \\ \overset{3}{1}4 \\ \underset{\text{___}}{\times 8} \\ 112\end{array}\) |
| Write a sentence to answer the question. | Van needs 112 tiles for his patio. |
Condensed — the full section is in OpenStax Prealgebra 2e.
Key Concepts
| Operation | Notation | Expression | Read as | Result |
| \(\text{Multiplication}\) | \(\times\) \(\cdot\) \((\ )\) | \(3\ \times \ 8\) \(3\cdot 8\) \(3(8)\) | \(\text{three times eight}\) | \(\text{the product of 3 and 8}\) |
- Multiplication Property of Zero
- The product of any number and 0 is 0.
\(a⋅0=0\)
\(0⋅a=0\)
- The product of any number and 0 is 0.
- Identity Property of Multiplication
- The product of any number and 1 is the number.
\(1⋅a=a\)
\(a⋅1=a\)
- The product of any number and 1 is the number.
- Commutative Property of Multiplication
- Changing the order of the factors does not change their product.
\(a⋅b=b⋅a\)
- Changing the order of the factors does not change their product.
- Multiply two whole numbers to find the product.
- Write the numbers so each place value lines up vertically.
- Multiply the digits in each place value.
- Work from right to left, starting with the ones place in the bottom number.
- Multiply the bottom number by the ones digit in the top number, then by the tens digit, and so on.
- If a product in a place value is more than 9, carry to the next place value.
- Write the partial products, lining up the digits in the place values with the numbers above. Repeat for the tens place in the bottom number, the hundreds place, and so on.
- Insert a zero as a placeholder with each additional partial product.
- Add the partial products.
Multiply Whole Numbers
Use Multiplication Notation
In the following exercises, translate from math notation to words.
Try it.
\(4\ \times \ 7\)
Solution
four times seven; the product of four and seven
Try it.
\(8\ \times \ 6\)
Try it.
\(5\cdot 12\)
Solution
five times twelve; the product of five and twelve
Try it.
\(3\cdot 9\)
Try it.
\((10)(25)\)
Solution
ten times twenty-five; the product of ten and twenty-five
Try it.
\((20)(15)\)
Try it.
\(42(33)\)
Solution
forty-two times thirty-three; the product of forty-two and thirty-three
Try it.
\(39(64)\)
Model Multiplication of Whole Numbers
In the following exercises, model the multiplication.
Try it.
\(3\ \times \ 6\)
Solution
Try it.
\(4\ \times \ 5\)
Try it.
\(5\ \times \ 9\)
Solution
Try it.
\(3\ \times \ 9\)
Multiply Whole Numbers
In the following exercises, fill in the missing values in each chart.
Try it.
Solution
Try it.
Try it.
Solution
Try it.
Try it.
Solution
Try it.
Try it.
Solution
Try it.
In the following exercises, multiply.
Try it.
\(0\cdot 15\)
Solution
0
Try it.
\(0\cdot 41\)
Try it.
\((99)0\)
Solution
0
Try it.
\((77)0\)
Try it.
\(1\cdot 43\)
Solution
43
Try it.
\(1\cdot 34\)
Try it.
\((28)1\)
Solution
28
Try it.
\((65)1\)
Try it.
\(1(240,055)\)
Solution
240,055
Try it.
\(1(189,206)\)
Try it.
- ⓐ \(7\cdot 6\)
- ⓑ \(6\cdot 7\)
Solution
- ⓐ 42
- ⓑ 42
Try it.
- ⓐ \(8\ \times \ 9\)
- ⓑ \(9\ \times \ 8\)
Try it.
\((79)(5)\)
Solution
395
Try it.
\((58)(4)\)
Try it.
\(275\cdot 6\)
Solution
1,650
Try it.
\(638\cdot 5\)
Try it.
\(3,421\ \times \ 7\)
Solution
23,947
Try it.
\(9,143\ \times \ 3\)
Try it.
\(52(38)\)
Solution
1,976
Try it.
\(37(45)\)
Try it.
