maths.freeAlgebra › Expanding

Expanding

Distributing products and collecting like terms.

Expanding multiplies out brackets: every term in one factor times every term in the other, then like terms combined. (x + 1)³ expands to x³ + 3x² + 3x + 1 — the coefficients are a row of Pascal's triangle.

Isibonelo esisebenza: expand (x+1)^3

Expand (x + 1)^3

\left(x + 1\right)^{3}

Isigaba

  1. \left(x + 1\right)^{3}

    Start from the expression.

  2. x^{3} + 3 x^{2} + 3 x + 1

    Distribute (multiply out) the products.

Bonisa impendulo
x^{3} + 3 x^{2} + 3 x + 1

Symbols used here

\leq,\ \geq
less/greater than or equal
Inequalities that allow equality; < and > exclude it.
\pm
plus or minus
Both signs at once: x = 3 ± 2 means 5 and 1.
\neq
not equal
The two sides are different.
\sqrt{x},\ \sqrt[n]{x}
square root, n-th root
The non-negative number whose square (n-th power) is x.
|x|
absolute value / modulus
Distance from zero: |−3| = 3. For a complex number, distance from the origin.
i
imaginary unit
i² = −1.
\log_b x,\ \ln x
logarithm, natural log
The exponent b must be raised to for x; ln uses base e.
\mathbb{N},\ \mathbb{Z},\ \mathbb{Q},\ \mathbb{R},\ \mathbb{C}
number sets
Naturals, integers, rationals, reals, complex numbers.

How to: Expanding

  1. Start from the expression.
  2. Distribute (multiply out) the products.

Questions people ask

What does it mean to solve an equation?

To find every value of the unknown that makes both sides equal. Each step is an operation applied to both sides that keeps the solution set the same, until the unknown stands alone.

Why do I sometimes get two answers?

A quadratic can cross the axis twice, so it can have two solutions. A degree-n polynomial has up to n. The graph shows where each one comes from.

How do I know whether to factor or use the quadratic formula?

Try factoring for a few seconds: look for two numbers that multiply to a·c and add to b. If nothing obvious appears, the discriminant b² − 4ac tells you how many real roots there are, and the formula finds them without guessing.

Zama wena

Okuningi Algebra