\(96\cdot 73\)
Solution
7,008
Try it.
\(89\cdot 56\)
Try it.
\(27\ \times \ 85\)
Solution
2,295
Try it.
\(53\ \times \ 98\)
Try it.
\(23\cdot 10\)
Solution
230
Try it.
\(19\cdot 10\)
Try it.
\((100)(36)\)
Solution
3,600
Try it.
\((100)(25)\)
Try it.
\(1,000(88)\)
Solution
88,000
Try it.
\(1,000(46)\)
Try it.
\(50\ \times \ 1,000,000\)
Solution
50,000,000
Try it.
\(30\ \times \ 1,000,000\)
Try it.
\(247\ \times \ 139\)
Solution
34,333
Try it.
\(156\ \times \ 328\)
Try it.
\(586(721)\)
Solution
422,506
Try it.
\(472(855)\)
Try it.
\(915\cdot 879\)
Solution
804,285
Try it.
\(968\cdot 926\)
Try it.
\((104)(256)\)
Solution
26,624
Try it.
\((103)(497)\)
Try it.
\(348(705)\)
Solution
245,340
Try it.
\(485(602)\)
Try it.
\(2,719\ \times \ 543\)
Solution
1,476,417
Try it.
\(3,581\ \times \ 724\)
Translate Word Phrases to Math Notation
In the following exercises, translate and simplify.
Try it.
the product of \(18\) and \(33\)
Solution
18 · 33; 594
Try it.
the product of \(15\) and \(22\)
Try it.
fifty-one times sixty-seven
Solution
51(67); 3,417
Try it.
forty-eight times seventy-one
Try it.
twice \(249\)
Solution
2(249); 498
Try it.
twice \(589\)
Try it.
ten times three hundred seventy-five
Solution
10(375); 3,750
Try it.
ten times two hundred fifty-five
Mixed Practice
In the following exercises, simplify.
Try it.
\(38\ \times \ 37\)
Solution
1,406
Try it.
\(86\ \times \ 29\)
Try it.
\(415-267\)
Solution
148
Try it.
\(341-285\)
Try it.
\(6,251+4,749\)
Solution
11,000
Try it.
\(3,816+8,184\)
Try it.
\((56)(204)\)
Solution
11,424
Try it.
\((77)(801)\)
Try it.
\(947\cdot 0\)
Solution
0
Try it.
\(947+0\)
Try it.
\(15,382+1\)
Solution
15,383
Try it.
\(15,382\cdot 1\)
In the following exercises, translate and simplify.
Try it.
the difference of 50 and 18
Solution
50 − 18; 32
Try it.
the difference of 90 and 66
Try it.
twice 35
Solution
2(35); 70
Try it.
twice 140
Try it.
20 more than 980
Solution
20 + 980; 1,000
Try it.
65 more than 325
Try it.
the product of 12 and 875
Solution
12(875); 10,500
Try it.
the product of 15 and 905
Try it.
subtract 74 from 89
Solution
89 − 74; 15
Try it.
subtract 45 from 99
Try it.
the sum of 3,075 and 95
Solution
3,075 + 95; 3,170
Try it.
the sum of 6,308 and 724
Try it.
366 less than 814
Solution
814 − 366; 448
Try it.
388 less than 925
Multiply Whole Numbers in Applications
In the following exercises, solve.
Try it.
Party supplies Tim brought 9 six-packs of soda to a club party. How many cans of soda did Tim bring?
Solution
Tim brought 54 cans of soda to the party.
Try it.
Sewing Kanisha is making a quilt. She bought 6 cards of buttons. Each card had four buttons on it. How many buttons did Kanisha buy?
Try it.
Field trip Seven school busses let off their students in front of a museum in Washington, DC. Each school bus had 44 students. How many students were there?
Solution
There were 308 students.
Try it.
Gardening Kathryn bought 8 flats of impatiens for her flower bed. Each flat has 24 flowers. How many flowers did Kathryn buy?
Try it.
Charity Rey donated 15 twelve-packs of t-shirts to a homeless shelter. How many t-shirts did he donate?
Solution
Rey donated 180 t-shirts.
Try it.
School There are 28 classrooms at Anna C. Scott elementary school. Each classroom has 26 student desks. What is the total number of student desks?
Try it.
Recipe Stephanie is making punch for a party. The recipe calls for twice as much fruit juice as club soda. If she uses 10 cups of club soda, how much fruit juice should she use?
Solution
Stephanie should use 20 cups of fruit juice.
Try it.
Gardening Hiroko is putting in a vegetable garden. He wants to have twice as many lettuce plants as tomato plants. If he buys 12 tomato plants, how many lettuce plants should he get?
Try it.
Government The United States Senate has twice as many senators as there are states in the United States. There are 50 states. How many senators are there in the United States Senate?
Solution
There are 100 senators in the U.S. senate.
Try it.
Recipe Andrea is making potato salad for a buffet luncheon. The recipe says the number of servings of potato salad will be twice the number of pounds of potatoes. If she buys 30 pounds of potatoes, how many servings of potato salad will there be?
Try it.
Painting Jane is painting one wall of her living room. The wall is rectangular, 13 feet wide by 9 feet high. What is the area of the wall?
Solution
The area of the wall is 117 square feet.
Try it.
Home décor Shawnte bought a rug for the hall of her apartment. The rug is 3 feet wide by 18 feet long. What is the area of the rug?
Try it.
Room size The meeting room in a senior center is rectangular, with length 42 feet and width 34 feet. What is the area of the meeting room?
Solution
The area of the room is 1,428 square feet.
Try it.
Gardening June has a vegetable garden in her yard. The garden is rectangular, with length 23 feet and width 28 feet. What is the area of the garden?
Try it.
NCAA basketball According to NCAA regulations, the dimensions of a rectangular basketball court must be 94 feet by 50 feet. What is the area of the basketball court?
Solution
The area of the court is 4,700 square feet.
Try it.
NCAA football According to NCAA regulations, the dimensions of a rectangular football field must be 360 feet by 160 feet. What is the area of the football field?
Condensed — the full section is in OpenStax Prealgebra 2e.
Practice (40)
Try each one on paper first. Reveal the answer to check; verified ones can be opened in the solver for every step.
-
Add: \(1,683+479.\)
If you missed this problem, review .ເປີດເຜີຍຄຳຕອບ
\(2,162\)
-
Subtract: \(605-321.\)
If you missed this problem, review .ເປີດເຜີຍຄຳຕອບ
\(284\)
-
Translate from math notation to words:
- ⓐ \(7\ \times \ 6\)
- ⓑ \(12\cdot 14\)
- ⓒ \(6(13)\)
ເປີດເຜີຍຄຳຕອບ
- ⓐ We read this as seven times six and the result is the product of seven and six.
- ⓑ We read this as twelve times fourteen and the result is the product of twelve and fourteen.
- ⓒ We read this as six times thirteen and the result is the product of six and thirteen.
-
Translate from math notation to words:
- ⓐ \(8\ \times \ 7\)
- ⓑ \(18\cdot 11\)
ເປີດເຜີຍຄຳຕອບ
- ⓐ eight times seven ; the product of eight and seven
- ⓑ eighteen times eleven ; the product of eighteen and eleven
-
Translate from math notation to words:
- ⓐ \((13)(7)\)
- ⓑ \(5(16)\)
ເປີດເຜີຍຄຳຕອບ
- ⓐ thirteen times seven ; the product of thirteen and seven
- ⓑ five times sixteen; the product of five and sixteen
-
Model: \(3\ \times \ 8.\)
ເປີດເຜີຍຄຳຕອບ
To model the product \(3\ \times \ 8,\) we’ll start with a row of \(8\) counters.
The other factor is \(3,\) so we’ll make \(3\) rows of \(8\) counters.
Now we can count the result. There are \(24\) counters in all.
\(3\ \times \ 8=24\)
If you look at the counters sideways, you’ll see that we could have also made \(8\) rows of \(3\) counters. The product would have been the same. We’ll get back to this idea later.
-
Model each multiplication: \(4\ \times \ 6.\)
ເປີດເຜີຍຄຳຕອບ
-
Model each multiplication: \(5\ \times \ 7.\)
ເປີດເຜີຍຄຳຕອບ
-
Multiply:
- ⓐ \(0\cdot 11\)
- ⓑ \((42)0\)
ເປີດເຜີຍຄຳຕອບ
ⓐ \(0\cdot 11\) The product of any number and zero is zero. \(0\) ⓑ \((42)0\) Multiplying by zero results in zero. \(0\) -
Find each product:
- ⓐ \(0\cdot 19\)
- ⓑ \((39)0\)
ເປີດເຜີຍຄຳຕອບ
- ⓐ \(0\)
- ⓑ \(0\)
-
Find each product:
- ⓐ \(0\cdot 24\)
- ⓑ \((57)0\)
ເປີດເຜີຍຄຳຕອບ
- ⓐ \(0\)
- ⓑ \(0\)
-
Multiply:
- ⓐ \((11)1\)
- ⓑ \(1\cdot 42\)
ເປີດເຜີຍຄຳຕອບ
ⓐ \((11)1\) The product of any number and one is the number. \(11\) ⓑ \(1\cdot 42\) Multiplying by one does not change the value. \(42\) -
Find each product:
- ⓐ \((19)1\)
- ⓑ \(1\cdot 39\)
ເປີດເຜີຍຄຳຕອບ
- ⓐ \(19\)
- ⓑ \(39\)
-
Find each product:
- ⓐ \((24)(1)\)
- ⓑ \(1\ \times \ 57\)
ເປີດເຜີຍຄຳຕອບ
- ⓐ \(24\)
- ⓑ \(57\)
-
Multiply:
- ⓐ \(8\cdot 7\)
- ⓑ \(7\cdot 8\)
ເປີດເຜີຍຄຳຕອບ
ⓐ \(8\cdot 7\) Multiply. \(56\) ⓑ \(7\cdot 8\) Multiply. \(56\) Changing the order of the factors does not change the product.
-
Multiply:
- ⓐ \(9\cdot 6\)
- ⓑ \(6\cdot 9\)
ເປີດເຜີຍຄຳຕອບ
54 and 54; both are the same.
-
Multiply:
- ⓐ \(8\cdot 6\)
- ⓑ \(6\cdot 8\)
ເປີດເຜີຍຄຳຕອບ
48 and 48; both are the same.
-
Multiply: \(15\cdot 4.\)
ເປີດເຜີຍຄຳຕອບ
Write the numbers so the digits \(5\) and \(4\) line up vertically. \(\begin{array}{l}15\ \\ \underset{\text{_____}}{\times \ 4}\end{array}\) Multiply \(4\) by the digit in the ones place of \(15.\) \(4⋅5=20.\) Write \(0\) in the ones place of the product and carry the \(2\) tens. \(\begin{array}{l}\overset{2}{1}5\ \\ \underset{\text{_____}}{\times \ 4} \\ 0\ \end{array}\) Multiply \(4\) by the digit in the tens place of \(15.\) \(4⋅1=4\).
Add the \(2\) tens we carried. \(4+2=6\).Write the \(6\) in the tens place of the product. \(\begin{array}{l}\overset{2}{1}5\ \\ \underset{\text{_____}}{\times \ 4} \\ 60\ \end{array}\) -
Multiply: \(64\cdot 8.\)
ເປີດເຜີຍຄຳຕອບ
\(512\)
-
Multiply: \(57\cdot 6.\)
ເປີດເຜີຍຄຳຕອບ
\(342\)
-
Multiply: \(286\cdot 5.\)
ເປີດເຜີຍຄຳຕອບ
Write the numbers so the digits \(5\) and \(6\) line up vertically. \(\begin{array}{l}286\ \\ \underset{\text{_____}}{\times \ 5}\end{array}\) Multiply \(5\) by the digit in the ones place of \(286.\) \(5⋅6=30.\) Write the \(0\) in the ones place of the product and carry the \(3\) to the tens place.Multiply \(5\) by the digit in the tens place of \(286.\) \(5⋅8=40\). \(\begin{array}{l} \\ 2\overset{3}{8}6\ \\ \underset{\text{_____}}{\times \ 5} \\ 0\ \end{array}\) Add the \(3\) tens we carried to get \(40+3=43\).
Write the \(3\) in the tens place of the product and carry the 4 to the hundreds place.\(\begin{array}{l}\overset{4}{2}\overset{3}{8}6\ \\ \underset{\text{_____}}{\times \ 5} \\ 30\ \end{array}\) Multiply \(5\) by the digit in the hundreds place of \(286.\) \(5⋅2=10.\)
Add the \(4\) hundreds we carried to get \(10+4=14.\)
Write the \(4\) in the hundreds place of the product and the \(1\) to the thousands place.\(\begin{array}{l}\overset{4}{2}\overset{3}{8}6\ \\ \underset{\text{_____}}{\times \ 5} \\ 1,430\ \end{array}\) -
Multiply: \(347\cdot 5.\)
ເປີດເຜີຍຄຳຕອບ
\(1,735\)
-
Multiply: \(462\cdot 7.\)
ເປີດເຜີຍຄຳຕອບ
\(3,234\)
-
Multiply: \(62(87).\)
ເປີດເຜີຍຄຳຕອບ
Write the numbers so each place lines up vertically. Start by multiplying 7 by 62. Multiply 7 by the digit in the ones place of 62. \(7⋅2=14.\) Write the 4 in the ones place of the product and carry the 1 to the tens place. Multiply 7 by the digit in the tens place of 62. \(7⋅6=42.\) Add the 1 ten we carried. \(42+1=43\). Write the 3 in the tens place of the product and the 4 in the hundreds place. The first partial product is 434. Now, write a 0 under the 4 in the ones place of the next partial product as a placeholder since we now multiply the digit in the tens place of 87 by 62. Multiply 8 by the digit in the ones place of 62. \(8⋅2=16.\) Write the 6 in the next place of the product, which is the tens place. Carry the 1 to the tens place. Multiply 8 by 6, the digit in the tens place of 62, then add the 1 ten we carried to get 49. Write the 9 in the hundreds place of the product and the 4 in the thousands place. The second partial product is 4960. Add the partial products. The product is \(5,394.\)
-
Multiply: \(43(78).\)
ເປີດເຜີຍຄຳຕອບ
3,354
-
Multiply: \(64(59).\)
ເປີດເຜີຍຄຳຕອບ
3,776
-
Multiply:
- ⓐ \(47\cdot 10\)
- ⓑ \(47\cdot 100.\)
ເປີດເຜີຍຄຳຕອບ
ⓐ \(47\cdot 10\). \(\begin{array}{l}47\ \\ \underset{\text{___}}{\times 10} \\ 00 \\ \underset{\text{___}}{470} \\ 470\end{array}\) ⓑ \(47\cdot 100\) \(\begin{array}{l}47\ \\ \underset{\text{_____}}{\times 100}\ \\ 00\ \\ \underset{\text{_____}}{\begin{array}{l}000 \\ 4700\end{array}} \\ 4,700\ \end{array}\) When we multiplied \(47\) times \(10,\) the product was \(470.\) Notice that \(10\) has one zero, and we put one zero after \(47\) to get the product. When we multiplied \(47\) times \(100,\) the product was \(4,700.\) Notice that \(100\) has two zeros and we put two zeros after \(47\) to get the product.
Do you see the pattern? If we multiplied \(47\) times \(10,000,\) which has four zeros, we would put four zeros after \(47\) to get the product \(470,000.\)
-
Multiply:
- ⓐ \(54\cdot 10\)
- ⓑ \(54\cdot 100.\)
ເປີດເຜີຍຄຳຕອບ
- ⓐ 540
- ⓑ 5,400
-
Multiply:
- ⓐ \(75\cdot 10\)
- ⓑ \(75\cdot 100.\)
ເປີດເຜີຍຄຳຕອບ
- ⓐ 750
- ⓑ 7,500
-
Multiply: \((354)(438).\)
ເປີດເຜີຍຄຳຕອບ
There are three digits in the factors so there will be \(3\) partial products. We do not have to write the \(0\) as a placeholder as long as we write each partial product in the correct place.
-
Multiply: \((265)(483).\)
ເປີດເຜີຍຄຳຕອບ
127,995
-
Multiply: \((823)(794).\)
ເປີດເຜີຍຄຳຕອບ
653,462
-
Multiply: \((896)201.\)
ເປີດເຜີຍຄຳຕອບ
There should be \(3\) partial products. The second partial product will be the result of multiplying \(896\) by \(0.\)
Notice that the second partial product of all zeros doesn’t really affect the result. We can place a zero as a placeholder in the tens place and then proceed directly to multiplying by the \(2\) in the hundreds place, as shown.
Multiply by \(10,\) but insert only one zero as a placeholder in the tens place. Multiply by \(200,\) putting the \(2\) from the \(12.\) \(2\cdot 6=12\) in the hundreds place.
\[\begin{array}{l} \\ \\ 896\ \\ \underset{\text{_____}}{\times 201}\ \\ 896\ \\ \underset{\text{__________}}{17920}\ \\ 180,096\ \end{array}\] -
Multiply: \((718)509.\)
ເປີດເຜີຍຄຳຕອບ
365,462
-
Multiply: \((627)804.\)
ເປີດເຜີຍຄຳຕອບ
504,108
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Translate and simplify: the product of \(12\) and \(27.\)
ເປີດເຜີຍຄຳຕອບ
The word product tells us to multiply. The words of \(12\) and \(27\) tell us the two factors.
the product of 12 and 27 Translate. \(12⋅27\) Multiply. \(324\) -
Translate and simplify: the product of \(13\) and \(28.\)
ເປີດເຜີຍຄຳຕອບ
13 · 28; 364
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Translate and simplify: the product of \(47\) and \(14.\)
ເປີດເຜີຍຄຳຕອບ
47 · 14; 658
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Translate and simplify: twice two hundred eleven.
ເປີດເຜີຍຄຳຕອບ
The word twice tells us to multiply by \(2.\)
twice two hundred eleven Translate. 2(211) Multiply. 422 -
Translate and simplify: twice one hundred sixty-seven.
ເປີດເຜີຍຄຳຕອບ
2(167); 334
Symbols used here
Both signs at once: x = 3 ± 2 means 5 and 1.
The two sides are different.
Inequalities that allow equality; < and > exclude it.
Equal to the precision shown, not exactly.
The non-negative number whose square (n-th power) is x.
What is left after dividing a by n.
Per hundred: 15% = 15/100.
a for every b; a divided by b.
How to: Multiply Whole Numbers
- Use multiplication notation
- Model multiplication of whole numbers
- Multiply whole numbers
- Translate word phrases to math notation
- Multiply whole numbers in applications
- Write the numbers so each place value lines up vertically.
- Multiply the digits in each place value.
Questions people ask
Why does the order of operations matter?
Because 2 + 3 × 4 would otherwise be two different numbers. The convention (brackets, exponents, multiplication and division, addition and subtraction) exists so every reader gets the same value from the same expression.
How do I check an arithmetic answer?
Estimate first (round every number and compute roughly), then compare. If the estimate and the exact answer disagree by more than a little, one of them is wrong. The solver shows every operation, so you can find which line went astray.
Why are fractions harder than decimals?
They are not harder, they are more exact: 1/3 is a precise number, 0.333 is an approximation. Fractions need a common denominator to add, which is the one extra step people trip on.
ພະຍາຍາມເອງ
Parts of this page are adapted from OpenStax Prealgebra 2e (CC BY-NC-SA 4.0). Condensed and re-explained here; errors are ours.